replace

innerHTML not rendering after replace

£可爱£侵袭症+ 提交于 2020-01-25 01:33:26
问题 I am trying to get certain words to highlight in a page. To accomplish this, I want to find all text nodes and replace only the specific word with a span that will highlight it. The code appears to search and find the words in the text nodes properly, but the replace is not working. I get this: <span style="background-color: #FBC300;">foo</span> And I want to get this: foo (with a highlighted background) function toRegExp(text) { return new RegExp(text, 'g'); } function toSpan(text) { return

sed replace two double quotes and keep text

让人想犯罪 __ 提交于 2020-01-24 22:06:09
问题 Text to be processed : ""text"" "text" "" output desired : "text" "text" "" Tried with : echo -e '""text""\n"text"\n""' | sed -e 's/"".*""/".*"/g' But obviously no luck. Cheers, 回答1: You want to use a backreference (something that refers to a previously matched part) in your sed command : echo -e '""text""\n"text"\n""' | sed -E -e 's/""(.*)""/"\1"/g' Here are the modifications I did : I grouped what was inside the double-quote in the matching pattern with (...) I referenced that matching

How to replace all char except number [0-9] using javascript?

若如初见. 提交于 2020-01-24 21:54:08
问题 How to replace all char except number [ 0-9 ] using Javascript? This is my code, function test_fn(xxx) { var xxx = xxx.replace(/[^0-9,.]+/g, ""); document.getElementById("fid").value = xxx; } <input onkeyUp="test_fn(this.value)" id="fid"> But when user fill 012345... my code can not replace dot [ . ] How can I do for replace dot [ . ] too ? 回答1: If you only want to keep numbers, then replace everything that isn't a number \d = number. function test_fn(xxx) { var xxx = xxx.replace(/[^\d]/g, ""

How to replace outliers with NA having a particular range of values in R?

亡梦爱人 提交于 2020-01-24 21:51:08
问题 I have climate data and I'm trying to replace outliers with NA . I'm not using boxplot(x)$out is because I have a range of values to be considered to compute the outlier. temp_range <- c(-15, 45) wind_range <- c(0, 15) humidity_range <- c(0, 100) My dataframe looks like this df with outliers (I highlighted values that should be replaced with NA according to ranges.) So temp1 and temp2 outliers must be replaced to NA according to temp_range , wind 's outliers should be replaced to NA according

How to replace outliers with NA having a particular range of values in R?

六月ゝ 毕业季﹏ 提交于 2020-01-24 21:51:06
问题 I have climate data and I'm trying to replace outliers with NA . I'm not using boxplot(x)$out is because I have a range of values to be considered to compute the outlier. temp_range <- c(-15, 45) wind_range <- c(0, 15) humidity_range <- c(0, 100) My dataframe looks like this df with outliers (I highlighted values that should be replaced with NA according to ranges.) So temp1 and temp2 outliers must be replaced to NA according to temp_range , wind 's outliers should be replaced to NA according

Replace value in a specific with corresponding value

99封情书 提交于 2020-01-24 21:31:07
问题 I have a dataframe called REF with the following structure: old_id new_id 3 6 4 7 5 8 I want to replace all the values that can be found equal to any of the old_id values in another dataframe NEW that is: old_id column_1 column_2 3 a e 4 b f 9 c g 9 d h Therefore the new output dataset NEW will be: old_id column_1 column_2 6 a e 7 b f 9 c g 9 d h 回答1: Use map: s = df1.set_index('old_id')['new_id'] df2['old_id'] = df2['old_id'].map(s).fillna(df2['old_id']) Or slowier solution with replace: df2

How to replace all undefined values in an array with “-”?

核能气质少年 提交于 2020-01-24 19:46:31
问题 I have an array like: var array = [1, 2, undefined, undefined, 7, undefined] and need to replace all undefined values with "-" . The result should be: var resultArray = [1, 2, "-", "-", 7, "-"] I think there is a simple solution, but I couldn't find one. 回答1: You could check for undefined and take '-' , otherwise the value and use Array#map for getting a new array. var array = [1, 2, undefined, undefined, 7, undefined], result = array.map(v => v === undefined ? '-' : v); console.log(result);

How to replace a sub-string conditionally in a pandas dataframe column?

笑着哭i 提交于 2020-01-24 19:33:26
问题 I have a Series of strings (timestamps) and I would like to conditionally replace sub-string inside these strings: - if there is a '+' character, I want to replace it with '-' - or on the opposite, if there is a '-' character, I want to replace it with a '+' I obviously cannot use simply replace() without condition, or in the end, all + & - will be converted to a single + character. mySeries = mySeries.str.replace('+','-', regex=False) mySeries = mySeries.str.replace('-','+', regex=False)

Split and replace in one dataframe based on a condition with another dataframe in pandas

。_饼干妹妹 提交于 2020-01-24 19:31:10
问题 I have two dataframes and both contains sql table. This is my first Dataframe Original_Input Cleansed_Input Core_Input Type_input TECHNOLOGIES S.A TECHNOLOGIES SA A & J INDUSTRIES, LLC A J INDUSTRIES LLC A&S DENTAL SERVICES AS DENTAL SERVICES A.M.G Médicale Inc AMG Mdicale Inc AAREN SCIENTIFIC AAREN SCIENTIFIC My second dataframe is : Name_Extension Company_Type Priority co llc Company LLC 2 Pvt ltd Private Limited 8 Corp Corporation 4 CO Ltd Company Limited 3 inc Incorporated 5 CO Company 1

Split and replace in one dataframe based on a condition with another dataframe in pandas

纵然是瞬间 提交于 2020-01-24 19:31:08
问题 I have two dataframes and both contains sql table. This is my first Dataframe Original_Input Cleansed_Input Core_Input Type_input TECHNOLOGIES S.A TECHNOLOGIES SA A & J INDUSTRIES, LLC A J INDUSTRIES LLC A&S DENTAL SERVICES AS DENTAL SERVICES A.M.G Médicale Inc AMG Mdicale Inc AAREN SCIENTIFIC AAREN SCIENTIFIC My second dataframe is : Name_Extension Company_Type Priority co llc Company LLC 2 Pvt ltd Private Limited 8 Corp Corporation 4 CO Ltd Company Limited 3 inc Incorporated 5 CO Company 1