prepared-statement

问题 Okay I can't get this figured out. I want a logged in user to update a row with an amount (INT), I keep getting the invalid parameter error as well as a Call to member function execute() on a non-object. Here is the php and html that should update the db <?php ini_set("log_errors", 1); ini_set("error_log", "/tmp/php-error.log"); session_start(); require_once 'class.user.php'; $user_home = new USER(); if(!$user_home->is_logged_in()) { $user_home->redirect('index.php'); } $stmt = $user_home-

问题 EDIT: after reading all the input from the other users, i decided, to use what @chris suggested call_user_func_array() one more reason not to use eval() its slower than call_user_func_array() , but so far, nobody was able to exploit it my way, if you find a way, please post it as answer or comment :). So everybody can learn from it. Merry XMAS to all! ---EDIT END--- Ok i needed to make a dynamic code: I get user input like $_POST['a'], $_POST['b']; // Depends on each query how many user input

问题 what if I want to update data via prepared stmt each query loop, but why fails. the error msg is "All data must be fetched before a new statement prepare takes place " $link = mysqli_connect("localhost", "admin", "", "test"); if (!$link) { die('Connect Error: ' . mysqli_connect_error()); } //field_1 is PK if ($stmt = mysqli_prepare($link, "SELECT field_1, field_2 FROM table_data")) { mysqli_stmt_execute($stmt); mysqli_stmt_bind_result($stmt, $col1, $col2); while (mysqli_stmt_fetch($stmt)) {

问题 I have tried setting sessions which are stored in database.I have achieved this through implementing SessionHandlerInterface class.However i havenot used prepared statements before but now i want to implement prepared statements in order to make it sql injection proof.However , when i try the prepare method it shows me an error Method Prepare not defined in Class i even tried extending mysqli_stmt class which contains the methods for prepared statements. This is the full code of session class

问题 this is my insertion method in PDO, it is working 100%. this 'insert' method accepts table, column and value but i want to make it versatile. (i want to insert values with or without the column names) public function insert($table, $pair = array()){ try{ $Sql = "INSERT INTO $table ( "; $Sql .= implode(", ", array_keys($pair)); $Sql .= " )"; $Sql .= " VALUES ("; $Sql .= implode(", ", array_fill("0", count($pair), " ?")); $Sql .= " )"; $array = array_combine(array_keys(array_fill("1", count(

问题 I have the following query to obtain an average of a data of the 52 weeks of the year as follows: $dates = array(); $firstDate = date("Y-m-d", strtotime('first day of January 2016')); $lastDate = date("Y-m-d", strtotime('last day of December 2016')); for($i=strtotime($firstDate); $i<=strtotime($lastDate); $i+=86400 *7){ array_push($dates, date("Y-m-d", strtotime('monday this week', $i))); } for($i = 0; $i < count($dates); $i++){ $sql = "SELECT pr_products.product, CONCAT(YEAR('".$dates[$i]."'

问题 I'm using a prepared statment that should (using SQL & JDBC) insert data into a dataTable. I am using one that deletes data that works fine, but the insert one is not inserting any data into the data table and does not produce an error or warning. What could cause a prepared statement to fail in this way? Could inserting a null value into the prepared statement cause this? 回答1: What do you mean by "failing, but does not produce an error"? How do you know it's failing then - is data not

问题 I am trying to encrypt a password in SQL Server and I'm getting two different results when I use a string vs. using a prepared statement parameter. For example: SELECT sys.fn_varbintohexstr(HASHBYTES('sha1', ?)), sys.fn_varbintohexstr(HASHBYTES('sha1', 'password')) Where the ? is populated by 'password'. It gives me 0xe8f97fba9104d1ea50479... 0x5baa61e4c9b93f3f06822... Why am I getting two different results for what should be the same thing? Also, this is only happening in SQL Server, if I do

问题 I wrote a query of the form: select .... where x.y in (?) union select .... where p.y in (?) and a.b not in (?) The question marks indicate places where I put multiple values at run time (dynamically putting values in the IN clause) using the preparedStatement.setString() method. The resultset, on executing this query seems to ignore the query after the union clause. I get no exception anywhere. I post this question, just to know if anyone else has faced such a problem, like this link

问题 Are PHP/mysql prepared statements possible when mysqli and PDO are not available? Are there working Pear solutions for this problem? 回答1: http://pear.php.net/manual/en/package.database.mdb2.intro-execute.php That should contain all the information you need. Otherwise, the standard mysql_* functions do not provide functionality for prepared statements. 来源： https://stackoverflow.com/questions/11089862/prepared-statements-possible-when-mysqli-and-pdo-are-not-available