poison

1228.Poor Pigs 可怜的猪

∥☆過路亽.° 提交于 2020-03-05 12:44:54
转自 [LeetCode] Poor Pigs 可怜的猪 There are 1000 buckets, one and only one of them contains poison, the rest are filled with water. They all look the same. If a pig drinks that poison it will die within 15 minutes. What is the minimum amount of pigs you need to figure out which bucket contains the poison within one hour. Answer this question, and write an algorithm for the follow-up general case. Follow-up: If there are n buckets and a pig drinking poison will die within m minutes, how many pigs (x) you need to figure out the "poison" bucket within p minutes? There is exact one bucket with poison.

458. Poor Pigs

北慕城南 提交于 2020-03-04 03:50:01
There are 1000 buckets, one and only one of them contains poison, the rest are filled with water. They all look the same. If a pig drinks that poison it will die within 15 minutes. What is the minimum amount of pigs you need to figure out which bucket contains the poison within one hour. Answer this question, and write an algorithm for the follow-up general case. Follow-up: If there are n buckets and a pig drinking poison will die within m minutes, how many pigs (x) you need to figure out the "poison" bucket within p minutes? There is exact one bucket with poison. N个桶,一只猪喝了会在minutesToDie分钟内死亡

[LeetCode&Python] Problem 458. Poor Pigs

爱⌒轻易说出口 提交于 2020-03-04 03:40:05
There are 1000 buckets, one and only one of them contains poison, the rest are filled with water. They all look the same. If a pig drinks that poison it will die within 15 minutes. What is the minimum amount of pigs you need to figure out which bucket contains the poison within one hour. Answer this question, and write an algorithm for the follow-up general case. Follow-up: If there are n buckets and a pig drinking poison will die within m minutes, how many pigs (x) you need to figure out the "poison" bucket within p minutes? There is exact one bucket with poison. With 2 pigs, poison killing

[Swift]LeetCode458. 可怜的小猪 | Poor Pigs

ぐ巨炮叔叔 提交于 2020-03-04 03:24:18
★★★★★★★★★★★★★★★★★★★★★★★★★★★★★★★★★★★★★★★★ ➤微信公众号:山青咏芝(shanqingyongzhi) ➤博客园地址:山青咏芝( https://www.cnblogs.com/strengthen/ ) ➤GitHub地址: https://github.com/strengthen/LeetCode ➤原文地址: https://www.cnblogs.com/strengthen/p/9791579.html ➤如果链接不是山青咏芝的博客园地址,则可能是爬取作者的文章。 ➤原文已修改更新!强烈建议点击原文地址阅读!支持作者!支持原创! ★★★★★★★★★★★★★★★★★★★★★★★★★★★★★★★★★★★★★★★★ There are 1000 buckets, one and only one of them contains poison, the rest are filled with water. They all look the same. If a pig drinks that poison it will die within 15 minutes. What is the minimum amount of pigs you need to figure out which bucket contains the

【Unity】Unity中的枚举和标志

对着背影说爱祢 提交于 2019-12-03 15:11:47
原文链接 :http://unity3d.9tech.cn/news/2014/0410/40176.html 枚举和标志 今天的主题是枚举,它是C#语言中的一个很有帮助的工具,可以增强代码的清晰度以及准确性。 枚举一系列值 C#中最经常使用枚举的地方就是用来定义一系列可能值的时候。例如在制作一个角色类游戏中,角色有多个不同的状态效果。可以用一些基本的方式来定义玩家可能的状态效果: using UnityEngine; public class Player : MonoBehaviour { public string status; void Update() { if (status == "Poison") { //Apply poison effect } else if (status == "Slow") { //Apply slow effect } else if (status == "Mute") { //Apply mute effect } } } 此处我们用一个简单的if-else检测来查看应用的是哪个状态效果,哪个运行良好。但是如果你想应用一个状态效果,但是突然写成这样: //Oops, I spelled "Poison" wrong! status = "Pioson"; 突然,就不会有什么状态效果了。我们会利用if

Azure: How to move messages from poison queue to back to main queue?

匿名 (未验证) 提交于 2019-12-03 08:48:34
可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效,请关闭广告屏蔽插件后再试): 由 翻译 强力驱动 问题: I'm wondering if there is a tool or lib that can move messages between queues? Currently, i'm doing something like below public static void ProcessQueueMessage ([ QueueTrigger ( "myqueue-poison" )] string message , TextWriter log ) { CloudStorageAccount storageAccount = CloudStorageAccount . Parse ( connString ); CloudQueueClient queueClient = storageAccount . CreateCloudQueueClient (); CloudQueue queue = queueClient . GetQueueReference ( "myqueue" ); queue . CreateIfNotExists (); var messageData = JsonConvert . SerializeObject (

LeetCode-Poor_Pigs

匿名 (未验证) 提交于 2019-12-03 00:18:01
题目: There are 1000 buckets, one and only one of them contains poison, the rest are filled with water. They all look the same. If a pig drinks that poison it will die within 15 minutes. What is the minimum amount of pigs you need to figure out which bucket contains the poison within one hour. Answer this question, and write an algorithm for the follow-up general case. Follow-up: If there are n buckets and a pig drinking poison will die within m minutes, how many pigs (x) you need to figure out the "poison" bucket within p minutes? There is exact one bucket with poison. 翻译: 那里有1000个桶,其中只有一个装的是毒药