partitioning

Mysql table partition based on last digit of a column/id

好久不见. 提交于 2019-12-02 01:42:45
I want to create partitions based on last digit of employee id, i.e all ids ending with 0 go to first partition , ending with 1 go to second partition and so on.. This way I want to create 10 partitions, employee id can be int or varchar which ever is easy and fast in making partition. Currently we have 10 separate tables employee_01, employee_02... (dont like this) Although the retrieval and insertion time will be enhanced by no means, but maintainability would be increased by huge factors, thanks Edit: How do I specify partitioning criteria based on last digit of employee I was wondering if

Partitioning AWS Kinesis Firehose data to s3 by payload [duplicate]

随声附和 提交于 2019-12-01 16:22:14
问题 This question already has answers here : Write parquet from AWS Kinesis firehose to AWS S3 (3 answers) Closed 2 years ago . I am using AWS-Kinesis-Firehose to injest data to S3, and consume it afterwards with Athena. I am trying to analyze events from different games, to avoid Athena explore much data I would like to partition the s3 data using an identifier for each game, so far I did not find a solution, as Firehose receives data from different games. Does anyone knows how to do it? Thank

Partition table, each partition on different disk on my HDD

半城伤御伤魂 提交于 2019-12-01 13:54:06
I have a table that I would like to partition in MYSQL 5.5. That I know how to do, but what I also need is to specify a disk for each of my partitions. For example, I would like to put: P01 in c:\ P02 in d:\ ....... and so on. I'm currently using this statement: (which doesn't fulfil my requirements, but works perfectly) ALTER TABLE transaction_transaction PARTITION BY RANGE (effectiveDate_)( PARTITION p01 VALUES Less Than (1288562400000), PARTITION p02 VALUES Less Than (1293660000000), PARTITION p03 VALUES Less Than (1298757600000), PARTITION p04 VALUES Less Than (1303855200000), PARTITION

Is there any way to manipulate the titles of a ctree plot?

假如想象 提交于 2019-12-01 11:42:28
Is there any way to change the title sizes of a ctree plot? Use the following variables to quickly set up a ctree plot a<-c(41, 45, 50, 50, 38, 42, 50, 43, 37, 22, 42, 48, 47, 48, 50, 47, 41, 50, 45, 45, 39, 45, 46, 48, 50, 47, 50, 21, 48, 50, 48, 48, 48, 46, 36, 38, 50, 39, 44, 44, 50, 49, 40, 48, 48, 45, 39, 40, 44, 39, 40, 44, 42, 39, 49, 50, 50, 48, 48, 47, 48, 47, 44, 41, 50, 47, 50, 41, 50, 44, 47, 50, 24, 40, 43, 37, 44, 32, 43, 42, 44, 38, 42, 45, 50, 47, 46, 43, 37, 47, 37, 45, 41, 50, 42, 32, 43, 48, 45, 45, 28, 44,38, 41, 45, 48, 48, 47 ,49, 16, 45, 50, 47, 50, 43, 49, 50) X1<-c(NA

Kafka streams: Read from ALL partitions in every instance of an application

荒凉一梦 提交于 2019-12-01 10:15:58
问题 When using KTable, Kafka streams doesn't allow instances to read from multiple partitions of a particular topic when the number of instances / consumers is equal to number of partitions. I tried achieving this using GlobalKTable, the problem with this is that data will be overwritten, also aggregation cannot be applied on it. Let's suppose I have a topic named "data_in" with 3 partitions (P1, P2, P3). When I run 3 instances (I1, I2, I3) of a Kafka streaming application, I want each instance

EXECUTE of SELECT … INTO is not implemented

老子叫甜甜 提交于 2019-12-01 05:11:26
I am trying to run this function in PostrgeSQL: CREATE OR REPLACE FUNCTION create_partition_and_insert() RETURNS trigger AS $BODY$ DECLARE partition VARCHAR(25); _date text; BEGIN EXECUTE 'SELECT REPLACE(' || quote_literal(NEW.date) || ',''-'',''_'') into _date'; partition := TG_RELNAME || '_' || _date || ‘p’; IF NOT EXISTS(SELECT relname FROM pg_class WHERE relname=partition) THEN RAISE NOTICE 'A partition has been created %',partition; EXECUTE 'CREATE TABLE ' || partition || ' (check (date = ''' || NEW.date || ''')) INHERITS (' || TG_RELNAME || ');'; END IF; EXECUTE 'INSERT INTO ' ||

Hive 1.1.0 Alter table partition type from int to string

浪子不回头ぞ 提交于 2019-12-01 04:43:12
I have a table which has a partition of type int but which I want to convert to string. However, I can't figure out how to do this. The table description is: Col1 timestamp Col2 string Col3 string Col4 string Part_col int # Partition information # col_name data_type comment Part_col int The partitions I have created are Part_col=0, Part_col=1, ..., Part_col=23 I want to change them to Part_col='0' etc I run this command in hive: set hive.exec.dynamic.partitions = true; Alter table tbl_name partition (Part_col=0) Part_col Part_col string; I have also tried using "partition (Part_col)" to change

Is it possible to partially refresh a materialized view in Oracle?

我只是一个虾纸丫 提交于 2019-12-01 03:06:30
I have a very complex Oracle view based on other materialized views, regular views as well as some tables (I can't "fast refresh" it). Most of the time, existing records in this view are based on a date and are "stable", with new record sets having new dates. Occasionally, I receive back-dates. I know what those are and how to deal with them if I were maintaining a table, but I would like to keep this a "view". A complete refresh would take around 30 minutes, but it only takes 25 seconds for any given date. Can I specify that only a portion of a materialized view should be updated (i.e. the

Hive 1.1.0 Alter table partition type from int to string

谁都会走 提交于 2019-12-01 02:22:05
问题 I have a table which has a partition of type int but which I want to convert to string. However, I can't figure out how to do this. The table description is: Col1 timestamp Col2 string Col3 string Col4 string Part_col int # Partition information # col_name data_type comment Part_col int The partitions I have created are Part_col=0, Part_col=1, ..., Part_col=23 I want to change them to Part_col='0' etc I run this command in hive: set hive.exec.dynamic.partitions = true; Alter table tbl_name

EXECUTE of SELECT … INTO is not implemented

血红的双手。 提交于 2019-12-01 02:09:18
问题 I am trying to run this function in PostrgeSQL: CREATE OR REPLACE FUNCTION create_partition_and_insert() RETURNS trigger AS $BODY$ DECLARE partition VARCHAR(25); _date text; BEGIN EXECUTE 'SELECT REPLACE(' || quote_literal(NEW.date) || ',''-'',''_'') into _date'; partition := TG_RELNAME || '_' || _date || ‘p’; IF NOT EXISTS(SELECT relname FROM pg_class WHERE relname=partition) THEN RAISE NOTICE 'A partition has been created %',partition; EXECUTE 'CREATE TABLE ' || partition || ' (check (date