startup

MongoDB Failing to Start - ***aborting after fassert() failure

懵懂的女人 提交于 2019-12-28 14:30:48
问题 I am new to Ubuntu (Linux tbh). I encountered problem with starting MongoDB service. I want to created web app using Ruby on Rails and MongoDB but mongo seems to fail to start. I followed this MongoDB installation on Ubuntu all of installation went without problems until I got to sudo service mongod start mongod.log 2016-01-01T10:58:15.545+0000 I CONTROL ***** SERVER RESTARTED ***** 2016-01-01T10:58:15.548+0000 I CONTROL [initandlisten] MongoDB starting : pid=3868 port=27017 dbpath=/var/lib

makefile的一个错误:*** missing separator

旧街凉风 提交于 2019-12-28 07:09:48
原文转自:http://blog.sina.com.cn/s/blog_87c063060101c9yp.html 1、在写 多目录下makefile的时候,碰到一个错误提示,让我纠结许久,后面还是解决了,这个错误不容易被发现。 2、错误提示如下: Makefile:8: *** missing separator (did you mean TAB instead of 8 spaces?). Stop. 3、先来说一下我想干什么,有些什么? 想干什么: 搭建一个Linux LCD的裸机开发环境,注意是多目录下面的,想写 一个比较通用的makefile。 有什么:父目录①←子目录①(build目录)、子目录①(code目录) 子目录①(build目录)←Makefile make.rule 子目录①(code目录)← 子目录②(startup)、子目录②(lib)、子目录②(foo)、子目录②(huge) 如下图: 1.工程目录下: 2.build 目录下 3.code目录下 4.code目录下的子目录都有2个子目录: src目录(存放.c文件) 、 include目录(存放.h文件) 5、下面贴一下makefile的内容 a. build下面的make.rule: .PHONY:all clean CC = arm-linux-gcc LD = arm-linux-ld AR

Keep meteor running on amazon EC2

只谈情不闲聊 提交于 2019-12-28 06:39:51
问题 I have a simple meteor app that I'm running on an Amazon EC2 server. Everything is working great. I start it manually with my user via meteor in the project directory. However, what I would like is for this app to Run on boot Be immune to hangups I try running it via nohup meteor & , but when I try to log out of the EC2 instance, I get the "You have running jobs" message. Continuing to log out stops the app. How can I get the app to start on startup and stay up (unless it crashes for some

Script running in PyCharm but not from the command line

我怕爱的太早我们不能终老 提交于 2019-12-28 04:01:14
问题 When I try to run my program from the PyCharm IDE everything works fine but if I type in Fedora: python myScript.py in a shell prompt I get an import error from 1 of the module. ImportError : No modue named myDependency What does PyCharm do that allows the interpreter to find my dependencies when launched from the IDE? How can I get my script to find its dependencies so it can be launched with a singe command? 回答1: There are a few possible things that can be causing this: The same python

Linux安装Tomcat7

一曲冷凌霜 提交于 2019-12-27 17:47:11
linux版本:CentOS 6.2 iso文件下载地址: http://mirrors.163.com/centos/6.2/isos/i386/CentOS-6.2-i386-bin-DVD1.iso 1. 安装 JDK 先用java命令查看系统是否安装了默认的openJDK,如果已安装,建议用yum remove java卸载之。 下载jdk: wget –c http://download.oracle.com/otn-pub/java/jdk/7u5-b05/jdk-7u5-linux-i586.rpm 安装:rpm –ivh jdk-7u5-linux-i586.rpm 配置环境变量(等到tomcat安装好之后一起配置) 2. 安装 tomcat Tomca下载地址: http://apache.etoak.com/tomcat/tomcat-7/v7.0.28/bin/apache-tomcat-7.0.28.tar.gz 下载后解压:tar -zxvf apache-tomcat-7.0.28 移动到/usr/local/tomcat7:mv apache-tomcat-7.0.28 /usr/local/tomcat7 设置目录可执行权限 chmod +x /usr/local/tomcat7 配置环境变量 编辑profile文件:vim /etc/profile

Run C# application at Windows startup?

℡╲_俬逩灬. 提交于 2019-12-26 23:12:43
问题 It's all the day that I'm trying to implement a startup feature into my project. I used Registry key: //Computer\HKEY_LOCAL_MACHINE\SOFTWARE\WOW6432Node\Microsoft\Windows\CurrentVersion\Run (Administrator Rights) I used Registry key: //Computer\HKEY_LOCAL_MACHINE\SOFTWARE\Microsoft\Windows\CurrentVersion\Run (Administrator Rights) The code work but when I restart the computer nothing happens. This is the code I used. RegistryKey registryKey = Registry.LocalMachine.OpenSubKey("SOFTWARE\

Run C# application at Windows startup?

非 Y 不嫁゛ 提交于 2019-12-26 23:09:34
问题 It's all the day that I'm trying to implement a startup feature into my project. I used Registry key: //Computer\HKEY_LOCAL_MACHINE\SOFTWARE\WOW6432Node\Microsoft\Windows\CurrentVersion\Run (Administrator Rights) I used Registry key: //Computer\HKEY_LOCAL_MACHINE\SOFTWARE\Microsoft\Windows\CurrentVersion\Run (Administrator Rights) The code work but when I restart the computer nothing happens. This is the code I used. RegistryKey registryKey = Registry.LocalMachine.OpenSubKey("SOFTWARE\

Linux配置tomcat自动启动

半腔热情 提交于 2019-12-26 20:29:13
请自行下载安装配置tomcat的服务器环境 切换到tomcat/bin目录下 用vi startup.sh文件 然后再startup.sh的文件开头的地方添加如下内容 #chkconfig: 2345 80 90 #description:tomcat auto start #processname: tomcat 保存退出 先按esc 然后按:键盘 接这个输入wq即可保存退出 编辑catalina.sh文件 vi catalina.sh 然后直接输入./ 出现/符号 然后输入export按回车开始搜索export 定位位置 然后添加环境变量 export CATALINA_BASE=/home/test/tomcatexport CATALINA_HOME=/home/test/tomcatexport CATALINA_TMPDIR=/home/test/tomcat/home/test/tomcat为tomcat的安装目录 保存退出 先按esc 然后按:键盘 接这个输入wq即可保存退出 然后添加连接 ln -s /home/test/tomcat/bin/startup.sh /etc/rc.d/init.d/tomcat7 通过上面的命令将startup.sh文件连接到init.d目录下名称为tomcat7 然后切换到/etc/rc.d/init.d/目录

Android - Service does not start

心已入冬 提交于 2019-12-25 11:50:35
问题 I am making app for me and my class mates, that checks for new homeworks and exams. It has service that may not be killed beacuse of checking school server (like every 5 minutes) for changed size of file with list of exams and stuff like this. I tried following code: MayinActivity.java package com.test.simpleservice; import android.app.ActivityManager; import android.support.v7.app.AppCompatActivity; import android.os.Bundle; import android.view.View; import android.widget.Button; import java

When window is split on startup, how to open the file on the right side?

拜拜、爱过 提交于 2019-12-25 08:17:03
问题 How do I open a file foo, associated with a major mode (in this case python, so it's a foo.py), on the right side of a split window (and the window is split only for this major mode)? The following code doesn't work at all (it displays the scratch buffer on both sides). (defun my-eval-after-load-python() (split-window-horizontally) ) (eval-after-load "python" '(my-eval-after-load-python)) 回答1: For setting up a particular major-mode that matches a file name or file extension, see the variable