pow

问题 Closed. This question does not meet Stack Overflow guidelines. It is not currently accepting answers. Want to improve this question? Update the question so it's on-topic for Stack Overflow. Closed 6 years ago . Improve this question Hi I want to write a code for a pow function without using math.h libary. How is this code?how can i fix it when b<0 int MyPow(int a,int b){ if(b<0) return 1 / MyPow (a,-b) else if(b==0) return 1; else if(b==1) return a; else return a*MyPow(a,b-1) } 回答1:

问题 I have a function that deals with arbitrarily large grids. I need to compute if a grid to the power of another number will fit into a double due to using std::pow . If it cannot, I want to take a different branch and use gnu multiprecision library instead of normal. Is there a quick way to see if: int a = 1024; int b = 0-10; if(checkPowFitsDouble(a, b)) { long c = static_cast<long>(std::pow(a, b)); //this will only work if b < 6 } else { mpz_t c; //yada yada gmp } I am completely stumped on

问题 Question more or less says it all. calling a host function("std::pow<int, int> ") from a __device__/__global__ function("_calc_psd") is not allowed from my understanding, this should be using the cuda pow function instead, but it isn't. 回答1: The error is exactly as the compiler is reported. You can't used host functions in device code, and that include the whole host C++ std library. CUDA includes its own standard library, described in the programming guide, but you should use either pow or

来源： https://stackoverflow.com/questions/17351438/why-is-the-pow-function-slower-than-simple-operations

来源： https://stackoverflow.com/questions/17351438/why-is-the-pow-function-slower-than-simple-operations

问题 I'm testing a small C# program fragment: short min_short = (short)(int)-Math.Pow(2,15); short max_short = (short)(int)(Math.Pow(2, 15) - 1); Console.WriteLine("The min of short is:{0};\tThe max of short is:{1}", min_short, max_short); int min_int = (int)-Math.Pow(2, 31); int max_int = (int)(Math.Pow(2, 31) - 1); Console.WriteLine("The min of int is:{0};\tThe max of int is:{1}", min_int, max_int); uint min_uint = 0; uint max_uint = (uint)(Math.Pow(2, 32) - 1); Console.WriteLine("The min of

问题 This is kind of obscure, but I need a function that can be computed very quickly and resembles a^b where a is between 0 and 1 and b is very large. It will be calculated for one a at a time for many b's. Ideally, the result would be within 0.4%. Thanks in advance. 回答1: Pulling my comments into an answer: Since you mention that b is large enough to be rounded to an integer, then one approach is to use the Binary Exponentiation algorithm by squaring. Math.pow() is slow because it needs to handle

问题 I'm programming for a while now(beginner), and recursive functions are a somewhat abstract concept for me. I would not say I'm stuck, program works fine, I'm just wondering if the function itself could be written without the pow function in the code (but still doing exactly what the problem suggests) Problem: http://prntscr.com/30hxg9 My solution: #include<stdio.h> #include<math.h> int power(int, int); int main(void) { int x, n; printf("Enter a number and power you wish to raise it to: ");

问题 I'm having a problem with C#. To be precise with the Math.pow(). If I try to calculate 15^14 then I get "29192926025390624". But if I calculate it with Wolfram Alpha I get "29192926025390625". As you can see this only difference is 1 number. Wolfram Alpha is correct though. Why isn't C# ? and how do I fix this so I can get the correct value in C# ?7 My code is fairly simple since I'm just trying with hardcoded examples. So what I'm doing is : Math.Pow(15,14); This gives 29192926025390624 .

问题 I have do to a question to write a method to input an array of type LONG that stores the values of all the powers of 2 from 0 to 63 (i.e. 2 0 to 2 63 ) Output the contects of the array screen. Hint: Math.pow(x,y) is ued to put number x to exponent y so far I have something like I keep getting error or Math.pow(size,2); required long, found double. I tried Math.pow(i,2); I get same error./ possible loss of precision ,, any help :) thanks class ws3q2 { public static void main(String[]args) {