substr

Get BinData UUID from Mongo as string

匿名 (未验证) 提交于 2019-12-03 01:49:02
可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效,请关闭广告屏蔽插件后再试): 问题: I currently have some ids stored in Mongo as UUIDs (necessary for processing). They get returned like this: "_id" : new BinData(3, "JliB6gIMRuSphAD2KmhzgQ==") What would be an easy way to turn this value into a string for debugging? Just to be clear - the application can handle the data fine. I just need a way to get the actual UUID from Mongo quickly. 回答1: The answer to your question is more complicated that you would expect! The main reason it's complicated is that for historical reasons (unfortunately) different drivers have written UUIDs

Using JQuery to set CKEditor Value

匿名 (未验证) 提交于 2019-12-03 01:48:02
可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效,请关闭广告屏蔽插件后再试): 由 翻译 强力驱动 问题: I have a CKEditor textarea: I have jQuery trying to set the value from the database: $ ( '#ContentPlaceHolder_taBody' ). val ( substr [ 5 ]); Don't worry about the substring I already tested that it is returning a string. For testing purposes I replaced the substring with 'test' and was receiving the same issue. I know that the jquery surrounding this line doesn't affect it because the other textfields I'm trying to populate work. Just when it comes to the ckeditor. Here is the script in whole: function ( obj ) { $ . ajax ({ type :

Oracle substr 字符截取函数

和自甴很熟 提交于 2019-12-03 01:40:03
1、substr函数格式 (俗称:字符截取函数)   格式1: substr(string string, int a, int b);   格式2:substr(string string, int a) ; 解释: 格式1: 1、string 需要截取的字符串 2、a 截取字符串的开始位置(注:当a等于0或1时,都是从第一位开始截取) 3、b 要截取的字符串的长度 格式2: 1、string 需要截取的字符串 2、a 可以理解为从第a个字符开始截取后面所有的字符串。 2、实例解析 格式1: 1、select substr('HelloWorld',0,3) value from dual; //返回结果:Hel,截取从“H”开始3个字符 2、select substr('HelloWorld',1,3) value from dual; //返回结果:Hel,截取从“H”开始3个字符 3、select substr('HelloWorld',2,3) value from dual; //返回结果:ell,截取从“e”开始3个字符 4、select substr('HelloWorld',0,100) value from dual; //返回结果:HelloWorld,100虽然超出预处理的字符串最长度,但不会影响返回结果,系统按预处理字符串最大数量返回。 5、select

Split Strings in Half (Word-Aware) with PHP

匿名 (未验证) 提交于 2019-12-03 01:39:01
可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效,请关闭广告屏蔽插件后再试): 问题: I'm trying to split strings in half, and it should not split in the middle of a word. So far I came up with the following which is 99% working : $text = "The Quick : Brown Fox Jumped Over The Lazy / Dog"; $half = (int)ceil(count($words = str_word_count($text, 1)) / 2); $string1 = implode(' ', array_slice($words, 0, $half)); $string2 = implode(' ', array_slice($words, $half)); This does work, correctly splitting any string in half according to the number of words in the string. However, it is removing any symbols in the string, for example

Transforming Calendar Quarter to Financial Quarter

匿名 (未验证) 提交于 2019-12-03 01:36:02
可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效,请关闭广告屏蔽插件后再试): 问题: I am working with a dateframe (INPUT) that contains number the of transaction of a product per calendar quarter. The first column (DATE) contains the calendar quarter in this format "2016 Q2". I would like to transform this date into the a financial quarter format such as "2016/17 Q1". The financial year start in the 1st April. I came up with the following code which does the job, but I was wondering if there is a formula or a neater code that I could use. INPUT$FY_Date=character(nrow(INPUT)) for (i in 1:nrow(INPUT)) { INPUT$FY_Date[i]= if

How to toggle (show/hide) element in Angular 4?

匿名 (未验证) 提交于 2019-12-03 01:36:02
可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效,请关闭广告屏蔽插件后再试): 问题: This is my html element: <ng-container> <span *ngIf="row.messageText && row.messageText.length >= 30 && expanded">{{row.messageText.substr(0, 25)}} <span>more</span> </span> </ng-container> It shows part of a message when row.messageText.length is greater than 30. I need first span to show entire message (by using row.messageText.substr() ) after clicking the more span. I think that there is a solution by using (click)="toggle()" and setting some true/false values. Do you have any ideas? 回答1: <ng-container> <span *ngIf="row.messageText &&

Disable automatic formatting inside WordPress shortcodes

匿名 (未验证) 提交于 2019-12-03 01:29:01
可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效,请关闭广告屏蔽插件后再试): 问题: I've seen the tutorials on creating a [raw] shortcode that leaves the code inside it untouched, http://www.wprecipes.com/disable-wordpress-automatic-formatting-on-posts-using-a-shortcode but unfortunately this only applies to 1 shortcode at a time... AND b/c the else statement bypasses the normal filters and calls the functions directions, my other modifications to autop and texturize functions get ignored. is there a way to 1. match multiple shortcodes and 2. preserve my other add/remove filters to the_content? 回答1: After implementing

How to skip comma from csv using double quotes

匿名 (未验证) 提交于 2019-12-03 01:23:02
可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效,请关闭广告屏蔽插件后再试): 问题: I am getting a string in the below format after reading data from a csv file v_lastline = '29218368,8062115," Benedict Canyon Equities, Inc",CLS,,FAX'; I just want to convert it into an array while will contain 6 values, the comma before the , Inc needs to be escaped. Can any one please suggest whats the best way to do it in PL/SQL? 回答1: This is similar to this question , but you have empty elements in your list; and a simple translation of one of the patterns I tried there skips those: var v_lastline varchar2(50); exec :v_lastline :=

DBMS_LOB.SUBSTR() throwing “character string buffer too small” error

匿名 (未验证) 提交于 2019-12-03 01:20:02
可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效,请关闭广告屏蔽插件后再试): 问题: Does oracle have a method to get substring based on number of bytes from a CLOB field? select DBMS_LOB.SUBSTR(a.COMMENTS, 3998, 1) FROM FOO; I am getting error: "ORA-06502: PL/SQL: numeric or value error: character string buffer too small" . The problem was in special characters. Each new special character takes 8 bytes so when I reduce the string limit to 3992 then it works. DBMS_LOB.SUBSTR(a.COMMENTS, 3992, 1) works. For testing purpose I put many special characters and again it throws same error. Does oracle have any method which finds

Use function as default value for column in Oracle11g

匿名 (未验证) 提交于 2019-12-03 01:20:02
可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效,请关闭广告屏蔽插件后再试): 问题: We are testing out Oracle at my work and im in charge of building all of the database objects (tables, procs, trigger, etc) on Oracle, and we currently use Microsoft SQL Server 2008 R2. We use uniqueidentifier's for almost all of our ID column's. I used this function to create GUID's: CREATE OR REPLACE FUNCTION NEWID RETURN CHAR IS guid CHAR(36) ; BEGIN SELECT SYS_GUID() INTO guid FROM DUAL; guid := SUBSTR(guid, 1, 8) || '-' || SUBSTR(guid, 9, 4) || '-' || SUBSTR(guid, 13, 4) || '-' || SUBSTR(guid, 17, 4) || '-' || SUBSTR(guid, 21); RETURN