rounding

问题 I have results of an "on the fly" calculation that end in decimal values (after converted using money_format) as follows: $cost_per_trans = 0.0000000476 $cost_per_trans = 0.0000007047 The corresponding values before the money_format are: 4.7564687975647E-8 7.0466204408366E-7 These values may be of different lengths but I would like to be able to round them to the last 2 digits after the string of "0s", to get this for example: $cost_per_trans = 0.000000048 $cost_per_trans = 0.00000070 I am

问题 How to round off a float value if the value is like: eg: 1.0 ==> then it should return 1 2.0 ==> then it should return 2 but if the value is like: 1.2 ==> then it should return 1.2 1.90 ==>then it should return 1.9 I have tried to round off it and also tries different solutions but that doesn't worked for me. 回答1: You can create a helper function like this static public void Normalize(String pattern, double value ) { DecimalFormat formatter = new DecimalFormat(pattern); String normalizedValue

问题 How to round off a float value if the value is like: eg: 1.0 ==> then it should return 1 2.0 ==> then it should return 2 but if the value is like: 1.2 ==> then it should return 1.2 1.90 ==>then it should return 1.9 I have tried to round off it and also tries different solutions but that doesn't worked for me. 回答1: You can create a helper function like this static public void Normalize(String pattern, double value ) { DecimalFormat formatter = new DecimalFormat(pattern); String normalizedValue

问题 ticketPriceInPence = 7360 percentageToRefund = 100 (int)(Math.Round((ticketPriceInPence * 0.01) * (percentageToRefund * 0.01), 2, MidpointRounding.AwayFromZero) * 100) This results in : 73.59 (int)(Math.Round((ticketPriceInPence * 0.01) * (percentageToRefund * 0.01) * 100, 2, MidpointRounding.AwayFromZero)) This results in : 73.60 Any idea why it results in different 2 different results 回答1: It's the old case of floating point numbers not being able to represent decimals exactly. You seem to

问题 I have to do a special type of rounding in excel for my school project. If the number is bigger than #.5 I have to round it up. If the number is equal to #.5 I have to round it to the nearest even number. If the number is less the #.5 I have to round it down. I hope somebody is able to help me. Dim getal As Decimal = Nothing Console.WriteLine("voer een nummer in") getal = Console.ReadLine() Dim dec As Integer = Nothing Console.WriteLine("voer het aantal deciale in") dec = Console.ReadLine()

问题 Just wondering how would i round the number "15.755" up to "15.76" in ruby. I have tried the round method, but doesnt produce the result im looking for. Thanks 回答1: Is this not what you want? >> 15.755.round(2) => 15.76 Ah, you are probably using 1.8 (why btw?). There you can do the following: >> (15.755 * 100).round / 100.0 => 15.76 You could wrap that up in a helper function: def round(n, precision) raise "Precision needs to be >= 0" if precision < 0 power_of_ten = 10 ** precision (n *

问题 I'm having a problem with rounding. For some reason I can't round testP to the tenth place. For example, on the first given example (Alex Smith) it gives me the answer of 82.0, but it should be 82.6. Here is the assignment that has the examples: http://www.hpcodewars.org/past/cw5/problems/Average.htm import java.io.File; import java.io.FileOutputStream; import java.io.PrintWriter; import java.math.*; import java.util.Scanner; public class Average { public static void main(String[] args) { int

问题 hope you can help, this is driving me up the wall I need to calculate the percentage of times a question has been failed, but this needs to be narrowed down by the geographical area, and product these questions are being asked against. I have : $CA002 = "( SELECT ROUND(100 * (SELECT count(CA002Result) from Data_Table where (CA002Result='Fail'))/count(CA002Result),2) from Data_Table) AS 'CA002 %'"; Which 'works' but just calculates against the whole set of records as an 'overall' I'm trying :

问题 I'm running into following issue... Does an already 'built-in' function exists in java to round given random numbers to the closest lower quarter value. These are the given random numbers: 2.00 -> 2.00 2.24 -> 2.00 2.25 -> 2.25 2.49 -> 2.25 2.50 -> 2.50 2.74 -> 2.50 2.75 -> 2.75 2.99 -> 2.75 3.00 -> 3.00 回答1: You can multiply the value by 4 then floor it then divide by 4. public static double quarterRound(double v){ return Math.floor(v*4)/4; } 回答2: You need to round to quarters so: Multiply

问题 I'm running into following issue... Does an already 'built-in' function exists in java to round given random numbers to the closest lower quarter value. These are the given random numbers: 2.00 -> 2.00 2.24 -> 2.00 2.25 -> 2.25 2.49 -> 2.25 2.50 -> 2.50 2.74 -> 2.50 2.75 -> 2.75 2.99 -> 2.75 3.00 -> 3.00 回答1: You can multiply the value by 4 then floor it then divide by 4. public static double quarterRound(double v){ return Math.floor(v*4)/4; } 回答2: You need to round to quarters so: Multiply