prepared-statement

问题 I understand mysql_ has been deprecated, but I'm just using it as a tool to learn from a book. I'm trying to learn about placeholders and I got the following error when I clicked on "add record": INSERT failed: EXECUTE statement USING @first,@last,@email,@user Unknown prepared statement handler (statement) given to EXECUTE using the following code: if (isset($_POST['first']) && isset($_POST['last']) && isset($_POST['user_name']) && isset($_POST['email'])) { $first = get_post('first'); $last =

问题 In PreparedStatement which method i need to use execute the class I write a method like public Text getMessage(){ return message; } In my class PreparedStatement ps; ps=con.prepareStatement("insert into tblmessage (message) values(?)"); ps.setString(2, usermsgmodel.getMessage()); ps.executeUpdate(); i got an error in this line saying that "the method getMessage return type is Text, So you setString property cannot accommodate Text value " ps.setString(1, usermsgmodel.getMessage()); 回答1: Try

问题 I have data in a wp_users table, and I want to duplicate the data from that table (except for the ID column) into another table, called wp_users2 . If I didn't care about the id column, which I want to auto-increment, I could just do this: insert into wp_users2 (select *, NULL as ID from wp_users) So I know I could do this by typing out all of the column headers except for ID and manually selecting that one as NULL, SELECT NULL as id, col2, col3... but I'd like to do it dynamically. I read

问题 I've been sanitising my inputs using mysql_real_escape_string amongst other functions and have recently read that Prepared Statements are the only way to be truly secure. However I am reluctant to use these for two reasons: I don't want to rewrite code and I read that using them can have an impact on performance (queries are used extensively in this application). So I am looking for a recent , concrete example of where mysql_real_escape_string fails in a query and the resolution is to use

问题 A PDO prepared update statement is somehow updating the datetime column for the selected record in the table, even though that particular datetime column is not even in the query. if(isset($_POST['editCriteria'])) { $value = $_POST['editCriteria']; $editusername = $value['editusername']; $hiddenUsername = $value['hiddenUsername']; $editfullname = $value['editfullname']; $editemail = $value['editemail']; $edituserlevel = $value['edituserlevel']; $editdivision = $value['editdivision'];

问题 I usually use this code to read/get the result of an prepared MySQL SELECT: $sqlname = $conn->prepare("SELECT name FROM test1 WHERE test2 = ?"); $sqlname->bind_param('s',$test); $sqlname->execute(); $result = $sqlname->get_result(); if ($result->num_rows > 0) { while($row = $result->fetch_assoc()) { $testname = $row['name']; } } But when I know that there will only be one row in the result: Do I have to use a while loop with fetch_assoc anyway or is there a better way? 回答1: When you know the

问题 I'm trying to understand a (probably) basic procedure but I think I'm missing something. So I used a prepared statement to get some data from a mysql database: <select> <?php $select_item_name = "select * from item order by item_name ASC"; $run_item = mysqli_query($con, $select_item_name); while($row=mysqli_fetch_array($run_item)){ $item_id = $row['item_id']; $item_name = $row['item_name']; $item_price = $row['item_price']; $item_desc = $row['item_desc']; echo "<option value='$item_desc'>

问题 There is a good way to use a prepared statement in java where there is the possibility to have a probability that some parameter can be or not be set? Let's assume I have a complete query like this one: SELECT * FROM Table1 WHERE Field1='....' AND Field2='....' AND Field3='....' Then in my program I would like to do something like that (I know it's not possible the way I write) // part of code where I have 3 variable set by some logic and the query itself //......... String Query = "SELECT *

问题 Let's say I have a table T_SWA.This is my prepared statement. Select version From (Select id, version, creator, created_date ROW_NUMBER() OVER(order by created_date) cnt From T_SWA Where cnt=3 and id=35); I need to select the 3rd recent version from the T_SWA table. Can anyone suggest a replacement for this query without using ROW_NUM() and OVER() functiions? 回答1: First take the three most recent and then from those three take the first. select id, version, creator, created_date from ( select

问题 I have to fetch country name twice in the single page. I have four dropdowns which is country_1,state_1, country_2, state_2. In the country, User select the country name and according to the country name, state name will display. If I use only country_1, state_1 then I am able to display it but I need both countries dropdown on the same page. I tried $stmt->data_seek($stmt,0); $stmt->data_seek(0); but still not able to display it. I just want to know where should I use the data_seek <!-