sign | 易学教程

Is internet access needed for CA signed applet?

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问题 We coded a java applet and signed it through a Certificate Authority, Entrust. When the applet is deployed through any browser, we can see in java console logs that a request is made to the CA: network: Connecting http://ocsp.entrust.net/ with proxy=DIRECT security: OCSP Response: GOOD However, our client has some computers in an intranet without internet connection. So, is there a way to avoid any internet request to CA server? 回答1: You will find this option from Java Control Panel >>

Microsoft signtool removes administrative privileges?

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问题 I need to sign an installer executable for Windows using a p12 file. Before signing, this EXE file icon has a "shield icon" on it indicating that it requires administrative privileges, as it should. However, after I sign using the signtool and the following command: signtool.exe sign /f mycert.pfx /p <password> /t http://timestamp.verisign.com/scripts/timstamp.dll /v "<file to be signed>" the signing succeeds but the shield icon disappears. When I run the resulting executable, it fails

How to prevent minus sign when using DecimalFormat?

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问题 I am using a library that lets me configure the way numbers are formatted using a DecimalFormat pattern. I need to remove the minus symbol to show the absolute value of the numbers. I have tried both "0.00###;0.00###" and "0.00###;#" without success. I can choose any minus symbol (e.g. "0.00###;(0.00###)") but I can't have no sign at all? Thanks in advance for your suggestions, Tom 回答1: If you use "0.00###; 0.00###" (notice the space after the semicolon) the negative sign will not be

JS实现简易计算器的7种方法

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先放图（好吧比较挫）方法一：最容易版 <!DOCTYPE html> <html lang="zh-CN"> <head> <meta charset="UTF-8" /> <title>简易计算器</title> <style> body { background-color: #eee; } #calculator { margin: 100px 0 0 150px; } </style> </head> <body>  <div id="calculator"> <p> <input type="text" class="formerInput" value="1" /> <span class="sign">+</span> <input type="text" class="laterInput" value="1" /> <span>=</span> <span class="resultOutput">2</span> </p> <p> <input type="button" value="+" onclick="addHandler();" /> <input type="button" value="-" onclick="subtractHandler();" /> <input type="button" value="×"

(栈，BST) leetcode 224. Basic Calculator 173. Binary Search Tree Iterator

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开两个栈，一个记录数字，一个记录操作符。然后从前往后扫描整个表达式： 1. 如果遇到 (、+、-，直接入栈； 2. 如果遇到数字，则判断操作符栈的栈顶元素，如果不是 (，则弹出操作符的栈顶元素，并用相应操作更新数字栈的栈顶元素。从而保证操作符栈的栈顶最多有一个连续的+或-； 3. 如果遇到 )，此时操作符栈顶一定是 (，将其弹出。然后根据新栈顶的操作符，对数字栈顶的两个元素进行相应操作；时间复杂度分析：每个数字和操作进栈出栈一次，所以总时间复杂度是 O(n) class Solution { public: void calc(stack<char>& op, stack<int>& num){ int y = num.top(); num.pop(); int x = num.top(); num.pop(); if(op.top() == '+') num.push(x+y); else num.push(x-y); //这里一定是先进栈的x减去后进栈的y op.pop(); } int calculate(string s) { //s 中包含 ( ) + - 非负整数空格 // two stacks: one records numbers, one records operations stack<int> num; stack<char> op; for(int

Do modern compilers optimize multiplication by 1 and -1

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问题 If I write template<int sign> inline int add_sign(int x) { return sign * x; } template int add_sign<-1>(int x); template int add_sign<1>(int x); Are most C++ compilers smart enough to optimize the multiplication by 1 or -1 into some faster operation (no-op or negation)? 回答1: Yes. This is part of a class of simple optimizations known as arithmetic local optimizations. For example 1 * x can be simplified statically to x , likewise -1 * x can be simplified to -x . Production compilers all do

[CF484E]Sign on Fence

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题目大意：一个长度为$n$的数列，$m$次询问。每次询问$l\;r\;k$，表示在区间$[l,r]$内选一个长度为$k$的区间，求区间最小数的最大值题解：常见操作，开一棵主席树，比这一位大的就赋成$1$，否则为$0$，维护前缀$1$的个数，后缀$1$的个数和区间最长$1$的个数，二分答案判断一下就行了卡点：无 C++ Code： #include <cstdio> #include <algorithm> #define maxn 100010 #define N maxn * 20 int n, m; int v[maxn], rnk[maxn]; inline int min(int a, int b) {return a < b ? a : b;} inline int max(int a, int b) {return a > b ? a : b;} inline bool cmp(int a, int b) {return v[a] > v[b];} inline bool cmp1(int a, int b) {return a > b;} namespace Segment_Tree { struct node { int ml, mr, len, sz; node() {ml = mr = len = sz = 0;} node(int x) {ml =

CF484E Sign on Fence

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题意给定一个长度为n的数列，有m次询问，询问形如l r k 要你在区间[l,r]内选一个长度为k的区间，求区间最小数的最大值 Sol 二分答案怎么判定，每种数字开一棵线段树某个位置上的数大于等于它为1 那么就是求区间最大的1的序列长度大于k 二分的最优答案一定在这个区间内，否则不优排序后就是用主席树优化空间之前 $build$ 一下，因为区间有长度不好赋值 # include <bits/stdc++.h> # define RG register # define IL inline # define Fill(a, b) memset(a, b, sizeof(a)) using namespace std; typedef long long ll; const int _(1e5 + 5); const int __(2e6 + 5); IL int Input(){ RG int x = 0, z = 1; RG char c = getchar(); for(; c < '0' || c > '9'; c = getchar()) z = c == '-' ? -1 : 1; for(; c >= '0' && c <= '9'; c = getchar()) x = (x << 1) + (x << 3) + (c ^ 48); return x * z

可持续化线段树(例题Sign on Fence[Codeforces 484E])

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刚刚学习的想记录一下：第一次接触可持续化线段树，很懵。。。题目：题目描述 izon the Champion has recently finished painting his wood fence. The fence consists of a sequence of n panels of 1 meter width and of arbitrary height. The i -th panel's height is h i meters. The adjacent planks follow without a gap between them. After Bizon painted the fence he decided to put a "for sale" sign on it.The sign will be drawn on a rectangular piece of paper and placed on the fence so that the sides of the sign are parallel to the fence panels and are also aligned with the edges of some panels. Bizon the Champion introduced the following

AC日记——Sign on Fence Codeforces 484e

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E. Sign on Fence time limit per test 4 seconds memory limit per test 256 megabytes input standard input output standard output Bizon the Champion has recently finished painting his wood fence. The fence consists of a sequence of n panels of 1 meter width and of arbitrary height. The i -th panel's height is h i meters. The adjacent planks follow without a gap between them. After Bizon painted the fence he decided to put a "for sale" sign on it. The sign will be drawn on a rectangular piece of paper and placed on the fence so that the sides of the sign are parallel to the fence panels and are

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