repeat

How to set iTunes 11 in shuffle or repeat mode via applescript

℡╲_俬逩灬. 提交于 2019-11-27 12:08:58
问题 According to http://dougscripts.com/ setting shuffle and repeat modes via applescript is broken in iTunes 11. According to this stackoverflow answer shuffle is now a playlist independent setting. Thus, I tried to set the shuffle value via the UI, either by the LCD-ish display of iTunes or via the menu bar. All I could get was "unknown UI index" errors when trying to click the shuffle button/menu item, either in the LCD area or the menu bar. (I'm new to applescript). If some of you could come

Print header/footer on all pages (Print Mode)

流过昼夜 提交于 2019-11-27 11:36:57
问题 <div id="header">header</div> <div id="content"> content spanning several pages... </div> <div id="footer">Footer - Fixed at the bottom of each page</div> I want to print #header and #footer on every page in print mode. I searched a lot but nothing seems to work, even position:fixed doesn't work as expected. 回答1: If you're willing to switch over to tables for your layout (not necessarily ideal), you can do it with the <thead> and <tfoot> elements. They'll print at the top and bottom of every

Initializing a vector of vectors having a fixed size with boost assign

房东的猫 提交于 2019-11-27 09:37:38
问题 Having a vector of vector with a fixed size, vector<vector<int> > v(10); I would like to initialize it so that it has in all elements a one dimensional vector with initialized value (for example 1). I have used Boost Assign as follows v= repeat(10,list_of(list_of(1))); and I've got a compilation error error: no matching function for call to ‘repeat(boost::assign_detail::generic_list<int>)’ Could you please tell me how to do that. Thanks in advance 回答1: This doesn't use boost::assign but does

Repeating background image in native iPhone app

天大地大妈咪最大 提交于 2019-11-27 08:59:40
问题 Short of putting a UIWebView as the back-most layer in my nib file, how can I add a repeating background image to an iPhone app (like the corduroy look in the background of a grouped UITableView)? Do I need to create an image that's the size of the iPhone's screen and manually repeat it using copy and paste? 回答1: Apparently a UIColor is not necessarily a single color, but can be a pattern as well. Confusingly, this is not supported in Interface Builder. Instead you set the backgroundColor of

Find String Inside Outermost Parenthesis

徘徊边缘 提交于 2019-11-27 08:43:00
问题 Say that I have a string which contains both multiple sets and nesting of parenthesis. I want to extract only the string in the first parenthesis encountered, including whatever nested parenthesis it contains. For example: this (is(maybe)) a test (and maybe not) I want to extract: is(maybe) I believe this can be accomplished without the use of regexes, by which I can easily do it. So my question is how can this be accomplished without regexes? 回答1: Pseudo code: iterate over chars if char is (

Repeat elements of vector [duplicate]

大兔子大兔子 提交于 2019-11-27 08:15:19
问题 This question already has an answer here: Repeat copies of array elements: Run-length decoding in MATLAB 5 answers I have a value vector A containing elements i , for example: A = [0.1 0.2 0.3 0.4 0.5]; and say r = [5 2 3 2 1]; Now I want to create a new vector Anew containing r(i) repetitions of the values i in A , such that the first r(1)=5 items in Anew have value A(1) and the length of the new vector is sum(r) . Thus: Anew = [0.1 0.1 0.1 0.1 0.1 0.2 0.2 0.3 0.3 0.3 0.4 0.4 0.5] I am sure

Git: how to avoid repetitive committing with sub-sub-sub… Git -repos?

怎甘沉沦 提交于 2019-11-27 07:22:34
问题 I have many sub -repos, meaning one big umbrella repo that has smaller repos. Now when I do a commit in a leaf repo, it will automatically mean that I get a change in its parents. If you suppose the structure as a binary tree, you may realize it is ridiculous -- having 5 git-repo deep structure could easily mean $ git commit -m 'did 1'; cd ..; git commit -m 'did 1 as mentioned'; ... git commit -m 'did 1 same as earlier' . How can I avoid this kind of repetitive committing? Example 1: a

Why did the ListView repeated every 6th item?

☆樱花仙子☆ 提交于 2019-11-27 05:27:19
I have a ListView that is filled by a Custom Adapter with a specific Layout. The Adapter is mapped to a HashMap with the specific Elements that contains the Data for each ListView Element. The Data in the hashMap is correct, but the ListView repeats to draw every 6'th the same 6'th Elements again, till it reaches the end of the Map?? My Display allows to display 5 items, if you sroll a litte it's 6 items. Here is the Code of the Adapter, the relevant Code of the ListActivity and the layout file of the ListView. Please help, I've no Idea why this happens. package de.View; import java.util

Matlab: repeat every column sequentially n times [duplicate]

老子叫甜甜 提交于 2019-11-27 05:10:28
This question already has an answer here: Element-wise array replication in Matlab 7 answers I'm pretty much beginner so it's probably possible to do what I want in a simple way. I have a matrix 121x62 but I need to expand it to 121x1488 so every column has to be repeated 24 times. For example, transform this: 2.2668 2.2667 2.2667 2.2666 2.2666 2.2666 2.2582 2.2582 2.2582 2.2582 2.2581 2.2581 2.283 2.283 2.283 2.2829 2.2829 2.2829 2.2881 2.2881 2.2881 2.2881 2.2881 2.288 2.268 2.268 2.2679 2.2679 2.2678 2.2678 2.2742 2.2742 2.2741 2.2741 2.2741 2.274 into this: 2.2668 2.2668 2.2668 and so on

Javascript: Random number out of 5, no repeat until all have been used

£可爱£侵袭症+ 提交于 2019-11-27 03:05:47
问题 I am using the below code to assign a random class (out of five) to each individual image on my page. $(this).addClass('color-' + (Math.floor(Math.random() * 5) + 1)); It's working great but I want to make it so that there are never two of the same class in a row. Even better would be if there were never two of the same in a row, and it also did not use any class more than once until all 5 had been used... As in, remove each used class from the array until all of them have been used, then