sorting

OpenCV C++ how to know the number of contours per row for sorting?

最后都变了- 提交于 2021-02-10 12:36:12
问题 I have a binary image: In this image I can easily sort the contours that I found from top to bottom and from left to right using the overloaded std::sort . I first sort from top to bottom via: sort(contours.begin(), contours.end(), top_to_bottom_contour_sorter()); Then I sort from left to right by: for (int i = 0; i < contours.size(); i = i + no_of_contours_horizontally) { sort(i, i + no_of_contours_horizontally, left_to_right_contour_sorter); } Where top_to_bottom and left_to_right are

OpenCV C++ how to know the number of contours per row for sorting?

我怕爱的太早我们不能终老 提交于 2021-02-10 12:34:51
问题 I have a binary image: In this image I can easily sort the contours that I found from top to bottom and from left to right using the overloaded std::sort . I first sort from top to bottom via: sort(contours.begin(), contours.end(), top_to_bottom_contour_sorter()); Then I sort from left to right by: for (int i = 0; i < contours.size(); i = i + no_of_contours_horizontally) { sort(i, i + no_of_contours_horizontally, left_to_right_contour_sorter); } Where top_to_bottom and left_to_right are

sorting with two key= arguments

落花浮王杯 提交于 2021-02-10 12:12:29
问题 I want a case-insensitive sort of a tuple of records (lists) on two fields in each record. HowTo/Sorting tells me how to do case-insensitive ( key=str.lower ), and it tells me how to sort on two keys ( key=operator.itemgetter(0,1) ). I tried the following: parts = [ ('A',2,''), ('a',1,''), ('b',2,''), ('B',1,''), ] foo = sorted(parts, key=str.lower, key=operator.itemgetter(0,1)) print(foo) Python does not like two key= s in the same sorted . It says: SyntaxError: keyword argument repeated ,

Python “IndexError: string index out of range” (Beginner)

会有一股神秘感。 提交于 2021-02-10 12:10:36
问题 So for a Programming assignment we have to re write the sort function in python to sort a list of words. So far I have made it able to sort the words based of the first letter of each and now im trying to run recursion to still sort it if the first letters or any of the letters are the same. Im having problems with the "IndexError: string index out of range" error. What I have so far is def insertion_sort(bookwords): for index in range(1,len(bookwords)): global word word=bookwords[index] i

sorting with two key= arguments

为君一笑 提交于 2021-02-10 12:06:56
问题 I want a case-insensitive sort of a tuple of records (lists) on two fields in each record. HowTo/Sorting tells me how to do case-insensitive ( key=str.lower ), and it tells me how to sort on two keys ( key=operator.itemgetter(0,1) ). I tried the following: parts = [ ('A',2,''), ('a',1,''), ('b',2,''), ('B',1,''), ] foo = sorted(parts, key=str.lower, key=operator.itemgetter(0,1)) print(foo) Python does not like two key= s in the same sorted . It says: SyntaxError: keyword argument repeated ,

Sort a 2d array by the first column and then by the second one

[亡魂溺海] 提交于 2021-02-10 08:32:46
问题 int[][] arrs = {{1, 100}, {11, 22}, {1, 11}, {2, 12}}; Arrays.sort(arrs, (a, b) -> (a[0] - b[0])); Above array has been sorted as {1, 100} {1, 11} {2, 12} {11, 22} I want them to be sorted by a[0]-b[0] first and if a[0]=b[0] , then sort them by a[1]-b[1] . {1, 11} {1, 100} {2, 12} {11, 22} How to do that? 回答1: Essentially what you want to do is to compare the inner arrays lexicographically (like how words are ordered in a dictionary). Arrays.compare does exactly that. Arrays.sort(arrs, Arrays

Sort a 2d array by the first column and then by the second one

橙三吉。 提交于 2021-02-10 08:32:23
问题 int[][] arrs = {{1, 100}, {11, 22}, {1, 11}, {2, 12}}; Arrays.sort(arrs, (a, b) -> (a[0] - b[0])); Above array has been sorted as {1, 100} {1, 11} {2, 12} {11, 22} I want them to be sorted by a[0]-b[0] first and if a[0]=b[0] , then sort them by a[1]-b[1] . {1, 11} {1, 100} {2, 12} {11, 22} How to do that? 回答1: Essentially what you want to do is to compare the inner arrays lexicographically (like how words are ordered in a dictionary). Arrays.compare does exactly that. Arrays.sort(arrs, Arrays

How to sort latin after local language in python 3?

折月煮酒 提交于 2021-02-10 08:03:08
问题 There are many situations where the user's language is not a " latin " script (examples include: Greek, Russian, Chinese). In most of these cases a sorting is done by first sorting the special characters and numbers (numbers in local language though...), secondly the words in the local language-script at the end, any non native characters such as French, English or German "imported" words, in a general utf collation. Or even more specific for the rest...: is it possible to select the sort

How to sort latin after local language in python 3?

假装没事ソ 提交于 2021-02-10 08:01:49
问题 There are many situations where the user's language is not a " latin " script (examples include: Greek, Russian, Chinese). In most of these cases a sorting is done by first sorting the special characters and numbers (numbers in local language though...), secondly the words in the local language-script at the end, any non native characters such as French, English or German "imported" words, in a general utf collation. Or even more specific for the rest...: is it possible to select the sort

Is there a way to sort structs by multiple variables in C?

﹥>﹥吖頭↗ 提交于 2021-02-10 05:44:06
问题 I have to write a function that sorts structs in an array. the struct is: #define MAX_USERNAME_LENGTH 16 typedef struct{ char username[MAX_USERNAME_LENGTH]; unsigned int rides; unsigned int rank; } driver; The program load the data from a .txt file and fills an array driver driver_list[256] I have to sort driver_list by ranks AND number of rides. So if my file contains //user rides rank frank209 3 6 john76 7 6 harry99 2 2 bob77 5 2 Output must show: john76 7 6 frank209 3 6 bob77 5 2 harry99 2