traceback

What is the difference between a stack and a frame?

谁都会走 提交于 2019-11-28 15:47:40
Under what situations would I want to use one over the other? What is the difference between: >>> import inspect >>> print(inspect.getouterframes(inspect.currentframe())) [(<frame object at 0x8fc262c>, '<stdin>', 1, '<module>', None, None)] And: >>> import traceback >>> traceback.extract_stack() [('<stdin>', 1, '<module>', None)] Update: Another: >>> import sys >>> print(sys._getframe().f_trace,sys._getframe().f_code) (None, <code object <module> at 0x8682a88, file "<stdin>", line 1>) I do not understand the nuances here: Stack Frame Frame Object Stack Trace update 2, a bit of time since the

Exception traceback is hidden if not re-raised immediately

坚强是说给别人听的谎言 提交于 2019-11-28 04:48:57
I've got a piece of code similar to this: import sys def func1(): func2() def func2(): raise Exception('test error') def main(): err = None try: func1() except: err = sys.exc_info()[1] pass # some extra processing, involving checking err details (if err is not None) # need to re-raise err so caller can do its own handling if err: raise err if __name__ == '__main__': main() When func2 raises an exception I receive the following traceback: Traceback (most recent call last): File "err_test.py", line 25, in <module> main() File "err_test.py", line 22, in main raise err Exception: test error From

How to create a traceback object

放肆的年华 提交于 2019-11-28 02:58:03
问题 I want to create a traceback like the one returned by sys.exc_info()[2]. I don't want a list of lines, I want an actual traceback object: <traceback object at 0x7f6575c37e48> How can I do this? My goal is to have it include the current stack minus one frame, so it looks the the caller is the most recent call. 回答1: There's no documented way to create traceback objects. None of the functions in the traceback module create them. You can of course access the type as types.TracebackType, but if

Print an error message without printing a traceback and close the program when a condition is not met

爷,独闯天下 提交于 2019-11-28 02:40:09
问题 I've seen similar questions to this one but none of them really address the trackback. If I have a class like so class Stop_if_no_then(): def __init__(self, value one, operator, value_two, then, line_or_label, line_number): self._firstvalue = value_one self._secondvalue = value_two self._operator = operator self._gohere = line_or_label self._then = then self._line_number = line_number def execute(self, OtherClass): "code comparing the first two values and making changes etc" What I want my

Error - input expected at most 1 argument, got 3

╄→гoц情女王★ 提交于 2019-11-28 02:08:14
I've set up the following for loop to accept 5 test scores. I want the loop to prompt the user to enter 5 different scores. Now I could do this by writing the input "Please enter your next test score", but I'd rather have each inputted score prompt for its associated number. So, for the first input, I'd like it to display "Please enter your score for test 1", and then for the second score, display "Please enter your score for test 2". When I try to run this loop, I get the following error: Traceback (most recent call last): File "C:/Python32/Assignment 7.2", line 35, in <module> main() File "C

Get Traceback of warnings

纵然是瞬间 提交于 2019-11-27 17:49:08
In numpy we can do np.seterr(invalid='raise') to get a traceback for warnings raising an error instead (see this post ). Is there a general way for tracing warnings? Can I make python to give a traceback, when a warning is raised? mgab You can get what you want by assigning to warnings.showwarning . The warnings module documentation itself recommends that you do that, so it's not that you're being tempted by the dark side of the source . :) You may replace this function with an alternative implementation by assigning to warnings.showwarning . You can define a new function that does what

Exception traceback is hidden if not re-raised immediately

岁酱吖の 提交于 2019-11-27 10:40:03
问题 I've got a piece of code similar to this: import sys def func1(): func2() def func2(): raise Exception('test error') def main(): err = None try: func1() except: err = sys.exc_info()[1] pass # some extra processing, involving checking err details (if err is not None) # need to re-raise err so caller can do its own handling if err: raise err if __name__ == '__main__': main() When func2 raises an exception I receive the following traceback: Traceback (most recent call last): File "err_test.py",

Get full traceback

故事扮演 提交于 2019-11-27 10:08:44
问题 How can i get full traceback in the following case, including the calls of func2 and func functions? import traceback def func(): try: raise Exception('Dummy') except: traceback.print_exc() def func2(): func() func2() When i run this, i get: Traceback (most recent call last): File "test.py", line 5, in func raise Exception('Dummy') Exception: Dummy traceback.format_stack() is not what i want, as need traceback object to be passed to a third party module. I am particularly interested in this

What is the difference between a stack and a frame?

无人久伴 提交于 2019-11-27 09:23:49
问题 Under what situations would I want to use one over the other? What is the difference between: >>> import inspect >>> print(inspect.getouterframes(inspect.currentframe())) [(<frame object at 0x8fc262c>, '<stdin>', 1, '<module>', None, None)] And: >>> import traceback >>> traceback.extract_stack() [('<stdin>', 1, '<module>', None)] Update: Another: >>> import sys >>> print(sys._getframe().f_trace,sys._getframe().f_code) (None, <code object <module> at 0x8682a88, file "<stdin>", line 1>) I do

Python: Getting a traceback from a multiprocessing.Process

落花浮王杯 提交于 2019-11-27 07:13:45
I am trying to get hold of a traceback object from a multiprocessing.Process. Unfortunately passing the exception info through a pipe does not work because traceback objects can not be pickled: def foo(pipe_to_parent): try: raise Exception('xxx') except: pipe_to_parent.send(sys.exc_info()) to_child, to_self = multiprocessing.Pipe() process = multiprocessing.Process(target = foo, args = (to_self,)) process.start() exc_info = to_child.recv() process.join() print traceback.format_exception(*exc_info) to_child.close() to_self.close() Traceback: Traceback (most recent call last): File "/usr/lib