rounding

Round to 25, 50, 75, 100

拟墨画扇 提交于 2020-05-09 16:26:30
问题 I'm not a Math person so I'm having a hard time to come up with a calculation to round the decimals to 25, 50, 75 and 100. And this will not be the typical round off because the decimals will not be decreased but only increased. Example: if 11.12, round to 11.25 if 11.34, round to 11.50 if 11.52, round to 11.75 if 11.76, round to 12.00 Here's my starting method: public float RoundNearestCents(String price) { float srp; return srp; } 回答1: public float RoundNearestCents(double d) { return

PHP to round up to the 2nd decimal place

折月煮酒 提交于 2020-05-08 17:36:06
问题 By calculating areas I have a number which I need to display in a strange way. Always display 2 decimal places. Always round up the 2nd decimal place if the 3rd+ decimal places > 0. Examples: 0.5 = 0.50 0.500003 = 0.51 0.96531 = 0.97 0.96231 = 0.97 0.8701 = 0.88 Is there a built in function to do this in PHP or do I need to write one? 回答1: You can use 2 functions: round() - docs here: http://www.php.net/manual/en/function.round.php number_format() - docs here: http://ro1.php.net/number_format

PHP to round up to the 2nd decimal place

折月煮酒 提交于 2020-05-08 17:34:31
问题 By calculating areas I have a number which I need to display in a strange way. Always display 2 decimal places. Always round up the 2nd decimal place if the 3rd+ decimal places > 0. Examples: 0.5 = 0.50 0.500003 = 0.51 0.96531 = 0.97 0.96231 = 0.97 0.8701 = 0.88 Is there a built in function to do this in PHP or do I need to write one? 回答1: You can use 2 functions: round() - docs here: http://www.php.net/manual/en/function.round.php number_format() - docs here: http://ro1.php.net/number_format

PHP to round up to the 2nd decimal place

自闭症网瘾萝莉.ら 提交于 2020-05-08 17:33:03
问题 By calculating areas I have a number which I need to display in a strange way. Always display 2 decimal places. Always round up the 2nd decimal place if the 3rd+ decimal places > 0. Examples: 0.5 = 0.50 0.500003 = 0.51 0.96531 = 0.97 0.96231 = 0.97 0.8701 = 0.88 Is there a built in function to do this in PHP or do I need to write one? 回答1: You can use 2 functions: round() - docs here: http://www.php.net/manual/en/function.round.php number_format() - docs here: http://ro1.php.net/number_format

Euclidean Distance

匆匆过客 提交于 2020-04-21 05:02:14
问题 Hacker Rank - Weather Observation Station 19 Given a table STATION that holds data for five fields namely ID, CITY, STATE, NORTHERN LATITUDE and WESTERN LONGITUDE. +-------------+------------+ | Field | Type | +-------------+------------+ | ID | INTEGER | | CITY | VARCHAR(21)| | STATE | VARCHAR(2) | | LAT_N | NUMERIC | | LONG_W | NUMERIC | +-------------+------------+ Consider P1(a, b) and P2(c, d) be two points on 2D plane, where (a, b) be minimum and maximum values of Northern Latitude and

Euclidean Distance

廉价感情. 提交于 2020-04-21 05:02:10
问题 Hacker Rank - Weather Observation Station 19 Given a table STATION that holds data for five fields namely ID, CITY, STATE, NORTHERN LATITUDE and WESTERN LONGITUDE. +-------------+------------+ | Field | Type | +-------------+------------+ | ID | INTEGER | | CITY | VARCHAR(21)| | STATE | VARCHAR(2) | | LAT_N | NUMERIC | | LONG_W | NUMERIC | +-------------+------------+ Consider P1(a, b) and P2(c, d) be two points on 2D plane, where (a, b) be minimum and maximum values of Northern Latitude and

SQL Server - Round TIME values to the next minute

假装没事ソ 提交于 2020-04-13 05:54:10
问题 I've found many posts about rounding "down" time values (e.g. https://stackoverflow.com/a/6667041/468823), but I have another problem: I wanna round to the higher minute and not to the lower, how can I do? My code: SELECT PA.ORE AS TOT_HOURS, CAST(CAST(PA.ORA_INIZIO AS DATETIME) AS TIME) AS BEGIN_TIME, CAST(dateadd(minute, datediff(minute, 0, (CAST(PA.ORA_INIZIO AS DATETIME))), 0) AS TIME) AS BEGIN_TIME_ROUNDED FROM PRG_ATTIVITA PA INNER JOIN PRG_TIPI_ATTIVITA PTA ON PA.ID_TIPO_ATTIVITA = PTA

How to round to 2.5 in Java?

非 Y 不嫁゛ 提交于 2020-04-11 11:51:03
问题 So I am making a fitness app for android and now I am asking the user to input a number e.g. 72.5 I would take this number and take percentages of it and apply functions to this etc. I need to make sure that the percentage I take of that number is rounded to 2.5. This is because in a UK gym you only have the following plates: 1.25x2=2.5 2.5x2=5 5+2.5=7.5 , 10, 15, 20, 25 What I mean is that it would be numbers like these: 40, 42.5, 45, 47.5, 50 How can I round a Number N to the nearest 2.5? I

How to round to 2.5 in Java?

∥☆過路亽.° 提交于 2020-04-11 11:48:18
问题 So I am making a fitness app for android and now I am asking the user to input a number e.g. 72.5 I would take this number and take percentages of it and apply functions to this etc. I need to make sure that the percentage I take of that number is rounded to 2.5. This is because in a UK gym you only have the following plates: 1.25x2=2.5 2.5x2=5 5+2.5=7.5 , 10, 15, 20, 25 What I mean is that it would be numbers like these: 40, 42.5, 45, 47.5, 50 How can I round a Number N to the nearest 2.5? I

Round Specific Corners SwiftUI

梦想与她 提交于 2020-04-07 12:40:38
问题 I know you can use .cornerRadius() to round all the corners of a swiftUI view but is there a way to round only specific corners such as the top? 回答1: There are two options, you can use a View with a Path , or you can create a custom Shape . In both cases you can use them standalone, or in a .background(RoundedCorders(...)) Option 1: Using Path + GeometryReader (more info on GeometryReader: https://swiftui-lab.com/geometryreader-to-the-rescue/) struct ContentView : View { var body: some View {