scope

appdelegate shared instance delegate

天大地大妈咪最大 提交于 2020-01-02 07:29:12
问题 MyAppDelegate *appD; appD = [UIApplication sharedApplication]; if(appD.sw1.on) NSLog(@"It is ON"); else NSLog(@"It is OFF"); Gives no error while compiling. Runs without any warning, but it doesn't work. I dont see what the problem is. ... EDIT: OMG, should have called delegate method too: appD = (MyAppDelegate *)[[UIApplication sharedApplication] delegate]; 回答1: I recommend you this method to share the app delegate: https://coderwall.com/p/z4h4uw?i=2&p=1&q=&t%5B%5D=%21%21mine&t%5B%5D=%21

c - global variables in pthreads

有些话、适合烂在心里 提交于 2020-01-02 05:19:27
问题 Suppose I defined a function in file function.c, and in main.c I create multiple pthreads to execute the function in function.c. If in function.c, I define a global variable, for example, int foo; Then, my question is, does every thread has its own instance of this variable "foo" or do they share a single "foo"? 回答1: They share a single foo variable. Global variable always exists only once per process and is usually protected by mutex to avoid concurrent access. Since C11 you can use thread

Accessing outer scope from inner scope

不羁的心 提交于 2020-01-02 03:36:28
问题 I have a type that looks a little something like this: var x = function(){ this.y = function(){ } this.z = function(){ ... this.A = function(){ CALLING POINT } } } From calling point, I'm attempting to call function this.y. I don't need to pass any parameters, but when I set some stuff from this.A, I need to call this.y. Is this possible? I'm OK with passing extra parameters to functions to make it possible. 回答1: Is this possible? Yes, you can assign this reference to another variable and

Variable in a function

故事扮演 提交于 2020-01-02 03:30:11
问题 I have see the following code... The first call of (next-num) returns 1 , and the second returns 2 . (define next-num (let ((num 0)) (lambda () (set! num (+ num 1)) num))) (next-num) ; 1 (next-num) ; 2 What I can not understand is... num is created by let inside next-num , it is kind of a local variable... How does scheme know that each time next-num is called, the value of num is not erased by let ((num 0)) ; How does scheme know that it is always the same num that we modify whenever next

Python 3 - Class variable is not defined [duplicate]

痞子三分冷 提交于 2020-01-02 02:51:18
问题 This question already has answers here : Accessing class variables from a list comprehension in the class definition (5 answers) Closed 2 years ago . Here I'm not able to access the class variable inside a Python's list comprehension . class Student: max_year = 18 year_choice = [i for i in range(100) if i > max_year] def __init__(self, name): self.name = name print (self.year_choice) Student('Blah') But it's working fine in Python 2. ../workspace$ python student.py [19, 20, 21, 22, 2.... 99]

Why is locality determined at compile time?

ⅰ亾dé卋堺 提交于 2020-01-02 01:04:11
问题 This is a bit of a follow-up to this question. Why is locality determined at compile time and not at execution time? Is it purely for performance? Are there languages that look up their variables at execution time? I.e. every time a variable is accessed, this variable is first searched in the local scope and then the search escalates through all enclosing scopes? How do ECMA languages handle this? To put question 2 in other words: Are there languages where the following code (in the necessary

Why is locality determined at compile time?

时光怂恿深爱的人放手 提交于 2020-01-02 01:03:53
问题 This is a bit of a follow-up to this question. Why is locality determined at compile time and not at execution time? Is it purely for performance? Are there languages that look up their variables at execution time? I.e. every time a variable is accessed, this variable is first searched in the local scope and then the search escalates through all enclosing scopes? How do ECMA languages handle this? To put question 2 in other words: Are there languages where the following code (in the necessary

Pass in local variable to callback function [duplicate]

青春壹個敷衍的年華 提交于 2020-01-02 00:59:54
问题 This question already has answers here : JavaScript closure inside loops – simple practical example (44 answers) Closed 3 years ago . Question How can a callback function retain a local variable from whence it was created? Simple example I'm creating a video player. It will have sliders to control the saturation, contrast, and hue. When the user plays with the sliders, it needs to acknowledge which slider got changed and what value it got changed to. The problem is that the name of the slider

Javascript nested function losing scope

好久不见. 提交于 2020-01-01 12:11:12
问题 Can someone explains the scope binding of the following code please window.name = "window"; object = { name: "object", method: function() { nestedMethod: function() { console.log(this.name); } nestedMethod(); } } object.method(); // print 'window' I think my question is more about this ...why is this losing the scope and default to the global scope ? do all the anonymous functions that we created will go on the global scope ? 回答1: Whenever you call a function, simply by writing func() , this

Environment and scope when using parallel functions

北城余情 提交于 2020-01-01 10:58:13
问题 I have the following function: f1<-function(x){ iih_data<-...stuff... ...more stuff... cl <- makeCluster(mc <- getOption("cl.cores", 6)) clusterExport(cl, c("iih_data")) clusterEvalQ(cl, require(lme4)) Tstar<-parCapply(cl, ystar, function(x){ ostar=glmer(x ~ GENO + RACE + (1|GROUP), family="binomial",data=iih_data,nAGQ=1) fixef(ostar)[2]/sqrt(vcov(ostar)[2,2]) }) stopCluster(cl) ...more stuff... } But I get this error: Error in get(name, envir = envir) : object 'iih_data' not found I am