startup

问题 I have problem with starting WPF app based on MahApps style on others computers than my. I'm installing my app via Inno Setup. When I run .exe on my computer/computer with visual studio 2015 or sometimes on others computer, the application starts correctly. But when I install application on virtual machine which have just vs2008 + .Net or some others computers the application doesn't start. I can find the .exe in Task Menager, but no window is shown. The best is that I install two WPF

问题 I'm trying to launch a faceless server application with it's associated project using shell script on OSX 10.10.4. The shell script has been set to executable. On Startup nothing happens to launch Wakanda\ Server.app/Contents/MacOS/Wakanda\ Server. Please help me make this work. The shell script is at: Macintosh HD:Library:StartupItems:DispatchStartup:DispatchStartup.sh The contents of this shell script is: #!/bin/sh . /etc/rc.common # The start subroutine StartService() { # Insert your start

问题 I'm developing an application and a library using SourceryGpp lite for arm. I'm not using standard libs or default start files. So to call the global ctrs i'm doing to following code: ldr r0,=__ctors_init__ ldr r0,[r0] mov lr,pc bx r0 So the problem is that I'm defining some global instances in the static library, but the their ctors are never called by the above code. The weird thing is that the global ctors of the application are successfully called, anyone knows why? 回答1: This is a well

问题 I'm working with the latest version of android maven plugin. I use android:deploy and android:run to launch my app on my device. When I want to debug, I go into DDMS in eclipse and check the green bug icon for my app. Everything works fine... but I can only debug a running app, ie it has already started. If I put a breakpoint in my application constructor or onCreate, it wont stop (obviously because the application has started and the debugging didn't been activated... yet). So my question is

问题 This question already has an answer here : Closed 6 years ago . Possible Duplicate: running a qt application at startup How can I run a qt program at startup so that the user won't see the desktop at all? I am building my program in linux and I want to distribute it to linux users. I want to add that code to my app, because the customers don't have any understanding about linux. I found that QSettings can do that, is it true? What about QService ? Can we use a simple code like this? QSettings

问题 So here I got this little program which everyone obviously understands. include <iostream> include <fstream> using namespace std; int main () { ofstream myfile; myfile.open ("example.txt"); myfile << "Writing this to a file.\n"; myfile.close(); return 0; } This program works just fine, however, the problem is that if I have added it to run on windows start up(in registries SOFTWARE\\Microsoft\\Windows\\CurrentVersion\\Run ), the programs starts fine, but it does not create example.txt file.

问题 Is it currently possible to set a specific file to open on startup in VSCode? I have the 'To Do Tasks' extension installed and I want to open my TODO file by default each time I load VSCode. Using Version 1.12.1 回答1: You can either create some shortcut for command "code path/to/file.todo" or change link's options. For example(windows): link => properties => shortcut => target => "C:\Program Files (x86)\Microsoft VS Code\Code.exe" "D:/howto.todo" vscode command-line 来源： https://stackoverflow

问题 I am using Spring 3.2 DispatcherServlet . I am looking for an initialization hook that takes place after the DispatcherServlet initialization completes; either a standard Spring solution or servlet solution. Any suggestions? As a point of reference, the final logging statements after servlet startup follow. I want my initialization method to execute right after the configured successfully log statement. DEBUG o.s.w.s.DispatcherServlet - Published WebApplicationContext of servlet

问题 I'm developing an phonegap-based android app, and I'm writing code to handle notifications. Here is a snippet of the piece of code which is supposed to raise the notification: Intent notificationIntent = new Intent(context, MainActivity.class); // set intent so it does not start a new activity notificationIntent.setFlags(Intent.FLAG_ACTIVITY_CLEAR_TOP | Intent.FLAG_ACTIVITY_SINGLE_TOP); PendingIntent intent = PendingIntent.getActivity(context, 0, notificationIntent, 0); notification

问题 By following the Inno Setup KB: Create shortcuts in the Startup (or Autostart) group. I have these lines: [Setup] ... PrivilegesRequired=admin [Icons] Name: "{commonstartup}\app"; Filename: "app.exe" However on startup, it says "access denied". Looks like it is not run as administrator. What should I do? 回答1: If I understand your question correctly, your application requires to be run with elevated privileges. You cannot use the ancient "Startup" folder method to run applications with