switch-statement

xamarin.forms add switch in toolbar

北战南征 提交于 2021-02-07 10:17:28
问题 Is it possible to add a switch on the toolbar? <ContentPage.ToolbarItems> <ToolbarItem> <Switch x:Name="Switch1" IsToggled="True" Margin="5,0,0,0"/> </ToolbarItem> </ContentPage.ToolbarItems> Does anybody have any ideas? Thanks! 回答1: <ContentPage xmlns="http://xamarin.com/schemas/2014/forms" xmlns:x="http://schemas.microsoft.com/winfx/2009/xaml" xmlns:local="clr-namespace:TitleViewSample" x:Class="TitleViewSample.MainPage"> <NavigationPage.TitleView> <Switch x:Name="Switch1" IsToggled="True"

PHP switch statement inside another switch statement

久未见 提交于 2021-02-07 05:01:53
问题 I have this situation where I have to check two GET variables. After checking the first one in one switch statement inside the statement, the second variable has to be checked in the second switch statement inside the first one case loop. I can't post the exact code here, but here is an example: <?php error_reporting(E_ALL); ini_set('display_errors', '1'); switch($_GET['parent']){ case 'child1': if(!isset($_GET['child'])){ echo "Only parent"; } else{ switch($_GET['child']){ case 'test': echo

Grouping switch statement cases together?

不羁的心 提交于 2021-02-05 20:17:02
问题 I may be over looking something but is there a simple way in C++ to group cases together instead of writing them out individually? I remember in basic I could just do: SELECT CASE Answer CASE 1, 2, 3, 4 Example in C++ (For those that need it): #include <iostream.h> #include <stdio.h> int main() { int Answer; cout << "How many cars do you have?"; cin >> Answer; switch (Answer) { case 1: case 2: case 3: case 4: cout << "You need more cars. "; break; case 5: case 6: case 7: case 8: cout << "Now

Grouping switch statement cases together?

你说的曾经没有我的故事 提交于 2021-02-05 20:14:13
问题 I may be over looking something but is there a simple way in C++ to group cases together instead of writing them out individually? I remember in basic I could just do: SELECT CASE Answer CASE 1, 2, 3, 4 Example in C++ (For those that need it): #include <iostream.h> #include <stdio.h> int main() { int Answer; cout << "How many cars do you have?"; cin >> Answer; switch (Answer) { case 1: case 2: case 3: case 4: cout << "You need more cars. "; break; case 5: case 6: case 7: case 8: cout << "Now

C++ cin.fail() executes and moves to next line even though input is of another data type

て烟熏妆下的殇ゞ 提交于 2021-02-05 09:17:10
问题 I am using get.fail() to check if there's any char in the input, and if there is I would like to give the user a chance to re-enter. However, the program seems to still accept the user input whenever there's an integer in front of the input no matter the case. Say w1 and 1w , the program will tell the user that the it only accepts integers while the latter one accepts the input and moves over to the next line which then causes another problem. void userChoice(int input){ switch(input) { case

(Java) How to get user input without pressing the “enter” key [duplicate]

心不动则不痛 提交于 2021-02-05 08:46:06
问题 This question already has answers here : How to read a single char from the console in Java (as the user types it)? (5 answers) Closed last year . I was curious and wanted to test this type of thing out in java. I looked it up online and couldn't really find anything that helped out in any of the questions I found; so I decided to ask it myself. In the example I wrote out, you're given a couple of options and you get user input and then stuff happens based off of user input using a switch

Switch statement with string wrong output

笑着哭i 提交于 2021-02-05 08:31:46
问题 I came across this basic question, where switch case is used with string. Break statement is not used between cases but why it going to all the cases even when it is not matching the case string? So I'm curious to know why is the output 3 and not 1? public static void main(String [] args) { int wd=0; String days[]={"sun","mon","wed","sat"}; for(String s:days) { switch (s) { case "sat": case "sun": wd-=1; break; case "mon": wd++; case "wed": wd+=2; } } System.out.println(wd); } 回答1: You don't

Switch statement with string wrong output

青春壹個敷衍的年華 提交于 2021-02-05 08:31:31
问题 I came across this basic question, where switch case is used with string. Break statement is not used between cases but why it going to all the cases even when it is not matching the case string? So I'm curious to know why is the output 3 and not 1? public static void main(String [] args) { int wd=0; String days[]={"sun","mon","wed","sat"}; for(String s:days) { switch (s) { case "sat": case "sun": wd-=1; break; case "mon": wd++; case "wed": wd+=2; } } System.out.println(wd); } 回答1: You don't

Switch statement with string wrong output

可紊 提交于 2021-02-05 08:31:24
问题 I came across this basic question, where switch case is used with string. Break statement is not used between cases but why it going to all the cases even when it is not matching the case string? So I'm curious to know why is the output 3 and not 1? public static void main(String [] args) { int wd=0; String days[]={"sun","mon","wed","sat"}; for(String s:days) { switch (s) { case "sat": case "sun": wd-=1; break; case "mon": wd++; case "wed": wd+=2; } } System.out.println(wd); } 回答1: You don't

Switch Statement, it does not work with prompt

匆匆过客 提交于 2021-02-05 05:53:25
问题 I just learned switch statements. I was practicing it by building something. When i set the value of variable to a number it works but when i asks the user for a number it always outputs the default statement . It works with this code: confirm("You want to learn basic counting?"); var i = 0; switch (i) { case 0: console.log(i); i++ case 1: console.log(i); i++; case 2: console.log(i); i++; case 3: console.log(i); i++; case 4: console.log(i); i++; case 5: console.log(i); i++; case 6: console