overriding

I've looked for overriding guidelines for structs, but all I can find is for classes. At first I thought I wouldn't have to check to see if the passed object was null, as structs are value types and can't be null. But now that I come to think of it, as equals signature is public bool Equals(object obj) it seems there is nothing preventing the user of my struct to be trying to compare it with an arbitrary reference type. My second point concerns the casting I (think I) have to make before I compare my private fields in my struct. How am I supposed to cast the object to my struct's type? C#'s as

When creating own Activity subclass, we are overriding some of the basic Activity lifecycle functions. In which of these we must call super implementation, where we should and where is it only good manner ? // base lifecycle onCreate(Bundle savedInstanceState); onStart(); onRestart(); onResume(); onPause(); onStop(); onDestroy(); finalize(); onUserLeaveHint(); // instance state onSaveInstanceState(Bundle outState); onRestoreInstanceState(Bundle savedInstanceState) // others onCreateContextMenu(ContextMenu menu, View v, ContextMenuInfo menuInfo); onCreateOptionsMenu(Menu menu);

I wrote this little code in a custom service in AngularJS. In my service: var deferred = $q.defer(); var promise = deferred.promise; deferred.resolve('success'); deferred.reject('error'); /* Handle success and error */ promise.success = function(fn) { promise.then(function(response) { fn(response); }); return promise; }; promise.error = function(fn) { promise.then(null, function(response) { fn(response); }); return promise; }; In my controller: promiseService.myPromise() .success(function(data){ $scope.success= data; }) .error(function(data){ $scope.error = data; }); I juste Handle the Success

Consider the following interface in Java: public interface I { public final String KEY = "a"; } And the following class: public class A implements I { public String KEY = "b"; public String getKey() { return KEY; } } Why is it possible for class A to come along and override interface I's final constant? Try for yourself: A a = new A(); String s = a.getKey(); // returns "b"!!! André Despite the fact that you are shadowing the variable it's quite interesting to know that you can change final fields in java as you can read here : Java 5 - "final" is not final anymore Narve Saetre from Machina

I am attempting to override the << operator for a class. The purpose is basically to implement a toString() like behavior for my class, so that sending it to cout will produce useful output. Using a dummy example, I have the code below. When I attempt to compile, I get the foollowing error: $ g++ main.cpp Rectangle.cpp /tmp/ccWs2n6V.o: In function `operator<<(std::basic_ostream<char, std::char_traits<char> >&, CRectangle const&)': Rectangle.cpp:(.text+0x0): multiple definition of `operator<<(std::basic_ostream<char, std::char_traits<char> >&, CRectangle const&)' /tmp/ccLU2LLE.o:main.cpp:(.text