repeat

问题 What is the most optimal way to find repetition in a infinite sequence of integers? i.e. if in the infinite sequence the number '5' appears twice then we will return 'false' the first time and 'true' the second time. In the end what we need is a function that returns 'true' if the integer appeared before and 'false' if the function received the integer the first time. If there are two solutions, one is space-wise and the second is time-wise, then mention both. I will write my solution in the

问题 I want my image to repeat only in X axis. I use this code: @Override protected void onCreate(Bundle savedInstanceState) { super.onCreate(savedInstanceState); LinearLayout l = new LinearLayout(this); l.setLayoutParams(new LayoutParams(-2, -2)); BitmapDrawable b = null; try { b = new BitmapDrawable(getAssets().open("pattern.jpg")); } catch (IOException e) { // TODO Auto-generated catch block e.printStackTrace(); } b.setTileModeX(TileMode.REPEAT); l.setBackgroundDrawable(b); setContentView(l); }

问题 I am working on a Java assignment and I am absolutely stumped. The question is: Write a function using Recursion to do the following: You have X different cards. You have only Y envelopes. Y is less than or equal to X. For any given values of X and Y, display all possible ways you can fill the Y envelopes when Order is not important and Repetition is not allowed. hint: X! / (( X-Y)! * Y!) display all possible ways you can fill the Y envelopes when Order is important and Repetition is allowed

问题 I don't know how to do this, but I would like to have 2 repeating textures, one that repeats to the left and one to the right. instead of: #header { background-image : Url('My_Two_Textures_Combined.png'); background-repeat : repeat-x; /*Which repeats my joined textures a long the x axis*/ } I would like: #header { background-image : Url('My_Left_Texture'); background-repeat : repeat-x-left; /*Which would ideally repeat my texture to the left on the x axis*/ background-image : Url('My_Right

问题 Is there any way to make a background image stretch rather than repeat? 回答1: Not using any kind of cross-browser compatible CSS (there is the background-size property however.) If this is directed at any browser in particular, it might be possible. Otherwise, you'll need to use an <img> and stretch that. Here's how you do it in recent browsers: body { background-image: url(bg.jpg); -moz-background-size: 100% 100%; /* Gecko 1.9.2 (Firefox 3.6) */ -o-background-size: 100% 100%; /* Opera 9.5 */

问题 In MATLAB I have a vector x of length n, where n is usually O(10), and I would like to build a tall matrix A of size [n^m,m], where m is again 0(10). The matrix has a peculiar form: if n=4 and m=6, let x=[x1; x2; x3; x4] then A is x1 x1 x1 x1 x1 x1 x2 x1 x1 x1 x1 x1 x3 x1 x1 x1 x1 x1 x4 x1 x1 x1 x1 x1 x1 x2 x1 x1 x1 x1 x2 x2 x1 x1 x1 x1 x3 x2 x1 x1 x1 x1 x4 x2 x1 x1 x1 x1 x1 x3 x2 x1 x1 x1 . . . . . . x4 x4 x4 x4 x4 x4 In practice, each column is obtained by repeating the elements of x, with

问题 My app requires very accurate timing of a repeating alarm. Since API 19 the AlarmManager setRepeating is now inexact to save battery ( Save the trees and all ). Is there any workaround to get API 19's setExact method to work on a loop? Note: as of API 19, all repeating alarms are inexact. If your application needs precise delivery times then it must use one-time exact alarms, rescheduling each time as described above. Legacy applications whose targetSdkVersion is earlier than API 19 will

问题 I have been trying to get this JavaScript to repeat the audio once it has finished, I have had a look around and I am inexperienced with JavaScript, although I have made attempts tweaking and researching I have had no luck so far. I would be very grateful for any help and tips Many thanks- Grant <!-- Script inside body --> <!-- Audio Player --> <script> $(document).ready(function() { var audioElement = document.createElement('audio'); audioElement.setAttribute('src', 'music/audio.mp3');

问题 I need a way to make a div repeat a certain number (36) of times vertically, with 1px of space between each one. The divs are absolutely positioned, so styling each one individually would be a ton of CSS. I don't mind putting 36 divs into the HTML directly, although I'd prefer not to, but styling each one would be inefficient. 回答1: How about nest them? you can nest them with relative positioning or maybe some margin: http://jsfiddle.net/zWbUu/ HTML div id="container"> <div class="square">

问题 I have this string "2017-03-05-02-10-10_78205" and I want to match it with this pattern [0-9]{4}(-[0-9]{2}){5}_[0-9]+ but it doesn't work on CMake. See this example in CMake : set(stuff "2017-03-05-02-10-10_78205") if( "${stuff}" MATCHES "[0-9]{4}(-[0-9]{2}){5}_[0-9]+") message("Hello") endif() CMake doesn't seem to support the syntax {n} . Obviously, I solved my problem with that pattern [0-9-]+_[0-9]+ Nevertheless, I would like to know if I'm doing something wrong with the syntax {n} . Is