random

Random Pick Index

由 杀马特。学长 韩版系。学妹 提交于 2020-01-20 07:56:51
Random Pick Index Given an array of integers with possible duplicates, randomly output the index of a given target number. You can assume that the given target number must exist in the array. Note: The array size can be very large. Solution that uses too much extra space will not pass the judge. Example: int[] nums = new int[] {1,2,3,3,3};
Solution solution = new Solution(nums);

// pick(3) should return either index 2, 3, or 4 randomly. Each index should have equal probability of returning.
solution.pick(3);

// pick(1) should return 0. Since in the array only nums[0] is equal to 1.
solution

rand() generating same number upon compilation [duplicate]

由 ＊爱你＆永不变心＊ 提交于 2020-01-20 07:52:05
问题 This question already has answers here : Closed 7 years ago . Possible Duplicate: What's the Right Way to use the rand() Function in C++? I've been learning how to use the rand() function and I wrote a small guessing game in C++ as seen bellow, but the problem is, no matter how many times I compile the programs the generated number is the same -> 41 #include <iostream> #include <cstdlib> #include <conio.h> using namespace std; int main() { int x = rand()%100; int y=0; cout << "Ghiceste

398. Random Pick Index随机pick函数

由 坚强是说给别人听的谎言 提交于 2020-01-20 06:59:33
［抄题］： Given an array of integers with possible duplicates, randomly output the index of a given target number. You can assume that the given target number must exist in the array. Note: The array size can be very large. Solution that uses too much extra space will not pass the judge. Example: int[] nums = new int[] {1,2,3,3,3}; Solution solution = new Solution(nums); // pick(3) should return either index 2, 3, or 4 randomly. Each index should have equal probability of returning. solution.pick(3); // pick(1) should return 0. Since in the array only nums[0] is equal to 1. solution.pick(1); [暴力解法

Seeding Multiple Random Number Generators

由 ▼魔方 西西 提交于 2020-01-20 05:04:41
问题 I have recently been discussing the initialisation of multiple random number generators of the same type in the comments of another post and in that discussion we asked the following questions: 1) Is it a good idea to create multiple instances of the same random number generator with different seeds and use these random number generators in different parts of the program? 2) In particular, can the technique of creating random number generators using the .Net Random class, seeded as below, and

Seeding Multiple Random Number Generators

由 大城市里の小女人 提交于 2020-01-20 05:03:16
问题 I have recently been discussing the initialisation of multiple random number generators of the same type in the comments of another post and in that discussion we asked the following questions: 1) Is it a good idea to create multiple instances of the same random number generator with different seeds and use these random number generators in different parts of the program? 2) In particular, can the technique of creating random number generators using the .Net Random class, seeded as below, and

changing probability of getting a random number

由 。_饼干妹妹 提交于 2020-01-19 10:21:11
问题 I would like to generate a random number between 0 and 3 and I have the following in my code: int random = rand() % 4; This works fine but I would like it to generate 1, 2, and 3 most of the time and 0 only occasionally. What is the best way to go about this? What are the names of common algorithms to address this problem? 回答1: Here's one way. Suppose you want 0, 1, 2, 3 to have a distribution of 5%, 20%, 30%, 45%. You could do it like this: double val = (double)rand() / RAND_MAX; int random;

changing probability of getting a random number

由 北战南征 提交于 2020-01-19 10:18:23
问题 I would like to generate a random number between 0 and 3 and I have the following in my code: int random = rand() % 4; This works fine but I would like it to generate 1, 2, and 3 most of the time and 0 only occasionally. What is the best way to go about this? What are the names of common algorithms to address this problem? 回答1: Here's one way. Suppose you want 0, 1, 2, 3 to have a distribution of 5%, 20%, 30%, 45%. You could do it like this: double val = (double)rand() / RAND_MAX; int random;

changing probability of getting a random number

由 孤者浪人 提交于 2020-01-19 10:13:06
问题 I would like to generate a random number between 0 and 3 and I have the following in my code: int random = rand() % 4; This works fine but I would like it to generate 1, 2, and 3 most of the time and 0 only occasionally. What is the best way to go about this? What are the names of common algorithms to address this problem? 回答1: Here's one way. Suppose you want 0, 1, 2, 3 to have a distribution of 5%, 20%, 30%, 45%. You could do it like this: double val = (double)rand() / RAND_MAX; int random;

Random随机数类的使用

由 ﹥＞﹥吖頭↗ 提交于 2020-01-19 05:56:30
import java.util.Random;import java.util.Scanner;public class GuessNumber { public static void main(String[] args) { Random a = new Random(); System.out.println("系统已将完成随机数字的生成！"); int randomNum = a.nextInt(100); Scanner b = new Scanner(System.in); System.out.println("请输入你要猜的数字："); int inputNum = b.nextInt(); while (randomNum != inputNum){ if (inputNum >randomNum){ System.out.println("对不起猜的太大了，请继续输入……"); }else { System.out.println("对不起猜的太小了，请继续输入……"); } System.out.println("请输入你要猜的数字："); inputNum = b.nextInt(); } System.out.println("恭喜你，猜对了！"); }} 来源： https://www.cnblogs.com/wangjixue/p/11542764

SSL/TLS握手过程

由 雨燕双飞 提交于 2020-01-19 01:50:08
1、握手与密钥协商过程 基于RSA握手和密钥交换的客户端验证服务器为示例详解TLS/SSL握手过程 再看一张手绘时序图 (1).client_hello 客户端发起请求，以明文传输请求信息，包含版本信息，加密套件候选列表，压缩算法候选列表，随机数，扩展字段等信息，相关信息如下： • 支持的最高TSL协议版本version，从低到高依次 SSLv2 SSLv3 TLSv1 TLSv1.1 TLSv1.2，当前基本不再使用低于 TLSv1 的版本; • 客户端支持的加密套件 cipher suites 列表， 每个加密套件对应前面 TLS 原理中的四个功能的组合：认证算法 Au (身份验证)、密钥交换算法 KeyExchange(密钥协商)、对称加密算法 Enc (信息加密)和信息摘要 Mac(完整性校验); • 支持的压缩算法 compression methods 列表，用于后续的信息压缩传输; • 随机数 random_C，用于后续的密钥的生成; • 扩展字段 extensions，支持协议与算法的相关参数以及其它辅助信息等，常见的 SNI 就属于扩展字段，后续单独讨论该字段作用。 (2).server_hello+server_certificate+sever_hello_done • server_hello, 服务端返回协商的信息结果，包括选择使用的协议版本
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