reference

问题 There'a a similar question here but I couldn't make use of the answers in XCode 4. I googled it but I couldn't come up with anything useful either. What's your effective method of getting this information? 回答1: Find in project, though if you are searching to change the name everywhere, better would be to use the Refactoring menu. EDIT: You can use Refactoring to find where a specific variable is referenced. Select the variable and choose Edit->Refactor->Rename. In the refactoring screen,

问题 I am trying to find how to reference branch start commit from script. I mean the commit sha at which branch was forked. Moreover I expect it work for history made from svn repo. This post just gives first commit of repo creation and not feature branch start commit. 回答1: What you're looking for is the command merge-base : git merge-base master feature-branch will print the best common ancestor of those two branches, i.e. where they forked apart. (The documentation has pretty pretty pictures to

问题 I'm trying to set up an assembly binding redirect, using the following app.config: <configuration> <runtime> <assemblyBinding xmlns="urn:schemas-microsoft-com:asm.v1"> <dependentAssembly> <assemblyIdentity name="Microsoft.AnalysisServices" PublicKeyToken="89845dcd8080cc91" /> <bindingRedirect oldVersion="10.0.0.0" newVersion="9.0.0.0" /> </dependentAssembly> </assemblyBinding> </runtime> </configuration> I'm running the program on a machine with version 9.0.242.0 in the GAC, with the

问题 I know this is probably a very newbish question, so I apologize. I am trying to access the Text property of a label on Form1 from another form, MaxScore. When I click the Ok button on MaxScore, I want to set Form1's myGameCountLbl.Text to Form1's variable, max by using max.ToString(). Here is my code in the OK button event of MaxScore: private void okBtn_Click(object sender, EventArgs e) { Form1.myGameCountLbl.Text = Form1.max.ToString(); Form1.compGameCountLbl.Text = Form1.max.ToString(); }

问题 I have a function like this const string &SomeClass::Foo(int Value) { if (Value < 0 or Value > 10) return ""; else return SomeClass::StaticMember[i]; } I get warning: returning reference to temporary . Why is that? I thought the both values the function returns (reference to const char* "" and reference to a static member) cannot be temporary. 回答1: This is an example when an unwanted implicit conversion takes place. "" is not a std::string , so the compiler tries to find a way to turn it into

问题 How would I make an exact duplicate of an array? I am having hard time finding information about duplicating an array in Swift. I tried using .copy() var originalArray = [1, 2, 3, 4] var duplicateArray = originalArray.copy() 回答1: Arrays have full value semantics in Swift, so there's no need for anything fancy. var duplicateArray = originalArray is all you need. If the contents of your array are a reference type, then yes, this will only copy the pointers to your objects. To perform a deep

问题 Please take a look at the following simple code: class Foo { public: Foo(){} ~Foo(){} Foo(const Foo&){} Foo& operator=(const Foo&) { return *this; } }; static Foo g_temp; const Foo& GetFoo() { return g_temp; } I tried to use auto like this: auto my_foo = GetFoo(); I expected that my_foo will be a constant reference to Foo , which is the return type of the function. However, the type of auto is Foo , not the reference. Furthermore, my_foo is created by copying g_temp . This behavior isn't that

问题 How would I make an exact duplicate of an array? I am having hard time finding information about duplicating an array in Swift. I tried using .copy() var originalArray = [1, 2, 3, 4] var duplicateArray = originalArray.copy() 回答1: Arrays have full value semantics in Swift, so there's no need for anything fancy. var duplicateArray = originalArray is all you need. If the contents of your array are a reference type, then yes, this will only copy the pointers to your objects. To perform a deep

问题 Please take a look at the following simple code: class Foo { public: Foo(){} ~Foo(){} Foo(const Foo&){} Foo& operator=(const Foo&) { return *this; } }; static Foo g_temp; const Foo& GetFoo() { return g_temp; } I tried to use auto like this: auto my_foo = GetFoo(); I expected that my_foo will be a constant reference to Foo , which is the return type of the function. However, the type of auto is Foo , not the reference. Furthermore, my_foo is created by copying g_temp . This behavior isn't that

问题 I have some data structures, and I would like to use one as a temporary, and another as not temporary. ArrayList<Object> myObject = new ArrayList<Object>(); ArrayList<Object> myTempObject = new ArrayList<Object>(); //fill myTempObject here .... //make myObject contain the same values as myTempObject myObject = myTempObject; //free up memory by clearing myTempObject myTempObject.clear(); now the problem with this of course is that myObject is really just pointing to myTempObject , and so once