rounding

问题 We found an interesting case in our business logic that totally breaks our logic and we don't understand why NSDecimalNumber and Decimal behaves the way it does. My playground for the cases is as follows: import Foundation let pQuantity = Decimal(string: "0.2857142857142857")! let pPrice = Decimal(string: "7.00000000000000035")! let calced = NSDecimalNumber(decimal: pQuantity * pPrice * Decimal(integerLiteral: 100)) // 200 let decimal = calced.decimalValue // 199

问题 I would like to solve rounding mechanism by using php4,5.2 and below (not 5.3) Currently I am doing 0.05 rounding, something like this page: http://www.bnm.gov.my/index.php?ch=209&pg=657&ac=568 before rounding | after rounding 89.90 | 89.90 89.91 | 89.90 89.92 | 89.90 89.93 | 89.95 89.94 | 89.95 89.95 | 89.95 89.96 | 89.95 89.97 | 89.95 89.98 | 90.00 89.99 | 90.00 I try to use string to split it out and manually do adding, but not really a good solution, hoping here can find someone to solve

问题 I want to shorten a number to the first significant digit that is not 0. The digits behind should be rounded. Examples: 0.001 -> 0.001 0.00367 -> 0.004 0.00337 -> 0.003 0.000000564 -> 0.0000006 0.00000432907543029 -> 0.000004 Currently I have the following procedure: if (value < (decimal) 0.01) { value = Math.Round(value, 4); } Note: numbers will always be positive the number of significant digits will always be 1 values larger 0.01 will always be rounded to two decimal places, hence the if <

问题 round function in jq doesn't work. $ jq '10.01 | round' jq: error: round/0 is not defined at <top-level>, line 1: 10.01 | round jq: 1 compile error $ jq --help jq - commandline JSON processor [version 1.5-1-a5b5cbe] What I need to do? 回答1: Seems like round is unavailable in your build. Either upgrade jq or implement round using floor : def round: . + 0.5 | floor; Usage example: $ jq -n 'def round: . + 0.5 | floor; 10.01 | round' 10 来源： https://stackoverflow.com/questions/56593531/jq-error

问题 I need a way to round a float to a given number of decimal places, but I want to always round down. For example, instead of >>> round(2.667, 2) 2.67 I would rather have >>> round_down(2.667, 2) 2.66 回答1: Something like this should work for whatever number of digits you want to do: >>> import math >>> def round_down(num,digits): factor = 10.0 ** digits return math.floor(num * factor) / factor >>> round_down(2.667,2) 2.66 回答2: You've got a friend in quantize and ROUND_FLOOR >>> from decimal

问题 I was wondering how to make avg in the following program round to 3 decimal places: public class BaseballCalculator { public static void main(String args[]) { Scanner myScanner = new Scanner(System.in); double atBats; double baseHits; double onBase; double avg; double onBasePercentage; System.out.println("How many atbats did you have? "); atBats = myScanner.nextDouble(); System.out.println("How many base hits and homeruns did you have? "); baseHits = myScanner.nextDouble(); System.out.println

问题 I was wondering how to make avg in the following program round to 3 decimal places: public class BaseballCalculator { public static void main(String args[]) { Scanner myScanner = new Scanner(System.in); double atBats; double baseHits; double onBase; double avg; double onBasePercentage; System.out.println("How many atbats did you have? "); atBats = myScanner.nextDouble(); System.out.println("How many base hits and homeruns did you have? "); baseHits = myScanner.nextDouble(); System.out.println

问题 I often end up in situations where it is necessary to check if the obtained difference is above machine precision. Seems like for this purpose R has a handy variable: .Machine$double.eps . However when I turn to R source code for guidelines about using this value I see multiple different patterns. Examples Here are a few examples from stats library: t.test.R if(stderr < 10 *.Machine$double.eps * abs(mx)) chisq.test.R if(abs(sum(p)-1) > sqrt(.Machine$double.eps)) integrate.R rel.tol < max(50*

问题 I often end up in situations where it is necessary to check if the obtained difference is above machine precision. Seems like for this purpose R has a handy variable: .Machine$double.eps . However when I turn to R source code for guidelines about using this value I see multiple different patterns. Examples Here are a few examples from stats library: t.test.R if(stderr < 10 *.Machine$double.eps * abs(mx)) chisq.test.R if(abs(sum(p)-1) > sqrt(.Machine$double.eps)) integrate.R rel.tol < max(50*

问题 I'm not a Math person so I'm having a hard time to come up with a calculation to round the decimals to 25, 50, 75 and 100. And this will not be the typical round off because the decimals will not be decreased but only increased. Example: if 11.12, round to 11.25 if 11.34, round to 11.50 if 11.52, round to 11.75 if 11.76, round to 12.00 Here's my starting method: public float RoundNearestCents(String price) { float srp; return srp; } 回答1: public float RoundNearestCents(double d) { return