timestamp

Adjusting CSV Datetime/Timestamp Formats in AWS or SQL Server

跟風遠走 提交于 2020-06-01 05:35:27
问题 I imported the contents of a SQL Server table into an S3 CSV file. A year_month column was formatted as datetime in SQL Server, and appeared as 2020-01-01 00:00:00.000 . That same record appears as 1/1/2020 12:00:00 AM in the S3 csv file. I am using this dataset in AWS Forecast, which requires 2020-01-01 00:00:00.000 formatting. What is the best tool within AWS to adjust the format? Or conversely, can I tackle the problem in SQL Server? 来源: https://stackoverflow.com/questions/61992855

Pandas assign group numbers for each time bin

安稳与你 提交于 2020-05-31 03:40:41
问题 I have a pandas dataframe that looks like below. Key Name Val1 Val2 Timestamp 101 A 10 1 01-10-2019 00:20:21 102 A 12 2 01-10-2019 00:20:21 103 B 10 1 01-10-2019 00:20:26 104 C 20 2 01-10-2019 14:40:45 105 B 21 3 02-10-2019 09:04:06 106 D 24 3 02-10-2019 09:04:12 107 A 24 3 02-10-2019 09:04:14 108 E 32 2 02-10-2019 09:04:20 109 A 10 1 02-10-2019 09:04:22 110 B 10 1 02-10-2019 10:40:49 Starting from the earliest timestamp, that is, '01-10-2019 00:20:21', I need to create time bins of 10

Create a dataframe of csv files based on timestamp intervals

↘锁芯ラ 提交于 2020-05-29 09:36:49
问题 I believe that my problem is really straightforward and there must be a really easy way to solve this issue, however as I am quite new with Python, specially pandas, I could not sort it out by my own. I have hundreds of csv files that are on the following format: text_2014-02-22_13-00-00 So the format is str_YY-MM-DD_HH-MI-SS . And to sum up, every file represents a interval of one hour. I want to create a dataframe based on the interval that I will set with Start_Time and End_Time , from

How to create folder with date and time using timestamp with robocopy command [duplicate]

跟風遠走 提交于 2020-05-17 06:54:09
问题 This question already has answers here : How do I get current date/time on the Windows command line in a suitable format for usage in a file/folder name? (27 answers) Closed last month . I want to create a folder using this Timestamp: %DATE:/=-%_%TIME::=-% My Robocopy command is : ROBOCOPY "%BUILD_SOURCESDIRECTORY%\sourcefolder\" "\\server\destination\%date:/=-%_%time::=-%" /V but it is not working, getting an error: 2020-04-07T03:53:21.7269608Z ##[error]Process completed with exit code 1.

Create a series of timestamps along milliseconds in R

荒凉一梦 提交于 2020-05-16 20:33:05
问题 I have start date as "2017-11-14 10:11:01 CET" and end date as "2017-11-15 01:15:59 CET". I want to create timestamps of 500 milliseconds each, between these start and end timestamps. E.g. I need a dataframe containing the following output timestamp 2017-11-14 10:11:01.000 2017-11-14 10:11:01.500 2017-11-14 10:11:02.000 2017-11-14 10:11:02.500 . . . 2017-11-15 01:15:59.000 Somehow, I managed to get the start and end date in milliseconds using the following code: start.date <- strptime("2017

Spark: converting GMT time stamps to Eastern taking daylight savings into account

给你一囗甜甜゛ 提交于 2020-05-14 18:13:52
问题 I'm trying to convert a column of GMT timestamp strings into a column of timestamps in Eastern timezone. I want to take daylight savings into account. My column of timestamp strings look like this: '2017-02-01T10:15:21+00:00' I figured out how to convert the string column into a timestamp in EST: from pyspark.sql import functions as F df2 = df1.withColumn('datetimeGMT', df1.myTimeColumnInGMT.cast('timestamp')) df3 = df2.withColumn('datetimeEST', F.from_utc_timestamp(df2.datetimeGMT, "EST"))

Hive String to Timestamp conversion with Milliseconds

拥有回忆 提交于 2020-05-13 14:35:10
问题 I have a requirement to convert the mentioned input string format and produce the desired output in timestamp as shown below. Input: 16AUG2001:23:46:32.876086 Desired Output: 2001-08-16 23:46:32.876086 Output which is coming by running the below code: 2001-08-17 00:01:08 Query: select '16AUG2001:23:46:32.876086' as row_ins_timestamp, from_unixtime(unix_timestamp('16AUG2001:23:46:32.876086', 'ddMMMyyyy:HH:mm:ss.SSSSSS')) as row_ins_timestamp from temp; Milliseconds part is not getting

Convert date to unix time stamp in c++

血红的双手。 提交于 2020-05-10 21:30:34
问题 As some websites that convert those unix time stamps say, the stamp of 2013/05/07 05:01:00 (yyyy/mm/dd, hh:mm:ss) is 1367902860. The way I do it in C++, the stamp differs from the date. Here is the code: time_t rawtime; struct tm * timeinfo; int year=2013, month=5, day=7, hour = 5, min = 1, sec = 0; /* get current timeinfo: */ time ( &rawtime ); //or: rawtime = time(0); /* convert to struct: */ timeinfo = localtime ( &rawtime ); /* now modify the timeinfo to the given date: */ timeinfo->tm

postgreSQL alter column data type to timestamp without time zone

你。 提交于 2020-05-10 14:49:50
问题 I want to alter one column of data from text into type timestamp. There is no time zone in my data. The format of my data is like 28-03-17 17:22, including time and date but no time zone. In other words, all my data are in the same time zone. How can I do it? I tried multiple ways below, but I still can not find the right approach. Hope you can help me. Certainly, I can build a new table if my trouble can be solved. alter table AB alter create_time type TIMESTAMP; ERROR: column "create_time"

postgreSQL alter column data type to timestamp without time zone

大憨熊 提交于 2020-05-10 14:49:18
问题 I want to alter one column of data from text into type timestamp. There is no time zone in my data. The format of my data is like 28-03-17 17:22, including time and date but no time zone. In other words, all my data are in the same time zone. How can I do it? I tried multiple ways below, but I still can not find the right approach. Hope you can help me. Certainly, I can build a new table if my trouble can be solved. alter table AB alter create_time type TIMESTAMP; ERROR: column "create_time"