sorting

问题 I am trying to implement a function that will sort an array of strings in lexical order (case-insensitive). But with one exception: if the string is equal to, let's say, "bingo!" put this line on top. I made some function which works well on the given test data. But I'm not sure I don't fool myself with special case. Please check me. <?php $a = [ 'alfa', 'beta', 'gama', 'sigma', 'foo', 'bar', 'bingo!', ]; usort($a, function ($a, $b) { $cmp = strcasecmp($a, $b); return $cmp == 0 ? 0 :

问题 I am trying to implement a function that will sort an array of strings in lexical order (case-insensitive). But with one exception: if the string is equal to, let's say, "bingo!" put this line on top. I made some function which works well on the given test data. But I'm not sure I don't fool myself with special case. Please check me. <?php $a = [ 'alfa', 'beta', 'gama', 'sigma', 'foo', 'bar', 'bingo!', ]; usort($a, function ($a, $b) { $cmp = strcasecmp($a, $b); return $cmp == 0 ? 0 :

问题 How do I remove a specific row from a matrix, keeping the same order? Example: 1 1 1 2 2 2 3 3 3 Let's say I need to remove the row with all even elements, so after deleting it should look like: 1 1 1 3 3 3 I tried writing code myself, (condition not the same as i mentioned above!) but it doesn't actually work properly: for (i = 0 ; i < no_of_rows ; i++) { if (abs(prosjeci[i] - prosjek) < 0.1) { /* condition */ for (k = i ; k < no_of_rows - 1 ; k++) { for (j = 0 ; j < no_of_columns ; j++) {

问题 I have been trying to understand how sorting using Comparable works. I have class Activity implementing Comparable interface. I am trying to understand how activity.finish-this.finish; sorts in descending order and how this.finish-activity.finish sorts in ascending order. I am confused about what to use first for sorting in ascending and descending? class Activity implements Comparable { int start; int finish; public Activity(int start, int finish) { this.start = start; this.finish = finish;

问题 This question already has answers here : How do you split a list into evenly sized chunks? (63 answers) Closed 6 years ago . Is there an easy way to convert a 1D list into a 2D list with a given row length? Suppose I have a list like this: myList = [1, 2, 3, 4, 5, 6, 7, 8, 9] I want to convert the above list into a 3 x 3 table like below: myList = [[1,2,3],[4,5,6],[7,8,9]] I know I can accomplish this by creating a new 2D list called myList2 and inserting the element into MyList2 using 2

问题 So I have to make a method which is using the quicksort as a sort algorithm without using the Java API. Then I have to write another method that gives the sorted array back and using the binary search return true if the searched element is found in it. I have no idea where am I making the stupid mistake. public class Aufgabe1 { public static void sort(int[] array) { /* TODO: add code here */ sort(array, 0, array.length - 1); } public static void sort(int[] array, int start, int end) { int i =

问题 I have an array that looks something like this: array( array('foo' => true), array('foo' => false), array('foo' => true), array('foo' => true), array('foo' => false) ) Is there a simple way to bring all the arrays where foo == true to the top? 回答1: Just use the uasort() function to order your array: $arr = array( array('foo' => true), array('foo' => false), array('foo' => true), array('foo' => true), array('foo' => false) ); function sortit($a, $b) { if($a['foo'] === $b['foo']) { return 0; }

问题 I have a column in a dataframe Fruits Apple Mango Banana Apple Mango Banana Apple Mango Grapes I want to sort this column by Frequency of the values occurring in it, So the dataframe now should be: Fruits Apple Apple Apple Banana Banana Banana Mango Mango Grapes Thanks! 回答1: Create a freq column and then sort by freq and fruit name. df.assign(freq=df.apply(lambda x: df.Fruits.value_counts()\ .to_dict()[x.Fruits], axis=1))\ .sort_values(by=['freq','Fruits'],ascending=[False,True]).loc[:,[

问题 I have a simple question about using binary search in the insertion sort algorithm. More precisely, at each step of the usual insertion sort, instead of linearly comparing the element with all the elements in the previous (sorted) subarray, we just use binary search in that sorted subarray to find the place where the element belongs. I know that this reduced the number of comparisons that the algorithm makes (O(log n) instead of O(n)), but the number of swaps needed at each step still

问题 This question already has answers here : Closed 9 years ago . Possible Duplicate: How do I sort unicode strings alphabetically in Python? As a citizen of the Rest-of-the-World, I'm really annoyed by the fact that computers aren't adapted by default to deal with international issues. Many sites still don't use Unicode and PHP is still in the Dark Ages. When I want to sort a list of words or names in romanian I always have to write my own functions, which are hardly efficient. There must be