strtotime

I am working on a script that will import some data from a CSV file. As I am doing this I want to be able to check a variable to see if it is a valid date string. I have seen several ways to check if a sting is a date, but most of them require you to now the format. I will not know the format that the date will in. right now I am using strtotime(), but this fails to easily $field ="May"; if(strtotime($field)){ echo "This is a date"; } In this case, "May" was the persons first name, and not a date at all. Can any one recommend more reliable function? Edit based on questions from some of you.

My code works fine if the times are AM to PM (Ex: 11 AM - 10 PM), but if the locations hours of operation are AM to AM (Ex: 9 AM - 1 AM) it breaks. Here is my code: $datedivide = explode(" - ", $day['hours']); //$day['hours'] Example 11:00 AM - 10:00 PM $from = ''.$day['days'].' '.$datedivide[0].''; $to = ''.$day['days'].' '.$datedivide[1].''; $date = date('l g:i A'); $date = is_int($date) ? $date : strtotime($date); $from = is_int($from) ? $from : strtotime($from); $to = is_int($to) ? $to : strtotime($to); if (($date > $from) && ($date < $to) && ($dateh != 'Closed')) { ?> <script type="text

I have a form in which date format is dd/mm/yyyy . For searching database , I hanverted the date format to yyyy-mm-dd . But when I echo it, it showing 1970-01-01 . The PHP code is below: $date1 = $_REQUEST['date']; echo date('Y-m-d', strtotime($date1)); Why is it happening? How can I format it to yyyy-mm-dd ? Replace / with - : $date1 = strtr($_REQUEST['date'], '/', '-'); echo date('Y-m-d', strtotime($date1)); January 1, 1970 is the so called Unix epoch. It's the date where they started counting the Unix time . If you get this date as a return value, it usually means that the conversion of

This question already has an answer here: Convert one date format into another in PHP 15 answers I have this string: "13/10 15:00" and I would like to convert it to timestamp but when I do this: $timestamp = strtotime("13/10 15:00"); It returns an empty value. In your code strtotime() is attempting to convert 13/10 as the tenth day of the 13th month, which returns an error. If you want to parse a date string with a custom format, it's better to use DateTime::createFromFormat() instead: $dtime = DateTime::createFromFormat("d/m G:i", "13/10 15:00"); $timestamp = $dtime->getTimestamp();

Is there a way to use strtotime to add working days (Monday to Friday) to a date? Or some other method? What I want to do is: date ( 'Y-m-j' , strtotime ( '+3 working days' ) ) If you are limiting to weekdays use the string weekdays. echo date ( 'Y-m-j' , strtotime ( '3 weekdays' ) ); This should jump you ahead by 3 weekdays, so if it is Thursday it will add the additional weekend time. Source: http://www.php.net/manual/en/datetime.formats.relative.php I have found this buggy when needing a larger amount of weekdays. I was looking for X amount of business days after the 1st of the current

I have a variable called $effectiveDate containing the date 2012-03-26 . I am trying to add three months to this date and have been unsuccessful at it. Here is what I have tried: $effectiveDate = strtotime("+3 months", strtotime($effectiveDate)); and $effectiveDate = strtotime(date("Y-m-d", strtotime($effectiveDate)) . "+3 months"); What am I doing wrong? Neither piece of code worked. Change it to this will give you the expected format: $effectiveDate = date('Y-m-d', strtotime("+3 months", strtotime($effectiveDate))); I assume by "didn't work" you mean that it's giving you a timestamp instead

The DateTime class sure has some handy methods and seems overall superior to the native PHP date functions like strtotime , mktime and strftime (and more). But is there any drawback or a reason why I shouldn't use it ? The only reason I can think of is that it might be more expensive to create a whole instance of a class than just using a function. Would you agree with that ? Does it make sense at all to use a DateTime object for simple stuff? Are there any other drawbacks ? It seems a bit confusing to switch between those two options all the time, so I'd like to have clearance what I should

I want to add 3 minutes to a date/time variable I have, but I'm not sure how to do this. I made the variable from a string like this: (which is in the RFC 2822 date format btw) $date = 2011-10-18T19:56:00+0200 I converted that string into date using this command: $time = date_format(DateTime::createFromFormat("Y-m-d\TH:i:sO", $date), "G:i") Now, I'd like to add 3 minutes to that variable, but I I'm not sure how. I've used the following command in my script before, but that applies to the current date/time, so I'm not sure how to use that for my time variable: $currenttime = date('G:i',