timestamp

Oracle与PostgreSQL中Timestamp型公元前、后数值的详解及JDBC存取

由 橙三吉。 提交于 2020-04-25 18:27:28
字段：date value1： 2010-01-01 value2： 2010-01-01BC 1.直接向数据库插入数值时： oracle需要使用to_timestamp('2010-01-01','yyyy-mm-ddBC'), PG可以直接用字符串‘2010-01-01BC'。 2.直接从数据库查询时： 在oracle数据库中直接查询date字段，value1和value1显示没有区别，均为2010-01-01， 使用to_char(time,'dd-mm-yyyybc','nls_date_language=American') ，才显示出bc和ad。如下： SQL> select time,to_char(time,'dd-mm-yyyybc','nls_date_language=American') AS TRUDATE; TIME TRUEDATE --------------------------------------------------------------------------- 01-JAN-10 12.00.00.000000 AM 01-01-2010bc 01-JAN-10 12.00.00.000000 AM 01-01-2010ad 在PG中：直接查询即可显示BC，如下： highgo=# select * from testtime;

Return Timestamp With Prepared Statement

由 偶尔善良 提交于 2020-04-10 05:39:11
问题 I have an auto generated timestamp that is created each time a record is inserted or updated in a mysql table. Is there a way to return this timestamp in a way similar to how I would use a keyholder to return a newly created id? KeyHolder keyHolder = new GeneratedKeyHolder(); JdbcTemplate jdbcTemplate = new JdbcTemplate(dataSource); //Insert Contact jdbcTemplate.update(new PreparedStatementCreator() { @Override public PreparedStatement createPreparedStatement(Connection connection) throws

Return Timestamp With Prepared Statement

由 Deadly 提交于 2020-04-10 05:36:17
问题 I have an auto generated timestamp that is created each time a record is inserted or updated in a mysql table. Is there a way to return this timestamp in a way similar to how I would use a keyholder to return a newly created id? KeyHolder keyHolder = new GeneratedKeyHolder(); JdbcTemplate jdbcTemplate = new JdbcTemplate(dataSource); //Insert Contact jdbcTemplate.update(new PreparedStatementCreator() { @Override public PreparedStatement createPreparedStatement(Connection connection) throws

在Titanium下,iPhone操作sqlite,时间戳毫秒取值不正确

由 ＊爱你＆永不变心＊ 提交于 2020-04-09 12:11:16
##问题描述: 在Titanium下存如sqlite毫秒级别的时间戳, 再获取的时候得到的数值不正确,有时候还可能是负数..在Android下没有此问题. ##解决办法: 先在数据库中更改原先的时间戳的字段为VARCHAR类型的,以后存储字符串的时间戳,如: '1360229569444' 由于字符串是无法比较的,在需要根据此字段作为where条件时,使用CAST(expr AS target_type)强制转换为NUMERIC类型,然后进行比较.如: select * from mytable where CAST(start_time AS NUMERIC) > 1360229569444 ###参考资料: [SQLite学习手册:三.转换表达式] ( http://www.2cto.com/database/201202/120267.html ) [Date Formatting And Format Validation: 一个js日期操作库] ( http://www.javascripttoolbox.com/lib/date/documentation.php ) 来源： oschina 链接： https://my.oschina.net/u/865845/blog/112805

Given a Unix timestamp, how to get beginning and end of that day?

由 China☆狼群 提交于 2020-04-05 07:12:08
问题 I have a Unix timestamp like this: $timestamp=1330581600 How do I get the beginning of the day and the end of the day for that timestamp? e.g. $beginOfDay = Start of Timestamp's Day $endOfDay = End of Timestamp's Day I tried this: $endOfDay = $timestamp + (60 * 60 * 23); But I don't think it'll work because the timestamp itself isn't the exact beginning of the day. 回答1: strtotime can be used to to quickly chop off the hour/minutes/seconds $beginOfDay = strtotime("today", $timestamp);

Given a Unix timestamp, how to get beginning and end of that day?

