query-string

问题 It's difficult to tell what is being asked here. This question is ambiguous, vague, incomplete, overly broad, or rhetorical and cannot be reasonably answered in its current form. For help clarifying this question so that it can be reopened, visit the help center. Closed 6 years ago . I have parsed a JSON response and got the String below : String queryString = "AQB=1&v1=somev1data&v25=somev25data&URL=http://www.someurl.com/configure/getvalues/request1=req1Passed&data2=somedataPassed&ce=UTF-8

问题 It's difficult to tell what is being asked here. This question is ambiguous, vague, incomplete, overly broad, or rhetorical and cannot be reasonably answered in its current form. For help clarifying this question so that it can be reopened, visit the help center. Closed 6 years ago . I have parsed a JSON response and got the String below : String queryString = "AQB=1&v1=somev1data&v25=somev25data&URL=http://www.someurl.com/configure/getvalues/request1=req1Passed&data2=somedataPassed&ce=UTF-8

问题 I'm using tuckey URL rewriting with JSF. I would like to get the relative URL including parameters that the user sees: e.g. example.com/mypage?param=test At the moment if I do #{view.viewId} I get mypage.xhtml what I want to get is: mypage?param=test 回答1: The UIViewRoot#getViewId() returns the JSF view ID. You need to use HttpServletRequest#getRequestURI() to obtain the current request URI and HttpServletRequest#getQueryString() to obtain the current request query string. #{request.requestURI

问题 I'm using tuckey URL rewriting with JSF. I would like to get the relative URL including parameters that the user sees: e.g. example.com/mypage?param=test At the moment if I do #{view.viewId} I get mypage.xhtml what I want to get is: mypage?param=test 回答1: The UIViewRoot#getViewId() returns the JSF view ID. You need to use HttpServletRequest#getRequestURI() to obtain the current request URI and HttpServletRequest#getQueryString() to obtain the current request query string. #{request.requestURI

问题 i have a query that retrieve data from 2 differents server, but once i execute the query i am getting this error Login failed for user 'usr1' i am running the query in server1, with username: usr1 select userid, m.name, Cardid, m.dircode, from [Server1].Database1.dbo.member m JOIN [Server2].Database2.dbo.GetUserDetails p on p.cprno = m.cardid WHERE PerUserName='mftrame' i already provide usr1 read permission on [Server2].Database2.dbo.GetUserDetails also how can i check if i added a link to

问题 this is my apache .htaccess setting with a search page redirect (RewriteRule ^search/(.*)$ /index.php?c=index&m=search&keywords=$1 [L,QSA]), if I set the search query in url without % , it works success request without '%' but if a % char added to the string, apache with return a bad request with % , howerver instead of adding % but %25 , the urlencoded string of % , success request when pre encode % to %25 I want to know about the reason of this situation. I guess in the RewriteRule of

问题 I am trying to make custom query integrated with a plugin to sort posts. Here's the code. index.php $view =$_GET["sort"]; if($view == "views"){ if ( have_posts() ) : $paged = ( get_query_var('paged') ) ? get_query_var('paged') : 1; $args = array('post_type' => 'post', 'meta_key' => '_kksr_avg', 'orderby' => 'meta_value', 'order' => 'desc', 'paged' => $paged, 'posts_per_page' => 5); $query = new WP_Query($args); while ( $query->have_posts() ) : $query->the_post(); // code for display posts

问题 I need help writing a mod rewrite rule to change the name of a query string parameter. I want to change the name, not the value. old name partner new name a_aid so a link like this http://domain.com/?partner=derphipster&pname=foo&plink=http%3A%2F%2Fbar.com%2Ffoo will become http://domain.com/?a_aid=derphipster&pname=foo&plink=http%3A%2F%2Fbar.com%2Ffoo I found this article but the accepted answer generated errors for the OP: mod_rewrite - old parameter name to new name also this article, but

问题 I've been trying to figure out how to submit multiple multi-select values using a redirect or something similar to an index() method/action in my resource controller in Laravel 4. I've made several attempts to achieve this but have yet to work out how to do it. I initially had it submitting to a query string, which worked to a certain extent but as soon as you selected more than 1 value in a single multi-select box, it wouldn't work, as it simply chose to use the last value. This is the form

问题 I'm trying to set up a system on my site so that users who come through a custom link get tagged with a cookie that triggers a specific code to replace the default part of a signup form. The desired result is, in this example, for someone coming to http://example.com/?=mylink1 getting tagged with a cookie that changes the "value" attribute in any inputs with id #xcode to "X190". What I have so far: Create cookie from query string: function cookieQuery() { var url = window.location.href; if