replace

如何替换字符串中出现的所有字符?

亡梦爱人 提交于 2020-01-27 15:08:20
用< c ode>std::string另一个字符替换所有出现的字符的有效方法是什么? #1楼 我以为我也会在 增强解决方案中 投入: #include <boost/ algorithm /string/replace.hpp> // in place std::string in_place = "blah#blah"; boost::replace_all(in_place, "#", "@"); // copy const std::string input = "blah#blah"; std::string output = boost::replace_all_copy(input, "#", "@"); #2楼 问题集中在 character 替换上,但是,由于我发现这个页面非常有用(特别是 Konrad 的评论),我想分享这个更通用的实现,它允许处理 substrings : std::string ReplaceAll(std::string str, const std::string& from, const std::string& to) { size_t start_pos = 0; while((start_pos = str.find(from, start_pos)) != std::string::npos) { str.replace

String操作

我是研究僧i 提交于 2020-01-27 00:19:05
/** * 去除空格 * @param {str} * @param {type} * type: 1-所有空格 2-前后空格 3-前空格 4-后空格 * @return {String} */ trim (str, type) { type = type || 1 switch (type) { case 1: return str.replace(/\s+/g, ""); case 2: return str.replace(/(^\s*)|(\s*$)/g, ""); case 3: return str.replace(/(^\s*)/g, ""); case 4: return str.replace(/(\s*$)/g, ""); default: return str; } } /** * @param {str} * @param {type} * type: 1:首字母大写 2:首页母小写 3:大小写转换 4:全部大写 5:全部小写 * @return {String} */ changeCase (str, type) { type = type || 4 switch (type) { case 1: return str.replace(/\b\w+\b/g, function (word) { return word.substring(0, 1)

PostgreSQL search and replace where condition

▼魔方 西西 提交于 2020-01-26 04:34:12
问题 I am trying to save some manual time by search and replacing in my PostgreSQL database. I have a table called Products_Colors where i'd like to replace all text in column color_image where column color_id is equal to 21. UPDATE Product_Colors SET color_image = REPLACE(color_image,"cars/car_2018.webp","cars/car_2019.webp") WHERE color_id = 21 Would this be correct syntax? 回答1: I think you need a query like this : UPDATE Product_Colors SET color_image = 'cars/car_2019.webp' WHERE color_id = 21

How to find and replace text strings in multiple files using Visual Basic

回眸只為那壹抹淺笑 提交于 2020-01-26 02:49:28
问题 I have a basic question about a simple vbs script. My goal is to find a replace multiple text strings in multiple files. (The 21 text strings to replace are the same across files.) The file names have about 12 prefixes and then will have numbers 1 to 200 at the end. The basic code I am using for just one of the strings in one of the files is as follows. Const ForReading = 1 Const ForWriting = 2 Set objFSO = CreateObject("Scripting.FileSystemObject") Set objFile = objFSO.OpenTextFile("C:

Kubernetes基础:重启pod的方法

大城市里の小女人 提交于 2020-01-26 01:04:43
Kubernetes没有提供诸如docker restart类似的命令用于重启容器那样重启pod的命令,一般会结合restartPolicy进行自动重启,这篇文章整理一下偶尔需要手动进行重启的时候所需要使用的方法。 事前准备 环境准备 本文使用Kubernetes 1.17,可参看下文进行快速环境搭建: 单机版本或者集群版本环境搭建 pod准备 使用如下pod的yaml文件 [root@host131 config]# cat busybox-pod-test.yaml apiVersion: v1 kind: Pod metadata: name: test-pod spec: containers: - name: busybox-container image: busybox:latest command: ["sleep", "15"] restartPolicy: Never [root@host131 config]# 执行命令:kubectl create -f busybox-pod-volume.yaml 执行日志示例如下所示 [root@host131 ~]# kubectl get pods No resources found in default namespace. [root@host131 ~]# kubectl create -f busybox

Copy data inside one field XML

戏子无情 提交于 2020-01-25 21:31:53
问题 I have some lines like: <channel update="i" site="merge-xmltv" site_id="" xmltv_id="Rai 1">Rai 1</channel> <channel update="i" site="merge-xmltv" site_id="" xmltv_id="Rai 1 +2HD">Rai 1 +2HD</channel> <channel update="i" site="merge-xmltv" site_id="" xmltv_id="Rai 1 +1HD">Rai 1 +1HD</channel> I need copy the value of xmltv_id into site_id like this: <channel update="i" site="merge-xmltv" site_id="Rai 1" xmltv_id="Rai 1">Rai 1</channel> <channel update="i" site="merge-xmltv" site_id="Rai 1 +2HD

正则实现整数运算

不羁岁月 提交于 2020-01-25 16:46:58
加 const sum = ( m , n ) => { m = Array ( m + 1 ) . join ( '#' ) ; n = Array ( n + 1 ) . join ( '#' ) ; return m . replace ( /$/ , n ) . length ; } ; sum ( 3 , 2 ) ; // 5 减 const diff = ( m , n ) => { m = Array ( m + 1 ) . join ( '#' ) ; n = Array ( n + 1 ) . join ( '#' ) ; return m . replace ( n , '' ) . length ; } ; diff ( 3 , 2 ) ; // 1 乘 const product = ( m , n ) => { m = Array ( m + 1 ) . join ( '#' ) ; n = Array ( n + 1 ) . join ( '#' ) ; return m . replace ( /\#/g , n ) . length ; } ; product ( 3 , 2 ) ; // 6 除 const division = ( m , n ) => { m = Array ( m + 1 ) . join ( '#' ) ; n =

How to replace new lines by regular expressions

此生再无相见时 提交于 2020-01-25 08:35:32
问题 Can you help me with replacing in PHP. I don't know how to set any quantity of new lines with regex. $var = "<p>some text</p><p>another text</p><p>more text</p>"; $search = array("</p>\s<p>"); $replace = array("</p><p>"); $var = str_replace($search,$replace,$var); What I need, is to remove every new line ( \n ), not <br/> , between two paragraphs. Thanks a lot. 回答1: To begin with, str_replace() (which you referenced in your original question) is used to find a literal string and replace it.

XSLT replacing text in attribute value and text nodes

时间秒杀一切 提交于 2020-01-25 04:26:13
问题 I have an XML document that I'm trying to transform and do a string replace of certain values when that value occurs in either a text node or an attribute named message . My xsl file is below, but the main issue is that when the replace occurs in the message attribute, it actually replaces the whole attribute and not just the value of that attribute, so <mynode message="hello, replaceThisText"></mynode> becomes <mynode>hello, withThisValue</mynode> Instead of <mynode message="hello,

XSLT replacing text in attribute value and text nodes

不羁岁月 提交于 2020-01-25 04:25:59
问题 I have an XML document that I'm trying to transform and do a string replace of certain values when that value occurs in either a text node or an attribute named message . My xsl file is below, but the main issue is that when the replace occurs in the message attribute, it actually replaces the whole attribute and not just the value of that attribute, so <mynode message="hello, replaceThisText"></mynode> becomes <mynode>hello, withThisValue</mynode> Instead of <mynode message="hello,