由 萝らか妹 提交于 2020-04-05 07:11:50
问题 I have a Unix timestamp like this: $timestamp=1330581600 How do I get the beginning of the day and the end of the day for that timestamp? e.g. $beginOfDay = Start of Timestamp's Day $endOfDay = End of Timestamp's Day I tried this: $endOfDay = $timestamp + (60 * 60 * 23); But I don't think it'll work because the timestamp itself isn't the exact beginning of the day. 回答1: strtotime can be used to to quickly chop off the hour/minutes/seconds $beginOfDay = strtotime("today", $timestamp);

Mysql: Find entries from specific day using timestamp column

由 跟風遠走 提交于 2020-03-26 07:31:25
问题 My each row have time-stamp column (called 'timestamp'). How can I find all rows from specific day? I've tried calculating start/end of the day, but i'm looking for a better way. 回答1: You need to extract just the date part, using DATE() function: SELECT * FROM yourtable WHERE DATE(your_column) = '2013-07-03' or you can use this, that can make use of an index: SELECT * FROM yourtable WHERE your_column >= '2013-07-03' AND your_column < '2013-07-03' + INTERVAL 1 DAY 回答2: use the date function:

postgresql timestamp to std::chrono value

由 点点圈 提交于 2020-03-25 23:06:34
问题 What is the appropriate way to work with the the postgresql datatype "timestamp without timezone" from c++ (libpqxx)? I haven't been able to find a way to do this yet. I am restricted to the "timestamp without timezone" datatype in the postgresql and the environment is running utc time. I was hoping to find a mapping to a std::chrono::system_clock::time_point member but I can't find a such in libpqxx. //s has a time_point var and r is a pqxx::result, r[0] is sensible s.creationtime = r[0][

Timestamp in DBase7

由 ε祈祈猫儿з 提交于 2020-03-21 20:04:10
问题 I'm trying to read DBase 7 timestamp values from .dbf files. From DBase format specification I got the following: 8 bytes - two longs, first for date, second for time. The date is the number of days since 01/01/4713 BC. Time is hours * 3600000L + minutes * 60000L + Seconds * 1000L However, I didn't get any correct values via this algorithm. Here are some timestamp values in binary representation and actual datetime values: 42 CC E1 EC 41 FB 64 00 | 27/08/2013 19:12:13 42 CC E1 ED AF 0E 60 00

读懂程序里的--时间

由 。_饼干妹妹 提交于 2020-03-17 12:28:48
某厂面试归来，发现自己落伍了！>>> 题外话，祝各位程序猿们中秋佳节快乐~~~O(∩_∩)O~。 ##追本溯源 ###历史 ####GMT 百度百科： 格林威治时间 ####UTC 百度百科： 协调世界时 两者比较： GMT ：最初确立的世界标准时间，名字由来是因为英国的皇家格林尼治天文台而得名，因为本初子午线被定义在通过那里的经线。自1924年2月5日开始，格林尼治天文台每隔一小时会向全世界发放调时信息。由于地球每天的自转是有些不规则的，而且正在缓慢减速，因此，格林尼治时间已经不再被作为标准时间使用。新的标准时间，是由原子钟报时的协调世界时（UTC）。 --百度百科 UTC ：是目前使用的世界标准时间，其以原子时秒长为基础，在时刻上尽量接近于格林尼治平时。国际原子时的误差为每日数纳秒，而世界时的误差为每日数毫秒。对于这种情况，一种称为协调世界时的折衷时标于1972年面世。为确保协调世界时与世界时相差不会超过0.9秒，在有需要的情况下会在协调世界时内加上正或负闰秒。因此协调世界时与国际原子时之间会出现若干整数秒的差别。位于巴黎的国际地球自转事务中央局负责决定何时加入闰秒。 --维基百科 这里要提下有趣的事情是，因为UTC闰秒的缘故，java中的秒可能为60或61，但java文档中有说这个是依据计算机的环境，无法保证准确性囧。 根据这两个比较
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