pywinauto

问题 What I'm trying to do: I'm trying to create a script in python with pywinauto to automatically install notepad++ in the background (hidden or minimized), notepad++ is just an example since I will edit it to work with other software. Problem: The problem is that I want to do it while the installer is hidden or minimized, but if I move my mouse the script will stop working. Question: How can I execute this script and make it work, while the notepad++ installer is hidden or minimized. This is my

问题 I tried using pywinauto for python 2.7. The installation went as expected using pip. But when I try to import pywinauto package in python I following error: Python 2.7.13 (v2.7.13:a06454b1afa1, Dec 17 2016, 20:53:40) [MSC v.1500 64 bit (AMD64)] on win32 Type "help", "copyright", "credits" or "license" for more information. >>> import pywinauto Traceback (most recent call last): File "<stdin>", line 1, in <module> File "pywinauto\__init__.py", line 40, in <module> from . import findwindows

问题 I have been using pywinauto for opening a command prompt (Mingw-64) and was passing commands using type_keys It was working properly in my local system but, when i hosted my code into RDP server, i am not able to restore the window and pass the commands when RDP is in minimized state Please give me a proper solution and let me know if any package does the same purpose. Thanks! 回答1: There are several points to improve. It's better to use standard Python module subprocess with stdin re

问题 I am working on the Automation of loading an image file in "Oracle VM Virtual box" to create a virtual machine using Pywinauto in python. I am able to automate the installation of Virtual Box software & after that able to launch the exe also shown in the image But after that I am not able to do any GUI operation on "Oracle VM VirtualBox Manager" (e.g.Selecting File Menu or click New button) automatically using Pywinauto. I have attached the snapshot of Inspect tool for Oracle VM Virtual box

问题 I am performing automation testing of an application using pywinauto . It worked successfully for every window of the app, but for some reason it fails to click the buttons on the install wizard, on Windows 8 and Windows 10. It works on Windows 7. Tested with python 2.7.10.amd64 pywinauto 0.5.3 Windows 10 x64 I can get the button coordinates, text, and every other info, however I cannot perform any action on it (click, press key) The error I get is: File "C:\Python27\Lib\site-packages

问题 I work as a test engineer. I have to test an application(softphone) which is done by using QWidget. I'm using python - pywinauto. I can click buttons and make calls. There is a qwidget object named with statusLabel. At the beginning of the test, "Ready" text written on it. When I make a call, this text is changed like "Calling..", "Call Established" and so on. I want to check the text of that widget. Do you have any idea? 回答1: Pywinauto uses standard windows API calls. Unfortunately many UI

问题 I am new to pywinauto and I don't know how to use control identifiers. How would I set No. of loops: to 99999? 回答1: For dynamic edit box you can use label text as a part of identifier. Examples: app.WindowName.No__of_loops_Edit.set_text('99999') # or app.WindowName['No. of loops:Edit'].set_text('99999') # for more realistic typing char by char: app.WindowName['No. of loops:Edit'].type_keys('99999') It's described in more details in the Getting Started Guide (section "How to know magic

问题 I'm doing automation scripting in Python for my desktop application. In that I'm sending TAB key/any key to my windows form. But I'm not able to find handle of that Windows form in my Python script. Here is the sample code snippet : __author__ = 'juhis' import SendKeys import sys import os from Tkinter import * import ctypes import win32gui import pywinauto pwapp = pywinauto.application.Application() whandle = pywinauto.findwindows.find_windows(title_re='Form1',class_name='WindowsForms10

问题 I used the below code to connect a opened window(Class type is SunAwtFrame), indeed I able to connect to it. but unable to click next button of it, my doubt is that 'Next' button may reside inside the frame of that window. Even when I use 'swapy' tool, I am unable to navigate through the controls, indeed not showing the controls actually. So, how to switch to frame if it is that case and click the 'Next' button. app2 = application.Application() app2.connect(title_re = u'abc') dialog = app2

问题 from pywinauto import application app = application.Application.start("C:\\Program Files\\Microsoft Office\\Office12\\EXCEL.exe") app.Microsoft_Excel.TypeKeys('%a') %a = Alt + a I Want Ctrl + a . is there a sign for this? 回答1: You must use Control key specifier - ^ , so try: app.Microsoft_Excel.TypeKeys('^a') You can get documentation on SendKeys mini-syntax here or here. 回答2: U can use: send_keys('^a') 来源： https://stackoverflow.com/questions/12056590/how-to-press-ctrl