stream

问题 I have a simple python program: test.py: import time for i in range(100000): print i time.sleep(0.5) I want to use another program that executes the above one in order to read the last line output while the above program is counting. import subprocess process = subprocess.Popen("test",stdout=PIPE) sleep(20) # sleeps an arbitrary time print stdout.readlines()[-1] The problem is that process.stdout.readlines() waits until test.py finishes execution. Is there any way to read the last line that

问题 I have a simple python program: test.py: import time for i in range(100000): print i time.sleep(0.5) I want to use another program that executes the above one in order to read the last line output while the above program is counting. import subprocess process = subprocess.Popen("test",stdout=PIPE) sleep(20) # sleeps an arbitrary time print stdout.readlines()[-1] The problem is that process.stdout.readlines() waits until test.py finishes execution. Is there any way to read the last line that

问题 I noticed that Stream is deprecated in Scala 2.13 and they suggest using LazyList . They also say "Use LazyList (which is fully lazy) instead of Stream (which has a lazy tail only)". What does it exactly mean ? Why did they deprecate Stream ? 回答1: NthPortal, a contributor to LazyList , states in Update and improve LazyList docs #7842 The key difference between LazyList and Stream - and its key feature - is that whether or not it is lazy is evaluated lazily. I'm not sure how best to convey

问题 I noticed that Stream is deprecated in Scala 2.13 and they suggest using LazyList . They also say "Use LazyList (which is fully lazy) instead of Stream (which has a lazy tail only)". What does it exactly mean ? Why did they deprecate Stream ? 回答1: NthPortal, a contributor to LazyList , states in Update and improve LazyList docs #7842 The key difference between LazyList and Stream - and its key feature - is that whether or not it is lazy is evaluated lazily. I'm not sure how best to convey

问题 So I'm currently trying to stream my microphone input from my raspberry pi (rasbian) to some sort of network stream in order to receive it later on my phone. In order to do this I use arecord -D plughw:1,0 -f dat -r 44100 | top pipe the soundstream from my usb-microphone to stdout which works fine as far as I can see but I needed it to be a bit louder so I can understand people standing far away from it . So i piped it to the sox play command like this : arecord -D plughw:1,0 -f dat -r 44100|

问题 I'm using some LLVM tools (like llvm-nm ) as static libraries. I.e. i copied source llvm-nm.cpp, renamed main(..) to llvm_nm(..) and compiled it as static library. I'd like to forward standard output to my file. I've tried to use the next approach: int out_fd, err_fd; fpos_t out_pos, err_pos; // redirect out fflush(stdout); fgetpos(stdout, &out_pos); out_fd = dup(fileno(stdout)); freopen(outFilename, "w", stdout); // execute int ret = llvm_nm(argc_, argv_); // restore output fflush(stdout);

问题 I want to read from a stream then encrypt it and finally write it to another file. This is my code: var fs = require('fs'); var crypto = require('crypto'); var infile = fs.createReadStream('a.dmg'); var outfile = fs.createWriteStream('b.dmg'); var encrypt = crypto.createCipher('aes192', 'behdad'); var size = fs.statSync('a.dmg').size; console.log(size); infile.on('data',function(data) { var percentage = parseInt(infile.bytesRead) / parseInt(size); console.log(percentage * 100); var encrypted

问题 I am using the stream API of Twitter (through tweepy) to collect tweets matching certain criteria, but when I use json.loads() to parse the created jsonl file I get this following error: File "twitter_time_series.py", line 19, in <module> tweet = json.loads(line) File "C:\Program Files\Anaconda3\lib\json\__init__.py", line 319, in loads return _default_decoder.decode(s) File "C:\Program Files\Anaconda3\lib\json\decoder.py", line 339, in decode obj, end = self.raw_decode(s, idx=_w(s, 0).end())

问题 Closed. This question needs debugging details. It is not currently accepting answers. Want to improve this question? Update the question so it's on-topic for Stack Overflow. Closed 4 years ago . Improve this question When I print the values in the sorted method, Stream.of("d", "a", "b", "e", "c", "f") .sorted((s1, s2) -> { System.out.printf("sort: %s - %s\n", s1, s2); return s1.compareTo(s2); }).forEach(System.out::println); The output is as follows; sort: a - d sort: b - a sort: b - d sort:

问题 Closed. This question needs debugging details. It is not currently accepting answers. Want to improve this question? Update the question so it's on-topic for Stack Overflow. Closed 4 years ago . Improve this question When I print the values in the sorted method, Stream.of("d", "a", "b", "e", "c", "f") .sorted((s1, s2) -> { System.out.printf("sort: %s - %s\n", s1, s2); return s1.compareTo(s2); }).forEach(System.out::println); The output is as follows; sort: a - d sort: b - a sort: b - d sort: