How to parse this queryString which is a resultant of JSON response [closed]

问题

It's difficult to tell what is being asked here. This question is ambiguous, vague, incomplete, overly broad, or rhetorical and cannot be reasonably answered in its current form. For help clarifying this question so that it can be reopened, visit the help center.

Closed 6 years ago.

I have parsed a JSON response and got the String below :

String queryString = "AQB=1&v1=somev1data&v25=somev25data&URL=http://www.someurl.com/configure/getvalues/request1=req1Passed&data2=somedataPassed&ce=UTF-8&ARB=1";

When i split the above queryString the output should be :

AQB=1
v1=somev1data
v25=somev25data
URL=http://www.someurl.com/configure/getvalues/request1=req1Passed&data2=somedataPassed
ce=UTF-8
ARB=1

NOTE :
queryString always changes and the URL parameters also always changes. AQB,v1.....v30,p1....p30,ce,pre,pe,URL,ARB are all the predefined variable names.

回答1:

It is NOT possible unless the URL parameter is properly URL-encoded, so the "&" characters will be escaped in order not to be interpreted as field separators.

The string should be encoded like this:

String queryString = "AQB=1&v1=somev1data&v25=somev25data&URL=http%3A%2F%2Fwww.someurl.com%2Fconfigure%2Fgetvalues%2Frequest1%3Dreq1Passed%26data2%3DsomedataPassed&ce=UTF-8&ARB=1";

As it is formatted in your question, the string cannot be parsed successively.

回答2:

StringTokenizer st = new StringTokenizer(queryString, "&");
while (st.hasMoreTokens()) {
  System.out.println(st.nextToken());
}

As another poster suggests, the only thing now left is to take care of the URL

来源：https://stackoverflow.com/questions/16543676/how-to-parse-this-querystring-which-is-a-resultant-of-json-response