substr

可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效，请关闭广告屏蔽插件后再试): 问题: I wanted to see your input on this concern I'm currently experiencing. It turns out that: <?php $disc_t=$name; if(strlen($disc_t)<=15) { $name_now=mb_substr( strip_tags($disc_t), 0, 10 ).''; } else { $name_now=mb_substr( strip_tags($disc_t), 0, 10).'...'; } ?> is somehow giving me an error on the site, the error shows: Fatal error: Call to undefined function mb_substr() in /home/(website)/public_html/index.php on line 308 I don't quite understand what they mean by mb_substr , is this a PHP version error? I am currently using PHP 5.3.19 回答1:

可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效，请关闭广告屏蔽插件后再试): 问题: One of my colleagues recently interviewed some candidates for a job and one said they had very good Perl experience. Since my colleague didn't know Perl, he asked me for a critique of some code written (off-site) by that potential hire, so I had a look and told him my concerns (the main one was that it originally had no comments and it's not like we gave them enough time). However, the code works so I'm loathe to say no-go without some more input. Another concern is that this code basically looks exactly how I'd code it in C. It's been a

可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效，请关闭广告屏蔽插件后再试): 问题: How to convert string to title case while following rules , not just simply capitalizing every first letter of the word? Sample rule: Capitalize all words, with exception to: Lowercase all articles (a, the), prepositions (to, at, in, with), and coordinating conjunctions (and, but, or) Capitalize the first and last word in a title, regardless of part of speech Any easy way to do this in bash? One-liners appreciated. (And just as an additional note, this is to be used in parcellite actions.) 回答1: $ cat titles.txt purple haze Somebody To Love

可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效，请关闭广告屏蔽插件后再试): 问题: I have a a.pdb file as, ATOM 1 N ARG 1 0.000 0.000 0.000 1.00 0.00 N ATOM 2 H1 ARG 1 0.000 0.000 0.000 1.00 0.00 H ATOM 3 H2 ARG 1 0.000 0.000 0.000 1.00 0.00 H ATOM 4 H3 ARG 1 0.000 0.000 0.000 1.00 0.00 H and a.xyz file as 16.388 -5.760 -23.332 17.226 -5.608 -23.768 15.760 -5.238 -23.831 17.921 -5.926 -26.697 I want to replace 6,7 and 8th column of a.pdb with a.xyz. Once replaced, I need to maintain tabs/space/columns of a.pdb. I have tried awk 'NR==FNR {fld1[NR]=$1; fld2[NR]=$2; fld3[NR]=$3; next} {$6=fld1[FNR]; $7=fld2[FNR]; $8=fld3[FNR]

可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效，请关闭广告屏蔽插件后再试): 问题: I need to round down a decimal in PHP to two decimal places so that: 49.955 becomes... 49.95 I have tried number_format , but this just rounds the value to 49.96 . I cannot use substr because the number may be smaller (such as 7.950). I've been unable to find an answer to this so far. Any help much appreciated. 回答1: This can work: floor($number * 100) / 100 回答2: Here is a nice function that does the trick without using string functions: An other option is to subtract a fraction before rounding: function floorp($val, $precision) { $half = 0.5

let str = 'abcdef'; // 0 str = str.slice(0);//返回整个字符串 abcdef str = str.substring(0);//返回整个字符串 abcdef str = str.substr(0);//返回整个字符串 abcdef // 使用一个参数 str = str.slice(2);//截取第二个之后所有的字符 cdef str = str.substring(2);//截取第二个之后所有的字符 cdef str = str.substr(2);//截取第二个之后所有的字符 cdef // 使用两个参数 str = str.slice(2,4);//截取第二个到第四个之间的字符 cd str = str.substring(2,4);//截取第二个到第四个之间的字符 cd str = str.substr(2,4);//截取从第3个开始往后数4位之间的字符 cdef // 使用两个负数 str = str.slice(1,-3);//截取第二个到第四个之间的字符 bc str = str.substring(1,-3);//截取第二个到第四个之间的字符 a #负数转换为0 str = str.substr(1,-3);//不能为负数，若强行传递负数，会被当成0处理 ' ' #负数转换为0 console.log(str) 来源：

可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效，请关闭广告屏蔽插件后再试): 问题: I want to extend the Form validation class to support array form elements like described here for L3 in L4. First, I changed the Validator alias with this in my app/config/app.php : 'Validator' => 'app\lib\Support\Facades\Validator', Then , I saved these codes as app/lib/Support/Facades/Validator.php <?php namespace app\lib\Support\Facades; class Validator extends \Illuminate\Support\Facades\Validator { public function __call($method, $parameters) { if (substr($method, -6) === '_array') { $method = substr($method, 0, -6); $values =

一、DVWA-SQL Injection(Blind)测试分析 SQL盲注 VS 普通SQL注入 ： 普通SQL注入 SQL盲注 1.执行SQL注入攻击时，服务器会响应来自数据库服务器的错误信息，信息提示SQL语法不正确等 2.一般在页面上直接就会显示执行sql语句的结果 1.一般情况，执行SQL盲注，服务器不会直接返回具体的数据库错误or语法错误，而是会返回程序开发所设置的特定信息（也有特例，如基于报错的盲注） 2.一般在页面上不会直接显示sql执行的结果 3.有可能出现不确定sql是否执行的情况 根据页面不同的响应方式，SQL盲注分为：基于布尔的盲注、基于时间的盲注、基于报错的盲注。 SQL盲注-测试思路 对于 基于布尔的盲注 ，可通过构造真or假判断条件（数据库各项信息取值的大小比较，如：字段长度、版本数值、字段名、字段名各组成部分在不同位置对应的字符ASCII码...），将构造的sql语句提交到服务器，然后根据服务器对不同的请求返回不同的页面结果（True、False）；然后不断调整判断条件中的数值以逼近真实值，特别是需要关注响应从True<-->False发生变化的转折点。 对于 基于时间的盲注 ，通过构造真or假判断条件的sql语句，且sql语句中根据需要联合使用sleep()函数一同向服务器发送请求，观察服务器响应结果是否会执行所设置时间的延迟响应

可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效，请关闭广告屏蔽插件后再试): 问题: I have a website in ASP.NET. After page load, I am getting below error. Error: Load denied by X-Frame-Options: http://www.youtube.com/v/lgZBsWGaQY0&feature does not permit cross-origin framing. Due to this error, youtube video is not able to open in iframe. Please provide some solution for this error. 回答1: Original URL in Query http://www.youtube.com/v/lgZBsWGaQY0&feature Expected URL http://www.youtube.com/embed/lgZBsWGaQY0?autoplay=1 回答2: YouTube Urls must be cleaned and normalized before inserting them into an iframe. Here is my Common js

可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效，请关闭广告屏蔽插件后再试): 问题: How do I get the last segment of a url? I have the following script which displays the full url of the anchor tag clicked: $(".tag_name_goes_here").live('click', function(event) { event.preventDefault(); alert($(this).attr("href")); }); If the url is http://mywebsite/folder/file how do I only get it to display the "file" part of the url in the alert box? 回答1: You can also use the lastIndexOf() function to locate the last occurrence of the / character in your URL, then the substr() function to return the substring starting from that location: