recursion

问题 I'm currently working on recursion and i keep getting stuck at this question: Find the cheapest path through an array using recursion. for example, if i had an array [0,1,3,4,1] i start at the value 0. Now i have 2 options i could jump to index 2 or just move to index 1.In this case i would jump right to index 2 (value 3) then jump to index 4 (value 1) because 3+1= 4 and that would be the cheapest way through the array. I've tried to compare the move index value with the jump index value and

问题 I'm currently working on recursion and i keep getting stuck at this question: Find the cheapest path through an array using recursion. for example, if i had an array [0,1,3,4,1] i start at the value 0. Now i have 2 options i could jump to index 2 or just move to index 1.In this case i would jump right to index 2 (value 3) then jump to index 4 (value 1) because 3+1= 4 and that would be the cheapest way through the array. I've tried to compare the move index value with the jump index value and

问题 I'm writing a basic recursion function that takes an integer, n, and returns the sum of the first n reciprocals. Inputting 2 should result in 1.5, and inputting 0 should return 0. sum_to(2) = (1 + 1/2) = 1.5 Here's what I have: def sum_to(n): if n>0: return sum_to(1+1/n) # Not sure if this is correct return 0 But all I'm getting is a Maximum recursion depth exceeded. I know I could lists to solve this, but recursion is really intriguing and I want to find a solution using it. 回答1: From the

问题 Following this question I need to put it in a function (maybe recursive) so that I pass in the array variants and it returns a single array with all the variants. I have an array with the different t-shirt variants like this: Color: Black, Red, Blue Size: L, M, XL ... The variants may differ, more sizes, les colors, or new variants like tissue variants. I need a function that returns an array with all the iterated variants like this: 0 Color=>Black Size=>L 1 Color=>Black Size=>M 2 Color=

问题 I have the following recursive function to count all the nodes having value 20, in a circular doubly linked list. I need to convert this to tail recursive function to prevent safety issues. Please help me with the same. Thanks int count(node *start) { return count_helper(start, start); } int count_helper(node *current, node *start) { int c; c = 0; if(current == NULL) return 0; if((current->roll_no) == 20) c = 1; if(current->next == start) return c; return (c + count_helper(current->next,

问题 This code is supposed to print the sum of numbers from 10 to 0. It should be printing 55, but is printing 10 instead. Can you help me figure out where it's going wrong? main: # initialize values to 3 registers addi $a0,$zero,10 jal sum # call method # Print out the summation upto 10 li $v0,1 # print integer add $a1,$v0,$zero # load return value into argument syscall li $v0,10 # Exit syscall sum: addi $sp,$sp,-8 # allocate space on stack sw $ra,0($sp) # store the return address sw $a0,4($sp) #

问题 I noticed there is a type mismatch caused in the line else if(r1 == 0 || divisors.tail.isEmpty || !divisors.tail.contains(r1)){newAcc} . Because there is no else clause to my if ... else if ... def euclidianDivision(dividend:Int,divisor:Int):(Int,Int)={ val quotient = dividend/divisor val remainder = dividend%divisor (quotient,remainder) } def firstExpansion(dividend:Int,divisors:List[Int]):List[(Int,Int)]={ def firstExpansionIter(dividend:Int,divisors:List[Int], acc:List[(Int,Int)]):List[

问题 I have the following problem. The recursive method public static String doSomeMagic("Test") should return: TTeesstt TTeess TTee TT I've implemented this behaviour already like this: public static String rowFunction(String s) { String toReturn = new String(); if (!s.isEmpty()) { toReturn = String.valueOf(s.charAt(0)); toReturn += toReturn + rowFunction(s.substring(1)); } return toReturn; } public static String doSomeMagic(String s) { String toReturn = new String(); if (!s.isEmpty()) { toReturn

问题 Could anyone say why the following recursive function does not work for me ? It should collect recursively all radio buttons in a given element. But, it does not found any for some reason !? Thanks !! <?xml version="1.0" encoding="Windows-1255"?> <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> <head> <script type="text/javascript"> function AllInputs(radioElement) { this

问题 I am stuck in Javascript promise based program and not able to figure out how to get it to return the right value, in a promise format. Given an Tree API that returns children of a node as PROMISE. Eg: tree.getChildren('/2/4') .then(function (nodes) { console.log(nodes); // logs 7,8,9 as children of node 4 } using tree.getChildren method, the searchNode method should recursively try to look for searchValue in the tree and return its path if found, null otherwise. The method below, simply