player

Android How to obtain media player progress bar and also how to show it on each activity top screen

匿名 (未验证) 提交于 2019-12-03 07:36:14
可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效,请关闭广告屏蔽插件后再试): 问题: Am working on certain app XYZ. In that app having a audio player module. I launch a player launch from an activity using some following code: playButton = (ImageButton) findViewById(R.id.play_image_button); playButton.refreshDrawableState(); playButton.setOnClickListener(new OnClickListener() { public void onClick(View arg0) { if (playCount % 2 == 0) { if (Data.songProfileArrayList.size() > 0) { SongProfileBean songData = Data.songProfileArrayList .get(0); if ("audio".equals(songData.getSongFileType())) { playButton .setBackgroundResource(R

Soundcloud custom player add and play song dynamically

匿名 (未验证) 提交于 2019-12-03 07:36:14
可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效,请关闭广告屏蔽插件后再试): 问题: I am using soundcloud custom player to create a player which can play all the songs on my site. This works pretty good when i just place static url of any track or a post. But what i want is to add the song to the list dynamically. I have done lots of research but couldn't get it to work. What i want is there would be multiple players through out the site. kind of( http://soundcloud.com ) and there would a main player on the top(like soundcloud) which would play around 100 latest songs on site and there would be a smaller player clicking on

ACM-ICPC 2018 南京赛区网络预赛 C. GDY [ 模拟 ]

霸气de小男生 提交于 2019-12-03 05:54:39
题目链接: ACM-ICPC 2018 南京赛区网络预赛 C. GDY 题意概括: 有 n 个仓鼠玩牌。有 13 种牌面分别标着整数 1至13 。现在有 m 张牌叠在一起(会有重复的牌),规则如下: 先轮流摸牌一次,每次摸 5 张。牌的数量保证每只仓鼠都有至少一张牌。因此最后一只可能只能拿到少于 5 张的牌,但不会没牌 第 1 位首先出其牌面数字最小的牌,后一位出牌面刚好大 1 的牌。也就是说,当前只能出比前一张大一的牌或牌 2 。大小关系: 只要前一张牌不是 2 ,牌 2 在任何时候都可以出,不需要满足刚好比前一张牌大 1 若当前有牌可出,则一定要打出。若无牌可出则什么都不用做。 若第 X 位出了牌后,其他几位的都无牌可出,经过一轮又回到 X 时: 从 X 开始轮流抽一张牌,若到某位没有牌了,则跳过不抽。抽完后,从 X 开始,出其牌面最小的牌,以此循环 数据范围: 题解分析: 就是纯模拟题,看懂题面就完成了一大半。为了方便操作,这里维护一个二维数组 int player[MAXN][14] player[i][j] 表示的是第 i 位拥有牌面为 j 的牌的数目 一定要仔细啊,有很多细节会出错。比赛的时候没找出错在哪里,赛后队友帮我debug出来的 AC代码: #include <stdio.h> #include <memory.h> using namespace std;

how to implemenent android video player in full screen

匿名 (未验证) 提交于 2019-12-03 03:12:02
可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效,请关闭广告屏蔽插件后再试): 问题: i have implemented android video player , but i don't need like this how i need mean when opening activity i need to pay video half screen in center when i click button full screen button then i need t pay in full screen , how to implement it help me.... VideoPlayerActivity public class VideoPlayerActivity extends Activity implements SurfaceHolder.Callback, MediaPlayer.OnPreparedListener, VideoControllerView.MediaPlayerControl { SurfaceView videoSurface; MediaPlayer player; VideoControllerView controller; @Override protected void onCreate

audioPlayerDidFinishPlaying never triggers

匿名 (未验证) 提交于 2019-12-03 03:08:02
可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效,请关闭广告屏蔽插件后再试): 问题: I created a custom class to handle audio playback. AudioPlayback.h #import <Foundation/Foundation.h> #import "AVFoundation/AVAudioPlayer.h" #import <AVFoundation/AVFoundation.h> @interface AudioPlayback : NSObject <AVAudioPlayerDelegate> { AVAudioPlayer *player; BOOL playing; NSTimeInterval duration; } @property (nonatomic, assign) AVAudioPlayer *player; @property (readonly) BOOL playing; @property (readonly) NSTimeInterval duration; -(NSTimeInterval)GetSoundFileDuration:(NSString *) sound_file_name; -(void)PlaySoundFile:(NSString *) sound

How to join two DataFrames in Scala and Apache Spark?

匿名 (未验证) 提交于 2019-12-03 03:06:01
可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效,请关闭广告屏蔽插件后再试): 问题: There are two DataFrames (Scala, Apache Spark 1.6.1) 1) Matches MatchID | Player1 | Player2 -------------------------------- 1 | John Wayne | John Doe 2 | Ive Fish | San Simon 2) Personal Data Player | BirthYear -------------------------------- John Wayne | 1986 Ive Fish | 1990 San Simon | 1974 john Doe | 1995 How could create a new DataFrame with 'BirthYear' for the both players MatchID | Player1 | Player2 | BYear_P1 |BYear_P2 | Diff ------------------------------------------------------------- 1 | John Wayne | John Doe | 1986 | 1995 | 9 2

HTML5 video/audio player control play &amp; pause with AngularJS

匿名 (未验证) 提交于 2019-12-03 03:03:02
可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效,请关闭广告屏蔽插件后再试): 问题: I want to control HTML5 audio/video player with AngularJS. I want to play & pause that player. I can do this using jQuery. But I need it to work with AngularJS. 回答1: https://github.com/2fdevs/videogular creating your own custom directive can does the job for you (Preferred and reusable), The simplest way is using angular.element and selecting the required video element from the DOM using its functionalities. <video autoplay="autoplay" preload="auto" ng-click="pauseOrPlay()"> <source src="{{url }}" type="video/mp4" /> </video> //controller

scrapy how spider returns value to another spider

匿名 (未验证) 提交于 2019-12-03 03:03:02
可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效,请关闭广告屏蔽插件后再试): 问题: The website that I am crawling contains many players and when I click on any player, I can go the his page. The website structure is like this: <main page> <link to player 1> <link to player 2> <link to player 3> .. .. .. <link to payer n> </main page> And when I click on any link, I go to player's page which is like this: <player name> <player team> <player age> <player salary> <player date> I want to scrap all the players those age is between 20 and 25 years. what I am doing scraping the main page using first spider . getting links using

HTML5 video player prevent seeking

匿名 (未验证) 提交于 2019-12-03 02:56:01
可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效,请关闭广告屏蔽插件后再试): 问题: I'm creating a series of video tutorials and would like to prevent users from seeking forward and skipping sections. I'll be using an HTML5 video player that will be used for desktop and iPad browsers. Ideally, I'd like this to work on the iPhone as well, but I realize you have no control over the video on the phone since it uses the iPhone video player. How can I prevent users from seeking forward on an HTML5 video player? 回答1: Another example for Video.js: videojs('example_video_1').ready(function(){ var player = this; var previousTime = 0

Tic Tac Toe and Minimax - Creating an imperfect AI on a microcontroller

匿名 (未验证) 提交于 2019-12-03 02:56:01
可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效,请关闭广告屏蔽插件后再试): 问题: I have created a Tic-Tac-Toe game on a microcontroller, including a perfect AI (perfect meaning that it doesn't lose). I did not use a minimax algorithm for that, just a little state machine with all possible and optimal moves. My problem now is that I wanted to implement different difficulties (Easy, Medium and Hard). The AI so far would be the hard one. So I've thought about how to do this the best way and ended up wanting to use the minimax algorithm but in a way that it calculates all the scores for all game positions so that I can also