timedelta

This question already has an answer here: Converting string into datetime 19 answers I have a raw input from the user such as "2015-01-30"...for the query I am using, the date has to be inputed as a string as such "yyyy-mm-dd". I would like to increment the date by 1 month at end of my loop s.t "2015-01-30" becomes "2015-02-27" (ideally the last business day of the next month). I was hoping someone could help me; I am using PYTHON, the reason I want to convert to datetime is I found a function to add 1 month. Ideally my two questions to be answered are (in Python): 1) how to convert string

I've spent the past hour digging around the Python docs and many SO questions; please forgive me for being another Python newbie trapped by the mystery of time difference in Python. My goal is to determine the difference between the current time and a certain date/time regardless of being in the past/future and return a workable format such as seconds. For example, if the inputs are 2:00PM and 4:00PM (now), I'd like it to say "-7200", representing the event occurred two hours AGO. If the inputs are Fri 4:00PM (now) and Sun 5:00PM the output should be "176400" seconds, representing two days and

I have a pandas dataframe with two columns, a date column and an int column, and I'd simply like to add the int column (in days) to the date column. I found a solution using df.apply(), but that was too slow on my full dataset. I don't see a ton of documentation on doing this in a vectorized manner (the closest I could find was this ), so I wanted to make sure the solution I found was the best way to go forward. My raw data is just a column of strings as a column of ints (days). import pandas as pd from datetime import timedelta df = pd.DataFrame([['2016-01-10',28],['2016-05-11',28],['2016-02

A mysql database table has a column whose datatype is time ( http://dev.mysql.com/doc/refman/5.0/en/time.html ). When the table data is accessed, Python returns the value of this column as a datetime.timedelta object. How do I extract the time out of this? (I didn't really understand what timedelta is for from the python manuals). E.g. The column in the table contains the value "18:00:00" Python-MySQLdb returns this as datetime.timedelta(0, 64800) Please ignore what is below (it does return different value) - Added: Irrespective of the time value in the table, python-MySQLdb seems to only

I have some input data, with timestamps in the input file in the form of hours from the date time specified in the filename. This is a bit useless, so I need to convert it to python datetime.datetime objects, and then put it in a numpy array. I could write a for loop, but I'd like to do something like: numpy.arange(datetime.datetime(2000, 1,1), datetime.datetime(2000, 1,2), datetime.timedelta(hours=1)) which throws a TypeError. Can this be done? I'm stuck with python 2.6 and numpy 1.6.1. nneonneo See NumPy Datetimes and Timedeltas . Basically, you can represent datetimes in NumPy using the