rotation

问题 I have following code for my vector: <vector xmlns:android="http://schemas.android.com/apk/res/android" android:width="24dp" android:height="24dp" android:viewportWidth="314.015" android:viewportHeight="314.015"> <path android:fillColor="#FCD83500" android:pathData="M157.007,0C70.291,0 0,70.289 0,157.007c0,86.712 70.29,157.007 157.007,157.007c86.709,0 157.007,-70.295 157.007,-157.007C314.014,70.289 243.716,0 157.007,0zM31.403,157.015c0,-69.373 56.228,-125.613 125.604,-125.613V282.62C87.631

问题 How do you rotate a UIButton by 90 degrees each time the button is clicked and also keep track of each rotated position/angle? Here is the code I have so far but it only rotates once: @IBAction func gameButton(sender: AnyObject) { UIView.animateWithDuration(0.05, animations: ({ self.gameButtonLabel.transform = CGAffineTransformMakeRotation(CGFloat(M_PI_2)) })) } 回答1: self.gameButtonLabel.transform = CGAffineTransformMakeRotation(CGFloat(M_PI_2)) Should be changed to // Swift 3 - Rotate the

问题 Given a 3 x 3 rotation matrix,R, and a 3 x 1 translation matrix,T, I am wondering how to multiply the T and R matrices to an image? Lets say the Iplimage img is 640 x 480. What I want to do is R*(T*img) . I was thinking of using cvGemm, but that didn't work. 回答1: The function you are searching for is probably warpPerspective() : this is a use case... // Projection 2D -> 3D matrix Mat A1 = (Mat_<double>(4,3) << 1, 0, -w/2, 0, 1, -h/2, 0, 0, 0, 0, 0, 1); // Rotation matrices around the X axis

问题 I need help figuring out the rotation of a sprite with my finger. The sprite is rotating fine but on the initial touch of my finger it somehow rotates by a few degrees by itself. Also the rotations only work when the finger is rotated around the center of the sprite. I am trying to simulate the bicycle wheel and have a gear sprite and a pedal sprite as a child of the gear sprite. I want the bicycle wheel to rotate as I touch the pedal and rotate it. I haven't got that far yet. Right now I am

问题 3I have an image that gets manipulated by touch. Lets say its an image of an arrow that points up. After it's been rotated 180 degrees, so the arrow is pointing down now, I want to reset CGAffineTransform properties so that it thinks now its turned back to 0 degrees. I want this because I have to translate, rotate, scale etc whether the image's angle is 0 OR 180. Thanks in advance. EDITED Ater 5 replies: Hmm, I am not sure if any of these answers do what I wanted to. I apologize for not being

问题 3I have an image that gets manipulated by touch. Lets say its an image of an arrow that points up. After it's been rotated 180 degrees, so the arrow is pointing down now, I want to reset CGAffineTransform properties so that it thinks now its turned back to 0 degrees. I want this because I have to translate, rotate, scale etc whether the image's angle is 0 OR 180. Thanks in advance. EDITED Ater 5 replies: Hmm, I am not sure if any of these answers do what I wanted to. I apologize for not being

问题 I'm trying to create a new kind of rotary control with a look and feel of a real massive wheel supported on a pin, able to rotate around it's center point with a certain degree of damping, which will eventually bring the wheel to a halt. Think "wheel of fortune". Rotary control sample project When working with native UITableView and/or UIScrollView, they can be "flicked" in one direction and continue scrolling in that direction for a while. I know similar effect may be achieved with the

问题 How can I rotate a marker in leaflet? I will have a lot of markers, all with a rotation angle. I've tried this solution from runanet/coomsie at Leaflet on GitHub, but nothing happens with my marker: L.Marker.RotatedMarker= L.Marker.extend({ _reset: function() { var pos = this._map.latLngToLayerPoint(this._latlng).round(); L.DomUtil.setPosition(this._icon, pos); if (this._shadow) { L.DomUtil.setPosition(this._shadow, pos); } if (this.options.iconAngle) { this._icon.style.WebkitTransform = this

问题 When I apply a rotation transform to a UITextView and then click inside to begin editing, it appears that the content size is automatically being made wider. The new width of the content view is the width of the rotated view's bounding box. For example, given a text box of width 500 and height 400, and rotated by 30 degrees, the new content width would be: (500 * cos(30)) + (400 * sin(30)) = 633 Or graphically: Interestingly, if you are already editing the text view and THEN apply the

问题 I'm trying to spin a world around its center - but cant seem to rotate it the correct way (around its own center axis) Its hard to explain so I made a demo: .world { -webkit-animation: spin1 2s infinite linear; -moz-animation: spin1 2s infinite linear; -o-animation: spin1 2s infinite linear; -ms-animation: spin1 2s infinite linear; animation: spin1 2s infinite linear; } @-webkit-keyframes spin1 { 0% { -webkit-transform: rotate(0deg); } 100% { -webkit-transform: rotate(360deg); } } @-moz