overriding

override existing onkeydown function

情到浓时终转凉″ 提交于 2019-11-29 15:28:12
My extensions go through every input entered on an on any website that is loaded. What I do is I consider every onkeydown and manipulate it if it has some value. my background js file contains the following: document.onkeydown = returnKey; function returnKey(evt) { var evt = (evt) ? evt : ((event) ? event : null); var node = (evt.target) ? evt.target : ((evt.srcElement) ? evt.srcElement : null); if ( node.value == 'fi' ) { evt.srcElement.value = "??"; } } My problem is when I have websites that already contains onkeydown function in their innerHTML webpage. for instance: taken from facebook's

Strange case of static method override in java

為{幸葍}努か 提交于 2019-11-29 15:20:21
It is written everywhere that static method cannot be overriden, but when I try to reduce the access specifier say from public to protected it gives an error. for example public class StaticOverrideFunda { public static void foo(){ System.out.println("Parent Foo"); } } public class B extends StaticOverrideFunda{ protected static void foo(){ System.out.println("Child Foo"); } /** * @param args */ public static void main(String[] args) { // TODO Auto-generated method stub B.foo(); } } It says Cannot reduce the visibility of the inherited method So insense it is following the overriding rules,

OverRiding Vs PolyMorphism

蹲街弑〆低调 提交于 2019-11-29 14:55:02
问题 What is the difference between the two? A super class having myMethod(int a) and an inheriting class having the same method, Is this overriding or polymorphism? I am clear with the difference b/w overriding and overloading, but the polymorphism and overriding seems the same. Or are they? 回答1: Overriding is when you call a method on an object and the method in the subclass with the same signature as the one in the superclass is called. Polymorphism is where you are not sure of the objects type

Interface and Abstract class ad method overriding

不打扰是莪最后的温柔 提交于 2019-11-29 14:53:25
Here is the code: interface hi { public void meth1(); } abstract class Hullo { public abstract void meth1(); } public class Hello extends Hullo implements hi { public void meth1(){} } Question:The code compiles and everything. I wanted to know the meth1() in class Hello is overriding which meth1()? The ont in the interface or the one in the abstract class and why? The answer is short: Both..... In fact, to be correct: You are overriding none of them, you are implementing them both, with one method. Generally we override a existing method which already has some definition. I mean we are adding

Overriding and return type compatibility

半世苍凉 提交于 2019-11-29 14:43:17
The following compiles without any problem boolean flag = true; Boolean flagObj = flag; Now imaging the following scenario interface ITest{ Boolean getStatus(); } class TestImpl implements ITest{ public boolean getStatus(){ // Compile error: return type is incompatible return true; } } My question is about the compile error at the mentioned line. My Interface mentions return type as Boolean but the implemented method returns boolean ( the literal ) My question is, if Boolean and boolean are compatible then why the compiler is complaining ? Doesn't the autoboxing apply here ? You can only

How does equals() method work in Java [duplicate]

笑着哭i 提交于 2019-11-29 14:41:16
This question already has an answer here: What is the difference between == and equals() in Java? 23 answers The equals method compares whether two object values are equal or not. My question is how it compares the two objects? How can it tell the two objects are equal or not? I want to know based on what it compares the two objects. I am not including the hashCode method. The default implementation, the one of the class java.lang.Object , simply tests the references are to the same object : 150 public boolean equals(Object obj) { 151 return (this == obj); 152 } The reference equality operator

Method overriding in Java throwing exceptions

大城市里の小女人 提交于 2019-11-29 14:37:51
I am trying to understand Object Casting and Method Overriding. I have a piece of code: public class ExceptionClass{ void m() throws SQLException{} } class A extends ExceptionClass{ void m() throws Exception{} } This gives an error "Exception Exception is not compatible with throws clause in ExceptionClass.m()". The same if I write as : public class ExceptionClass{ void m() throws SQLException{} } class A extends ExceptionClass{ void m() throws RuntimeException{} } This doesnt give any error and method is also overridden properly. After some analysis I thought that may be, since SQLException

How override model in Magento correctly?

二次信任 提交于 2019-11-29 14:28:24
guys. I need to override 2 functions in different classes (CatalogSearch/Layer.php and CatalogSearch/Mysql4/Fulltext/Collection.php). So, I have a config file: <config> <modules> <my_modulename> <version>0.1</version> </my_modulename> </modules> <global> <models> <catalogsearch> <rewrite> <layer>My_Modulename_Model_CatalogSearch_Layer</layer> <mysql4_fulltext_collection>My_Modulename_Model_CatalogSearch_Mysql4_Fulltext_Collection </mysql4_fulltext_collection> </rewrite> </catalogsearch> </models> </global> </config> Hence, Layer.php has been overridden correctly , but Collection.php hasn't - '

Resolving property and function “overrides” in QML

好久不见. 提交于 2019-11-29 14:25:01
It seems like although QML supports "overriding" of properties and functions, the support is somewhat clunky. Here is an example snippet: // T1.qml QtObject { property int p: 1 function f() { return 1 } } // T2.qml T1 { property string p: "blah" function f() { return "blah" } } // usage T1 { Component.onCompleted: { var obj = this for (var k in obj) console.log(k + " " + typeof obj[k] + " " + obj[k]) } } T2 { Component.onCompleted: { var obj = this for (var k in obj) console.log(k + " " + typeof obj[k] + " " + obj[k]) } } The behavior of overrides is consistent - no matter how many times a

Override of toString() that makes use of the overridden toString()

不羁的心 提交于 2019-11-29 14:12:52
Basically this is what I am trying to achieve. classname@address(?)[original toString() ], object's name, object's age @Override public String toString() { return String.format("%s , %s , %d", this.toString(), this.getName(),this.getAge()); } Problem, toString() gets called recursively. I can't call super.toString() because that's not what I want. I want ' this ' to call the original toString() . This this.super.toString() doesn't work for obvious reasons. I'm running out of steam, can this be done once a method gets overridden? I.e. call the original implementation ? (my edit) Basically what