traceback

The logs I am creating in Python are intended to be temporarily stored as files which will, in turn, be processed into a log database. They take a pipe-delineated format to dictate how the logs will be processed, but logging.exception() is breaking my standard by adding one too many fields and way too many newlines. import logging logging.basicConfig(filename='output.txt', format='%(asctime)s|%(levelname)s|%(message)s|', datefmt='%m/%d/%Y %I:%M:%S %p', level=logging.DEBUG) logging.info('Sample message') try: x = 1 / 0 except ZeroDivisionError as e: logging.exception('ZeroDivisionError: {0}'

Using: traceback.print_stack() I can get: File "x.py", line 20, in <module> y(x) File "x.py", line 11, in y fun(x) File "x.py", line 8, in fun traceback.print_stack() I there any way to get something like this: File "x.py", line 20, in <module> y(x) WHERE x == 1 File "x.py", line 11, in y fun(x) WHERE x == 'str' File "x.py", line 8, in fun traceback.print_stack() I just want to see what arguments was passed to functions. You can probably rig something up by using inspect.getargvalues() and accessing the stack frame belonging to your traceback: inspect.getargvalues(traceback.tb_frame) You'll

Can I get the parameters of the last function called in traceback? How? I want to make a catcher for standard errors to make readable code, yet provide detailed information to user. In the following example I want GET_PARAMS to return me a tuple of parameters supplied to os.chown. Examining the inspect module advised by Alex Martelli, I couldn't find that. def catch_errors(fn): def decorator(*args, **kwargs): try: return fn(*args, **kwargs) except (IOError, OSError): msg = sys.exc_info()[2].tb_frame.f_locals['error_message'] quit(msg.format(SEQUENCE_OF_PARAMETERS_OF_THE_LAST_FUNCTION_CALLED)\

try: print blah except KeyError: traceback.print_exc() I used to debug like this. I'd print to the console. Now, I want to log everything instead of print, since Apache doesn't allow printing. So, how do I log this entire traceback? You can use python's logging mechanism: import logging ... logger = logging.getLogger("blabla") ... try: print blah # You can use logger.debug("blah") instead of print except KeyError: logger.exception("An error occurred") This will print the stack trace and will work with apache. If you're running Django's trunk version (or 1.3 when it's released), there are a

Consider the following code and traceback: >>> try: ... raise KeyboardInterrupt ... except KeyboardInterrupt: ... raise Exception ... Traceback (most recent call last): File "<stdin>", line 2, in <module> KeyboardInterrupt During handling of the above exception, another exception occurred: Traceback (most recent call last): File "<stdin>", line 4, in <module> Exception >>> I'd like to print only the most recent traceback (the one in which Exception was raised). How can this be achieved? From the above example, I'd like to print the following, as if raise Exception had been called outside the

In reading about virtualenv here I realized I didn't have pip 1.3+, so I ran pip install --upgrade pip and now when I run pip --version i get the following: Traceback (most recent call last): File "/usr/local/bin/pip", line 5, in <module> from pkg_resources import load_entry_point File "/usr/local/Cellar/python/2.7.3/Frameworks/Python.framework/Versions/2.7/lib/python2.7/site-packages/distribute-0.6.34-py2.7.egg/pkg_resources.py", line 2807, in <module> parse_requirements(__requires__), Environment() File "/usr/local/Cellar/python/2.7.3/Frameworks/Python.framework/Versions/2.7/lib/python2.7