regex

问题 I have a PowerShell Scriptline that replaces(deletes) characters between the second and third underscore with an "_": get-childitem *.pdf | rename-item -newname { $_.name -replace '_\p{L}+, \p{L}+_', "_"} Examples: 12345_00001_LastName, FirstName_09_2018_Text_MoreText.pdf 12345_00002_LastName, FirstName-SecondName_09_2018_Text_MoreText.pdf 12345_00003_LastName, FirstName SecondName_09_2018_Text_MoreText.pdf This _\p{L}+, \p{L}+_ regex only works for the first example. To replace everything

问题 I need help in regular expressions. The code is in SQL and I would like to match the all string that is not referencing proxy database. The pattern would be: Contains .. and the word before it is not equal to proxy I would like to match the example word customer below: from proxy..vw_xxx a join customer..vw_xxx b from proxy..vw_xxx insert into proxy..vw_xxx from customer..vw_xxx Edit: How about if I would also like to capture the DDL statement. For Example: CREATE VIEW vw_yyy AS ... from

问题 I'm writing a free plugin for Google Docs and processing paragraphs of text. I need a regular expression to match everything except a phrase (i.e. multiple words separated with spaces). For example, when searching the text The quick brown fox jumped over the lazy dog I want to match everything except quick brown and lazy with the expected result being The fox jumped over the dog . \b((?!(lazy)\b).)+ This works; it matches all text except lazy and I get The quick brown fox jumped over the dog

问题 I have a several strings that I want to split by spaces when not inside parentheses. For example sentence = "blah (blah2 (blah3))|blah4 blah5" should produce ["blah", "(blah2 (blah3))|blah4", "blah5"] I've tried: re.split(r"\s+(?=[^()]*(?:\(|$))", sentence) but it produces: ['blah', '(blah2', '(blah3))|blah4', 'blah5'] 回答1: As said in the comments, it's impossible to process that using regex because of parenthesis nesting. An alternative would be some good old string processing with nesting

问题 I need regex that match Scheme identifier that will terminate if it find any of the not allowed strings. I have code like this: function make_tokens_re() { var tokens = specials.names() .sort((a, b) => b.length - a.length || a.localeCompare(b)) .map(escape_regex).join('|'); return new RegExp(`(#\\\\(?:x[0-9a-f]+|${character_symbols}|[\\s\\S])|#f|#t|#;|(?:${num_stre})(?=$|[\\n\\s()[\\]])|\\[|\\]|\\(|\\)|\\|[^|]+\\||;.*|(?:#[ei])?${float_stre}(?=$|[\\n\\s()[\\]])|\\n|\\.{2,}|(?!#:|'#[ft])(?:$

问题 My regex-fu is weak today. I'm trying to capture groups in a string into 5 parts with the format: substring delimiter substring number(space) substring I've tried using word boundaries but no success. I've resorted to using *.(greedy and lazy, I know) which is bit better than not working at all Here's what I have: import re s = "FOREVER - Alabaster Cuttlefish - 01 This Style Is Cheese" m = re.compile("(.*)(\s-\s)(\d{1,3}\s)(.*)") g = m.match(s) if g: print m.match(s).group(1) # FOREVER print

问题 I have messed around with special characters in regular expression for several hours now, and must admit that i give up. Trying to make a password test function, that test for at least one of the following: lowercase, uppercase, integer and special character. The special characters are "¤@+-£$!%*#?&().:;,_". I have used this function to escape them: //used to escape special characters [¤@+-£$!%*#?&().:;,_] RegExp.escape = function(str) { return String(str).replace(/([.*+?^=!:${}()|\[\]\/\\])

问题 This deals with the general problem of extracting a signed number from a string that also contains hyphens. Can someone please come up with the regex for the following: "item205" => 205 "item-25 => -25 "item-name-25" => -25 Basically, we want to extract the number to the end of the string, including the sign, while ignoring hyphens elsewhere. The following works for the first two but returns "-name-25" for the last: var sampleString = "item-name-25"; sampleString.replace(/^(\d*)[^\-^0-9]*/, "

问题 i need to replace all occurrences of a string within another string, if the original string matches some filter i can only use a single regex using an s command, because i need to send the assembled command to a 3rd party API i have tried to use positive lookahead as to not consume the string in which i want to replace characters, but somehow i can not get the replacing to work as expected. here is what i have tried so far and what was the outcome: (note that the filter - here [0-9]+ is just

问题 I want to extract year from a string. I got an incomplete solution. My string will be always like: Please message mpg of jazz 2014 and 2015+ to my mobile number +123456789 I have tried the following regex; preg_match_all('!\d{4}+| \d{4}+\W!', $str, $matches); This will output the following array. Array ( [0] => Array ( [0] => 2015 [1] => 2014+ [2] => 1234 [3] => 5678 ) ) I need to get only the year portion with + symbol if any. I.e, i want only this: Array ( [0] => Array ( [0] => 2015 [1] =>