repeat

I'm trying to make a simple floor texture, but it seems that wrapS and wrapT don't works. Look at the result: http://hpics.li/321350c var texture = THREE.ImageUtils.loadTexture( "Game/Texture/drytext.png" ); texture.wrapS = THREE.RepeatWrapping; texture.wrapT = THREE.RepeatWrapping; texture.repeat.set( 4, 4 ); var floorMaterial = new THREE.MeshBasicMaterial( { map: texture, side: THREE.DoubleSide }); var floorGeometry = new THREE.PlaneGeometry(20, 20, 10, 10); var floor = new THREE.Mesh(floorGeometry, floorMaterial); floor.rotation.x = -Math.PI / 2; scene.add(floor); Thank you 来源： https:/

I have been trying to get this JavaScript to repeat the audio once it has finished, I have had a look around and I am inexperienced with JavaScript, although I have made attempts tweaking and researching I have had no luck so far. I would be very grateful for any help and tips Many thanks- Grant <!-- Script inside body --> <!-- Audio Player --> <script> $(document).ready(function() { var audioElement = document.createElement('audio'); audioElement.setAttribute('src', 'music/audio.mp3'); audioElement.setAttribute('play', 'autoplay'); //audioElement.load() $.get(); audioElement.addEventListener(

I am converting the "zxcvbn" password strength algorithm from JavaScript to Scala. I am looking for a pure functional algorithm for finding sequences of repeating characters in a string. I know that I can translate the imperative version from JavaScript, but I would like to keep this as side-effect free as possible, for all the reasons usually given for functional programming. The algorithm can be in Scala, Clojure, Haskell, F#, or even pseudocode. Thanks. Using Haskell's standard higher-order functions: Data.List.group finds runs of equal elements in a list: > group "abccccdefffg" ["a","b",

My app requires very accurate timing of a repeating alarm. Since API 19 the AlarmManager setRepeating is now inexact to save battery ( Save the trees and all ). Is there any workaround to get API 19's setExact method to work on a loop? Note: as of API 19, all repeating alarms are inexact. If your application needs precise delivery times then it must use one-time exact alarms, rescheduling each time as described above. Legacy applications whose targetSdkVersion is earlier than API 19 will continue to have all of their alarms, including repeating alarms, treated as exact. Is there any workaround

In MATLAB I have a vector x of length n, where n is usually O(10), and I would like to build a tall matrix A of size [n^m,m], where m is again 0(10). The matrix has a peculiar form: if n=4 and m=6, let x=[x1; x2; x3; x4] then A is x1 x1 x1 x1 x1 x1 x2 x1 x1 x1 x1 x1 x3 x1 x1 x1 x1 x1 x4 x1 x1 x1 x1 x1 x1 x2 x1 x1 x1 x1 x2 x2 x1 x1 x1 x1 x3 x2 x1 x1 x1 x1 x4 x2 x1 x1 x1 x1 x1 x3 x2 x1 x1 x1 . . . . . . x4 x4 x4 x4 x4 x4 In practice, each column is obtained by repeating the elements of x, with an increasing stride for each column. How can I do that? If possible, I'd prefer an efficient

I have this string "2017-03-05-02-10-10_78205" and I want to match it with this pattern [0-9]{4}(-[0-9]{2}){5}_[0-9]+ but it doesn't work on CMake. See this example in CMake : set(stuff "2017-03-05-02-10-10_78205") if( "${stuff}" MATCHES "[0-9]{4}(-[0-9]{2}){5}_[0-9]+") message("Hello") endif() CMake doesn't seem to support the syntax {n} . Obviously, I solved my problem with that pattern [0-9-]+_[0-9]+ Nevertheless, I would like to know if I'm doing something wrong with the syntax {n} . Is it supported by CMake ? If not, how to define a specific number of repetition with CMake ? I'm using an

Assume you have a vector like so: v <- c(1,1,1,2,2,2,2,1,1,3,3,3,3) How can it be best reduced to a data.frame like this? v.df <- data.frame(value=c(1,2,1,3),repetitions=c(3,4,2,4)) In a procedural language I might just iterate through a loop and build the data.frame as I go, but with a large dataset in R such an approach is inefficient. Any advice? or more simply data.frame(rle(v)[]) with(rle(v), data.frame(values, lengths)) should get you what you need. values lengths 1 3 2 4 1 2 3 4 来源： https://stackoverflow.com/questions/3010790/sequence-reduction-in-r