overriding

I need a HashMap of Lists. Normally I do this: val lists = mutable.HashMap[String,List[Int]]() { override def default(key: String) = { val newList = List[Int]() this(key) = newList newList } } so that I can then simply write things like lists("dog") ::= 14 without having to worry about whether the "dog" List has been initialised yet. Is there a cleaner way to do this? I find myself typing out those five default override lines again and again. Thanks! Tomasz Nurkiewicz What about withDefaultValue() ? val lists = new mutable.HashMap[String,List[Int]].withDefaultValue(Nil) lists("dog") ::= 13

I am implementing the Map<V,K> and the Collection<V> interface in one class, but the remove(Object) method occurs in both interfaces, therfore eclipse shows me some errors. The return types are different, one returns boolean and the other V but that doesn't seem to matter. Is there some way of telling java/eclipse which method is actually being overridden? EDIT: I have got an interface that all values must implement, it supplies the value with a getKey() method, making it possible to write an add function for the map. But there seems to be no way to let this one class look as a map and a

Does a command exist, like \deprecated , but to mark overridden functions? Java has an annotation @override for functions you have overridden. I would like to do the same in C++, so that I can to see the superclass functions I've overridden. At best, the documentation page should also show all class member functions, which are inherited, but not explicitly overridden with hyper-links to the superclass functions. I know there is a way to copy the documentation from the superclass method. But I don't want to have the whole doc copied. I just want to know, that a function is inherited. The

Is it possible to over-ride methods that are part of Ruby itself, such as rb_error_frozen , that are written in C, with Ruby code? Background : I'm wondering if it's possible to make Ruby merely log a warning, rather than raise an exception, when a frozen object is modified. That way, I can log a variety of state modifications, rather than stopping when the first one occurs. I'm primarily thinking of doing this with YARV, but I could use another implementation if that made it easier. And yes, it's a whyday project! Don't try this in a production environment! I can only speak for MRI/YARV, but

Possible Duplicate: What's “@Override” there for in java? I've never put "@Override" before a method until now. I see some code examples with it, but I don't understand its utility. I'd love some explanation. Many thanks, JDelage First, you can't annotate a class with @Override . This annotation indicates that a method declaration is intended to override a method declaration in a superclass. You don't have to annotate overriding methods but if you use this annotation and your annotated method does not override a superclass method, then the compiler will generate an error message. Indicates

This is basically a copy from the example given in Item 21. Overriding Virtual Functions in Herb Sutter's book Exceptional C++ . #include <iostream> #include <complex> using namespace std; class Base { public: virtual void f(int); virtual void f(double); virtual ~Base() {}; }; void Base::f(int) { cout << "Base::f(int)" << endl; } void Base::f( double ) { cout << "Base::f(double)" << endl; } class Derived: public Base { public: void f(complex<double>); }; void Derived::f(complex<double>) { cout << "Derived::f(complex)" << endl; } int main() { Base* pb = new Derived; pb->f(1.0); delete pb; } The

function Ninja(){ this.swingSword = function(){ return true; }; } // Should return false, but will be overridden Ninja.prototype.swingSword = function(){ return false; }; var ninja = new Ninja(); log( ninja.swingSword(), "Calling the instance method, not the prototype method." ); now log showing me true. which means swingSword that were defined in Ninja.prototype has overridden so how can i override the constructor function or property.?? i know that preference is given to constructor variable then why need to define a function or property inside prototype?? Stephen Kaiser The reason to define

I know that main() can be overloaded in a class with the compiler always taking the one with String[] args as arguments as the main method from where the execution starts. But is it possible to declare the same main(String args[]) in an interface and implement it in different classes differently? For example, package test; interface test { public void main(String args[]); public void display(); } package test; class Testclass1 implements test { public void display() { System.out.println("hello"); } public static void main(String[] args) { test t; t.display(); } } package temp; import test.*;