super

Today, I read the official doc of super . In which it mentioned multiple inheritance will be decided by the __mro__ attribute of a class. So I did a bit experiment, but its result surprised me. # CODE PART class GrandFather(object): def p(self): print "I'm old." class Father(GrandFather): def p(self): print "I'm male." class Mother(object): def p(self): print "I'm female." class Son(Father, Mother): def p(self): print "busy, busy, crwaling. " # EXPERIMENT PART In [1]: Son.__mro__ Out[1]: (__main__.Son, __main__.Father, __main__.GrandFather, __main__.Mother, object) In [2]: Father.__mro__ Out[2

According to the docs, super(cls, obj) returns a proxy object that delegates method calls to a parent or sibling class of type cls I understand why super() offers this functionality, but I need something slightly different: I need to create a proxy object that delegates methods calls (and attribute lookups) to class cls itself; and as in super , if cls doesn't implement the method/attribute, my proxy should continue looking in the MRO order (of the new not the original class). Is there any function I can write that achieves that? Example: class X: def act(): #... class Y: def act(): #... class

Can I use clean Python 3 super() syntax in Python 2.5.6? Maybe with some kind of __future__ import? donkopotamus You cannot use a bare super() call that contains no type/class. Nor can you implement a replacement for it that will work. Python 3.x contains special support to enable bare super() calls (it places a __class__ cell variable in all functions defined within a class - see PEP 3135 Update As of Python 2.6+, bare super() calls can be used via the future Python package. See posita's answer for an explanation. posita I realize this question is old, and the selected answer may have been

This question is asking the opposite of Inherit namedtuple from a base class in python , where the aim is to inherit a subclass from a namedtuple and not vice versa. In normal inheritance, this works: class Y(object): def __init__(self, a, b, c): self.a = a self.b = b self.c = c class Z(Y): def __init__(self, a, b, c, d): super(Z, self).__init__(a, b, c) self.d = d [out]: >>> Z(1,2,3,4) <__main__.Z object at 0x10fcad950> But if the baseclass is a namedtuple : from collections import namedtuple X = namedtuple('X', 'a b c') class Z(X): def __init__(self, a, b, c, d): super(Z, self).__init__(a, b

With a simple pair of classes, I cannot get super working: class A(object): q = 'foo' class B(A): q = 'bar' def __init__(self): self.a = super(A, self).q a = B() errors like so: --------------------------------------------------------------------------- AttributeError Traceback (most recent call last) <ipython-input-210-802575054d17> in <module>() 5 def __init__(self): 6 self.a = super(A, self).q ----> 7 a = B() <ipython-input-210-802575054d17> in __init__(self) 4 q = 'bar' 5 def __init__(self): ----> 6 self.a = super(A, self).q 7 a = B() AttributeError: 'super' object has no attribute 'q' I

I am new to Java. My problem is that I have a class names MyClassExp. I have extended it from JFrame. Inside the class, I initiate an object of another class named TabbedFrame. TabbedFrame also extends a class DemoFrame . In DemoFrame, I have the title of the page set using keyword 'super' like: super("Some Title"); Now when I run my MyClassExp, even after creating a JFrame as: new JFrame("New Title"); I'm still getting the same title i.e Some Title. Is there any way to solve this problem? I've tried a lot to solve it but failed :'( Use the API method public void setTitle(String title) . -