prepared-statement | 易学教程

try and catch with a prepared statement

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问题 I have had a very hard time with this query and it was suggested to me to learn try and catch blocks to more easily figure out what is wrong. So this is my first attempt at it. I am getting the error for my @stmt2 not being defined for my print_r($stmt2) line. Notice: Undefined variable: stmt2 This is my attempt at the try catch. Am I doing anything wrong with it for this error to come up? try { $con = mysqli_connect("localhost", "", "", ""); if (mysqli_connect_errno()) { throw new Exception(

PDO prepared statement with optional parameters

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I'm kind of new with PDO and currently developing the API call that returns search results. How do I set a prepare statement if there are 2 optional parameters for the search query? $app->get('/get/search', function () { $sql = 'SELECT * FROM user WHERE name LIKE :name AND city = :city AND gender = :gender'; try { $stmt = cnn()->prepare($sql); $stmt->bindParam(':name', '%'.$_GET['name'].'%', PDO::PARAM_STR); $stmt->bindParam(':city', '%'.$_GET['city'].'%', PDO::PARAM_STR); $stmt->bindParam(':gender', $_GET['gender'], PDO::PARAM_INT); $stmt->execute(); if($data = $stmt->fetchAll()) { echo json

Getting error on binding param in select statement in MySQLi

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问题 I have added a select snippet below. Why am I getting the following error on bind_param() ? Uncaught Error: Call to a member function bind_param() on boolean Code: $sessien = $_POST['xsession']; $conn = new mysqli(DB_SERVER, DB_USERNAME, DB_PASSWORD, DB_NAME); $query = "SELECT `post` FROM `user` WHERE session=? ORDER BY `thedate` DESC "; $stmt = $conn->prepare($query); $stmt->bind_param("s", $sessien); $stmt->execute(); while ($stmt -> fetch()) { echo "$post<br>"; } $stmt->close(); $conn-

Fatal error: Call to a member function prepare() on null

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问题 I'm getting this error and i can't find whats wrong. I've read through the other posts about this error but none of them seemed to help. Fatal error: Call to a member function prepare() on null on line 92 <?php include 'config.php'; $lengd = $_POST["lengd"]; $height = $_POST["height"]; $width = $_POST["width"]; $min_lengd = $lengd * 0.9; $max_lengd = $lengd * 1.1; $min_height = $height * 0.9; $max_height= $height * 1.1; $min_width = $width * 0.9; $max_width= $width * 1.1; $sql = "SELECT lengd

When executing command.Prepare() I have “SqlCommand.Prepare method requires all parameters to have an explicitly set type” error

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问题 I have the following statements: SqlConnection con = new SqlConnection(ConfigurationManager.AppSettings["DataBaseName"]); SqlCommand cmd = new SqlCommand(); cmd.Connection = con; cmd.CommandText = "update Table1 set data = @data where id = @id"; cmd.Parameters.AddWithValue("@data", SqlDbType.VarChar).Value = data; cmd.Parameters.AddWithValue("@id", SqlDbType.Int).Value = id; cmd.CommandType = CommandType.Text; try { DataSet ds = new DataSet(); con.Open(); cmd.Prepare(); cmd.ExecuteNonQuery();

MySQL Prepare Statement - Maximum Length 1000 Characters

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问题 I have an SQL statement which exceeds 1000 characters that I'm using through prepare method - is there anyway to extend this value marginally? Once I use the prepare command it truncates the SQL to 1000 characters, similarly if I just select the variable holding the sql string this also is truncated in output. In addition to the core SQL there could be any number of additional queries added on. I suppose I could create a view and then select from the view, however views in MySQL are a little

PreparedStatement: How to insert data into multiple tables using JDBC

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Could somebody tell me whether the first stmt.close(); required in the following JDBC code, for executing two different SQL queries against two different tables? public class MyService { private Connection connection = null; public void save(Book book) { try { Class.forName("com.mysql.jdbc.Driver"); connection = DriverManager.getConnection("jdbc:mysql://localhost:3306/mydb", "root", "password"); PreparedStatement stmt = connection.prepareStatement("INSERT INTO PUBLISHER (CODE, PUBLISHER_NAME) VALUES (?, ?)"); stmt.setString(1, book.getPublisher().getCode()); stmt.setString(2, book.getPublisher

How to insert multiple rows in a mysql database at once with prepared statements?

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I am trying to use staticsan´s answer in this question for prepared statements. Lets take this example: $stmt = $mysqli->prepare("INSERT INTO something (userid, time, title) VALUES (?, ?, ?)"); $stmt->bind_param('iis', $userid, time(), $title); $stmt->execute(); In staticsan´s answer imploding the array is adding all the values into the mysql statement so that in the end we can insert multiple data into the database with just one statement. How would this be done in my example? This is completely valid: $stmt = $mysqli->prepare("INSERT INTO something (userid, time, title) VALUES (?, ?, ?)");

Does pg_prepare() prepared statement (not PDO) prevent SQL-Injection?

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问题 PDO ist not supported in target system I'm working on and though I seek a solution for preventing SQL-Injection using PHP 5.1.x on a PostGres-DB 8.2+ . There is at the moment no chance of switching to PDO. My solution at the moment is pg_prepare-prepared statement: // Trying to prevent SQL-Injection $query = 'SELECT * FROM user WHERE login=$1 and password=md5($2)'; $result = pg_prepare($dbconn, "", $query); $result = pg_execute($dbconn, "", array($_POST["user"], $_POST["password"])); if (pg

How to do MySQL IN clauses using Zend DB?

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I'm trying to fetch rows that are in an array of integers that I have using Zend Framework 1.11. $this->dbSelect ->from($table_prefix . 'product_link') ->joinLeft($table_prefix . 'product_link_name', $table_prefix . 'product_link.product_link_name_ref_id = ' . $table_prefix . 'product_link_name.product_link_name_id') ->where('product_ref_id IN (?)', implode(', ', $product_ids)); When I use the __toString() method of $this->dbSelect , I get SELECT `phc_distrib_product_link`.*, `phc_distrib_product_link_name`.* FROM `phc_distrib_product_link` LEFT JOIN `phc_distrib_product_link_name` ON phc