overloading

I want to understand the code from this answer type Mult = Mult with static member inline ($) (Mult, v1: 'a list) = fun (v2: 'b list) -> v1 |> List.collect (fun x -> v2 |> List.map (fun y -> (x, y))) : list<'a * 'b> static member inline ($) (Mult, v1:'a ) = fun (v2:'a) -> v1 * v2 :'a let inline (*) v1 v2 = (Mult $ v1) v2 F# can resolve overloaded members. (Because it doesn't support currying of members). So, I supposed, it should work for methods as well But it doesn't: type Mult = Mult with static member inline Do (Mult, v1: 'a list) = fun (v2: 'b list) -> v1 |> List.collect (fun x -> v2 |>

If I attempt to overload the method flexiPrint() in a class Varargdemo then it generates a compile time error. The compiler treats the following signatures the same: public static void flexiPrint(Object... data){} public static void flexiPrint(Object[] data){} Can someone explain to me why they are treated the same? I haven't been able to find the answer. Object... is nothing but it is an array, that means same as defining Object[] ... (three dots) represents varargs in java. We usually see this signature in main method like main(String... args) So, having more than one method with same

I'm receiving a double definition error on the following two methods: def apply[T](state: T, onRender: T => Graphic, onMouseEvent: (MouseEvent, T) => T): GraphicPanel = apply(state, onRender, onMouseEvent = Some(onMouseEvent)) and def apply[T](state: T, onRender: T => Graphic, onKeyEvent: (KeyEvent, T) => T): GraphicPanel = apply(state, onRender, onKeyEvent = Some(onKeyEvent)) which are both method overloads for the more general apply method with the signature: def apply[T](state: T, onRender: T => Graphic, onTickEvent: Option[T => T] = None, fps: Int = 30, onMouseEvent: Option[(MouseEvent, T)

In Haskell, how can one overload a built in function such as !! ? I originally was trying to figure out how to overload the built in function !! to support by own data types. Specifically, !! is of the type: [a] -> Int -> a and I want to preserve it's existing functionality, but also be able to call it where its type signature looks more like MyType1 -> MyType2 -> MyType3 I originally wanted to do this because MyType1 is like a list, and I wanted to use the !! operator because my operation is very similar to selecting an item from a list. If I was overloading something like + I could just add

I'm writing a C# programlet to crawl a directory and give me a listing of files whose date in the last CSV line is less than the current date. Since this is a programlet, I'm not really spending too much time making the code very clean or anything -- but that's all a matter of opinion, I suppose. The curious thing is the following set of code snippets. Three static methods all in the same class. public static DateTime dateStringConverter(string mmddyyyy, char delim='/') { string[] date = mmddyyyy.Split(delim); DateTime fileTime = new DateTime(Convert.ToInt32(date[2]), Convert.ToInt32(date[0]),

This question already has an answer here: Variable number of arguments in C++? 16 answers Can I overload my function to do something with a lot of arguments as in JavaScript . For example: function f() { alert(arguments[0]); } f(4); // will alert 4 Can I do the same thing in C++ ? You can use variadic template arguments and tuples: #include <tuple> #include <iostream> template <class... Args> void f(Args&&... args) { auto arguments = std::make_tuple(std::forward<Args>(args)...); std::cout << std::get<0>(arguments); } void f() {} // for 0 arguments int main() { f(2, 4, 6, 8); } Live Demo For