overriding

Why does this work? Method overloading + method overriding + polymorphism

别说谁变了你拦得住时间么 提交于 2019-11-29 06:11:59
In the following code: public abstract class MyClass { public abstract bool MyMethod( Database database, AssetDetails asset, ref string errorMessage); } public sealed class MySubClass : MyClass { public override bool MyMethod( Database database, AssetDetails asset, ref string errorMessage) { return MyMethod(database, asset, ref errorMessage); } public bool MyMethod( Database database, AssetBase asset, ref string errorMessage) { // work is done here } } where AssetDetails is a subclass of AssetBase. Why does the first MyMethod call the second at runtime when passed an AssetDetails, rather than

C++ function overriding

為{幸葍}努か 提交于 2019-11-29 06:07:52
问题 I have three different base classes: class BaseA { public: virtual int foo() = 0; }; class BaseB { public: virtual int foo() { return 42; } }; class BaseC { public: int foo() { return 42; } }; I then derive from the base like this (substitute X for A, B or C): class Child : public BaseX { public: int foo() { return 42; } }; How is the function overridden in the three different base classes? Are my three following assumptions correct? Are there any other caveats? With BaseA, the child class

Override Django Object Serializer to get rid of specified model

邮差的信 提交于 2019-11-29 05:11:07
I need to convert a Django Queryset Object into a Json string. The built in Django Serialization library works great. Although it specifies the name of the Model from where it was created. Since I don't need this, how do I get rid of it? What else do I need to override to be able to use the overridden end_object method below? class Serializer(PythonSerializer): def end_object(self, obj): self.objects.append({ "model" : smart_unicode(obj._meta), # <-- I want to remove this "pk" : smart_unicode(obj._get_pk_val(), strings_only=True), "fields" : fields }) self._current = None Sorry I had totally

Requiring virtual function overrides to use override keyword

混江龙づ霸主 提交于 2019-11-29 04:38:58
问题 C++11 added override to ensure that member functions you write that you intend to override base-class virtual functions actually do (or won't compile). But in a large object hierarchy, sometimes you could accidentally end up writing a member function that overrides a base-class virtual when you didn't intend it! For instance: struct A { virtual void foo() { } // because obviously every class has foo(). }; struct B : A { ... }; class C : B { private: void foo() { // was intended to be a

Why isn't my new operator called

你。 提交于 2019-11-29 04:19:49
I wanted to see that a dynamically loaded library (loaded with dlopen etc.) really uses its own new an delete operators and not these ones defined in the calling program. So I wrote the following library.cpp #include <exception> #include <new> #include <cstdlib> #include <cstdio> #include "base.hpp" void* operator new(size_t size) { std::printf("New of library called\n"); void *p=std::malloc(size); if (p == 0) // did malloc succeed? throw std::bad_alloc(); // ANSI/ISO compliant behavior return p; } void operator delete(void* p) { std::printf("Delete of library called\n"); std::free(p); } class

Java - inline class definition

六月ゝ 毕业季﹏ 提交于 2019-11-29 04:02:26
I've seen a couple of examples similar to this in Java, and am hoping someone can explain what is happening. It seems like a new class can be defined inline, which seems really weird to me. The first printout line is expected, since it is simply the toString. However the 2nd seems like the function can be overriden inline. Is there a technical term for this? Or any documentation which goes into more depth? Thanks! If I have the following code: public class Apple { public String toString() { return "original apple"; } } public class Driver { public static void main(String[] args) { System.out

Overriding interface's variable?

我们两清 提交于 2019-11-29 03:59:14
As I read from various Java book and tutorials, variables declared in a interface are constants and can't be overridden. I made a simple code to test it interface A_INTERFACE { int var=100; } class A_CLASS implements A_INTERFACE { int var=99; //test void printx() { System.out.println("var = " + var); } } class hello { public static void main(String[] args) { new A_CLASS().printx(); } } and it prints out var = 99 Is var get overridden? I am totally confused. Thank you for any suggestions! Thank you very much everyone! I am pretty new to this interface thing. "Shadow" is the key word to

how can I override jquery's .serialize to include unchecked checkboxes

天大地大妈咪最大 提交于 2019-11-29 03:49:01
I have read quite a few different methods of having html checkboxes get posted to the server, but I am really looking to do it without modifying anything except for $.serialize. I ideally, I would like checked boxes to be posted as on, and unchecked to be posted as 0, empty, or null. I'm a little confused by jquery's inner-workings, but I've got this so far, but it sets unchecked checkboxes to 'on'... Can anyone tell me how to continue this modification below? $.fn.extend({ serializeArray: function() { return this.map(function(){ return this.elements ? jQuery.makeArray( this.elements ) : this;

Java cloning abstract objects

|▌冷眼眸甩不掉的悲伤 提交于 2019-11-29 03:47:55
I'm wondering if there is any way to do the following. I have an abstract class, Shape , and all its different subclasses and I want to override the clone method. All I want to do in the method is create a new Shape from the toString() of the current one. Obviously I can't do the following because Shape is abstract. Is there another way to do this because overriding clone in every subclass just for a simple name change seems useless. public abstract class Shape { public Shape(String str) { // Create object from string representation } public Shape clone() { // Need new way to do this return

Implementing Comparable, compareTo name clash: “have the same erasure, yet neither overrides the other”

痴心易碎 提交于 2019-11-29 03:38:18
I'd like to have a compareTo method that takes a Real (a class for working with arbitrarily large and precise real numbers [well, as long as it's less than 2^31 in length at the moment]) and a compareTo method that takes an Object, but Java isn't letting me and I'm not experienced enough to know why. I just tried to modify the class to implement Comparable and I got these error messages below. I don't really understand what the error messages mean but I know it's got something to do with the horrible way I'm trying to give the class some flexibility with all the different method signatures for