regex | 易学教程

R regex lookbehind with a long expression

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问题 I have a long character that comes from a pdf extraction. Below is a MWE : MWE <- "4 BLABLA\r\n Table 1. Real GDP\r\n Percentage changes\r\n 2016 2017 \r\nArgentina -2.5 2.7\r\nAustralia 2.6 2.5\r\n BLABLA \r\n Table 2. Nominal GDP\r\n Percentage changes\r\n 2011 2012\r\nArgentina 31.1 21.1\r\nAustralia 7.7 3.3\r\n" I want to separate this into a list, with each element being a table. I can do that with : MWE_1 <- as.list(strsplit(MWE, "(?<=[Table\\s+\\d+\\.\\s+(([A-z]|[ \t]))+\\r\\n])")) >

Regex not matching words ending with “Impl”

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问题 I want to create a regex that allows only class names not ending with Impl . I'v read that "not ends with" could be tested with a negative lookahead (?!) , but I cannot find a working (Java) regex. I tried [A-Z][A-Za-z\d]*?(?!Impl) but it matches SomeImpl , what shouldn't be the case. What regex wouldn't match class names ending with Impl ? 回答1: A negative lookahead wont work because - with the *? (lazy zero-or-more) quantifier - it'll check at S and find no Impl immediately ahead so the

Using VBA regular expressions to find/replace in Word

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问题 Yes, I have searched (and found) many response similar to this, but none work for me. I have a lot of patterns to replace, most along these lines: Find: ([aA])ttorney-at-law Replace: \1ttorney at law I could create two ordinary find/replaces for each case, but I've got hundreds to do. Any help or direction would be much appreciated. I can do this in NPP, but the people I'm doing this for work in Word exclusively. I've got other phrases where I'm adding hyphens or, e.g., changing ([bB])ook

count occurrences of a string pattern in a file and count

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问题 Team, I am trying to count two patterns in a file and list them as pattern1: 2 pattern2: 3 #!/usr/bin/python import os import re d = dict() with open('/home/user/waste/nodes-prod.log', 'r') as file: for line in file: line = line.strip() for word in line.split(): node1 = re.match(r"team1.*", word) type(node1) node2 = re.match(r"team2.*", word) type(node2) if node1 in d: d[node1] = d[node1] + 1 else: d[node2] = d[node2] + 1 for key in list(d.keys()): print(key, ":", d[key]) my /home/user/waste

Command to import multiple files from Cloud Storage into BigQuery

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问题 I've figured that this command lists paths to all files: gsutil ls "gs://bucket/foldername/*.csv" This command imports a file to BQ and autodetects schema: bq load --autodetect --source_format=CSV dataset.tableName gs://bucket/foldername/something.csv Now I need to make it work together to import all files to respective tables in BQ. If table exists, then replace it. Could you give me a hand? 回答1: First, create a file with all the list with all the folders you want to load into BigQuery:

Parse url structure by regular expression

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问题 I have one URL pattern : product/[cat]/[page].[ext] product/category/page.html product/page.html But my Regular Expression does not work properly : ^product\/([\w\d\.\-_\s\'\"\[\]\؀-\ۿ](?!.*\.html))*\/([\w\d\.\-_\s\'\"\[\]\؀-\ۿ]+\.html+)*\/?$ I want by one regEx pattern detect url and it parameters I use match function in javascript EDIT : my route pattern : product/cat?/page.html? I want make regEx by this pattern ? in this pattern means this section is optional For example :

Match pattern not preceded or followed by string

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问题 I need to match any sequence of 9 digits or more, that is not preceded OR followed by 2 uppercase letters, anywhere in a text: OG237338070BR // should NOT match og237338070br // should match oG237338070bR // should match G237338070BR // should match OG237338070B // should match G237338070B // should match asd OG237338070BR asd // should NOT match asd G237338070BR asd // should match asd OG237338070B asd // should match asd OG237338070Basd asd // should match asd OG237338070BRasd asd // should

Extract Last Upper cases from a string [duplicate]

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问题 This question already has answers here : Extract the last word between | | (5 answers) Closed 2 years ago . I am practicing with regular expressions in R. I would like to extract the last occurrence of two upper case letters. I tried >str_extract("kjhdjkaYY,","[:upper:][:upper:]") [1] "YY" And it works perfectly fine. What if I would like to extract the last occurrence of such pattern. Example: function("kKKjhdjkaYY,") [1] "YY" Thank you for your help 回答1: We can use stri_extract_last_regex

Can use RegEx to compare two captured groups

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问题 I have a log message that i want to match only if two captured groups are the same! example some date from source-ip=1.1.1.1 trying to send another data to the destination-ip=1.1.1.1 in addition to some date So, i want to trigger if sip=dip it matches!? Would it be possible using a single regex? 回答1: Yes, this can be done via back-references. https://www.regular-expressions.info/backref.html Using "some date from source-ip=1.1.1.1 trying to send another data to the destination-ip=1.1.1.1 in

50个能帮你节省时间的开发工具

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