stream

Which algorithm use sorted method in Stream interface [closed]

时光怂恿深爱的人放手 提交于 2020-12-11 00:50:09
问题 Closed. This question needs debugging details. It is not currently accepting answers. Want to improve this question? Update the question so it's on-topic for Stack Overflow. Closed 4 years ago . Improve this question When I print the values in the sorted method, Stream.of("d", "a", "b", "e", "c", "f") .sorted((s1, s2) -> { System.out.printf("sort: %s - %s\n", s1, s2); return s1.compareTo(s2); }).forEach(System.out::println); The output is as follows; sort: a - d sort: b - a sort: b - d sort:

Which algorithm use sorted method in Stream interface [closed]

浪子不回头ぞ 提交于 2020-12-11 00:46:53
问题 Closed. This question needs debugging details. It is not currently accepting answers. Want to improve this question? Update the question so it's on-topic for Stack Overflow. Closed 4 years ago . Improve this question When I print the values in the sorted method, Stream.of("d", "a", "b", "e", "c", "f") .sorted((s1, s2) -> { System.out.printf("sort: %s - %s\n", s1, s2); return s1.compareTo(s2); }).forEach(System.out::println); The output is as follows; sort: a - d sort: b - a sort: b - d sort:

How to parse items from a large JSON stream in JavaScript?

ε祈祈猫儿з 提交于 2020-12-09 04:43:14
问题 So I have downloaded the Wikidata JSON dump and it's about 90GB, too large to load into memory. It consists of a simple JSON structure like this: [ item, item, item, ... ] Each "item" looks something like this: { "type": "item", "id": "Q23", "labels": { "<lang>": obj }, "descriptions": { "<lang>": { "language": "<lang>", "value": "<string>" }, }, "aliases": { "<key>": [ obj, obj, ], }, "claims": { "<keyID>": [ { "mainsnak": { "snaktype": "value", "property": "<keyID>", "datavalue": { "value":

How to parse items from a large JSON stream in JavaScript?

那年仲夏 提交于 2020-12-09 04:42:16
问题 So I have downloaded the Wikidata JSON dump and it's about 90GB, too large to load into memory. It consists of a simple JSON structure like this: [ item, item, item, ... ] Each "item" looks something like this: { "type": "item", "id": "Q23", "labels": { "<lang>": obj }, "descriptions": { "<lang>": { "language": "<lang>", "value": "<string>" }, }, "aliases": { "<key>": [ obj, obj, ], }, "claims": { "<keyID>": [ { "mainsnak": { "snaktype": "value", "property": "<keyID>", "datavalue": { "value":

How do I get Zlib to uncompress from S3 stream in Ruby?

心已入冬 提交于 2020-12-05 11:11:32
问题 Ruby Zlib::GzipReader should be created passing an IO-like object (must have a read method that behaves same as the IO#read ). My problem is that I can't get this IO-like object from AWS::S3 lib. As far as I know, the only way of having a stream from it is passing a block to S3Object#stream . I already tried: Zlib::GzipReader.new(AWS::S3::S3Object.stream('file', 'bucket')) # Wich gaves me error: undefined method `read' for #<AWS::S3::S3Object::Value:0x000000017cbe78> Does anybody know how can

How do I get Zlib to uncompress from S3 stream in Ruby?

喜欢而已 提交于 2020-12-05 11:09:42
问题 Ruby Zlib::GzipReader should be created passing an IO-like object (must have a read method that behaves same as the IO#read ). My problem is that I can't get this IO-like object from AWS::S3 lib. As far as I know, the only way of having a stream from it is passing a block to S3Object#stream . I already tried: Zlib::GzipReader.new(AWS::S3::S3Object.stream('file', 'bucket')) # Wich gaves me error: undefined method `read' for #<AWS::S3::S3Object::Value:0x000000017cbe78> Does anybody know how can