overloading

Does Java virtual machine allow overloading on return type?

由 痞子三分冷 提交于 2019-12-02 05:48:41
问题 I have gone through this presentation. Slide No:26 quote that Java language does not allow overloading on return type Java Virtual machine does allow overloading on return type Are these statements true? If both statements are true, how to make the code compilable so that jvm run the code? I have one SE question on this topic : Java - why no return type based method overloading? Thanks in advance. 回答1: These statements are perfectly true. Remember that Java is two things - one,a language and

How do I verify the number of invocations of overloaded method using Mockito?

由 ╄→гoц情女王★ 提交于 2019-12-02 05:30:25
How do I check if bar(Alpha, Baz) called bar(Xray, Baz) using Mockito - without actually calling the later, given my MCVE class Foo : public class Foo { public String bar(Xray xray, Baz baz) { return "Xray"; } public String bar(Zulu zulu, Baz baz) { return "Zulu"; } public String bar(Alpha alpha, Baz baz) { if(alpha.get() instanceof Xray) { return bar((Xray)alpha.get(), baz); } else if(alpha.get() instanceof Zulu) { return bar((Zulu)alpha.get(), baz); } else { return null; } } } Currently, I have roughly the following Mockito-enhanced JUnit test: @Test public void testBar_callsBarWithXray() {

Why can't a class method call a global function with the same name?

由 ◇◆丶佛笑我妖孽 提交于 2019-12-02 05:24:49
问题 The following code shows a function call another function. Both have the same name, but different signatures. This works as expected. //declarations void foo(); void foo(int); int main(){ foo(); } //definitions void foo(){ foo(1); } void foo(int){} The only difference I will make now, is wrap one of the functions into a structure: //declarations struct Bar{ void foo(); }; void foo(int); int main(){ Bar bar; bar.foo(); } //definitions void Bar::foo(){ foo(1); } void foo(int){} This fails to

Elaboration: Method overloading is a static/compile-time binding but not polymorphism. Is it correct to correlate static binding with polymorphism?

由 早过忘川 提交于 2019-12-02 04:55:27
Before I ask my question, let me to explain my understanding and opinion. By only Overriding we can't achieve polymorphism unless there is upcasting. And as it can only seen at runtime people might have named it as Run time ploymorphism. ( I have no objection to call polymorphism as Run Time Polymorphism ) I have objection to call method overloading as compile time polymorphism or polymorphism . I agree that method overloading is static binding (compile time binding), but I can't see polymorphism in that. According to the javadoc, there is only polymorphism . There is no compile time or run

how to overload operator == outside template class using friend function?

由 妖精的绣舞 提交于 2019-12-02 04:27:17
问题 I'm trying to write a template class which overloads operator== . I know how to get it inside the class: template <typename T> class Point { private: T x; public: Point(T X) : x(X) {} bool operator== (Point &cP) { return (cP.x == x); } }; But now I want to achieve this outside the template class. I've read this post: error when trying to overload << operator and using friend function and add template declaration in my code: template <typename> class Point; template <typename T> bool operator=

C++ globally overloaded operator= [duplicate]

由 生来就可爱ヽ(ⅴ＜●) 提交于 2019-12-02 04:06:34
问题 This question already has answers here : Closed 8 years ago . Possible Duplicate: What does “operator = must be a non-static member” mean? (C++) Hi, I have the following code... // Header file struct dataRecord{ size_t id; char name[gcNameLength]; }; void operator=(dataRecord &adr, const dataRecord &bdr); How ever gcc gives me the following error when compiling. error: ‘void operator=(dataRecord&, const dataRecord&)’ must be a nonstatic member function Thanks for the help. 回答1: You need to

Overloading method of comparison for custom class

由 …衆ロ難τιáo~ 提交于 2019-12-02 03:34:13
I want to overload methods of comparison for a personnal class. For example if I write this : $object1 < $object2 Php will use this function : function compare($a, $b){ if($a->attribute == $b->attribute){return 0;} else{return $a->attribute > $b->attribute ? 1 : -1;} } Is there a way to do this ? I already seen this and this but I can't use these solutions The PECL solution you point to above is your only option. PHP does not provide operator overloading as available in other languages. 来源： https://stackoverflow.com/questions/10600460/overloading-method-of-comparison-for-custom-class

Why can't a class method call a global function with the same name?

由 耗尽温柔 提交于 2019-12-02 02:42:35
The following code shows a function call another function. Both have the same name, but different signatures. This works as expected. //declarations void foo(); void foo(int); int main(){ foo(); } //definitions void foo(){ foo(1); } void foo(int){} The only difference I will make now, is wrap one of the functions into a structure: //declarations struct Bar{ void foo(); }; void foo(int); int main(){ Bar bar; bar.foo(); } //definitions void Bar::foo(){ foo(1); } void foo(int){} This fails to compile. In member function ‘void Bar::foo()’: error: no matching function for call to ‘Bar::foo(int)’

Overload built in function in Haskell

由 半城伤御伤魂 提交于 2019-12-02 01:31:58
问题 In Haskell, how can one overload a built in function such as !! ? I originally was trying to figure out how to overload the built in function !! to support by own data types. Specifically, !! is of the type: [a] -> Int -> a and I want to preserve it's existing functionality, but also be able to call it where its type signature looks more like MyType1 -> MyType2 -> MyType3 I originally wanted to do this because MyType1 is like a list, and I wanted to use the !! operator because my operation is

Operator overloading, operator+ vs operator+=

由 ◇◆丶佛笑我妖孽 提交于 2019-12-02 00:03:56
问题 I was reading through some c++ source code, and i came over some syntax. path& path::operator+=(string postPath) and i was wondering whether it is actual syntax and why c++ is not using the already existing operator+ instead combined with applying the value to the object in question. Is it like, if you want to make sure that the object gets deleted properly. But the destructor should deal with all of that. -Edit1 I know there is a difference between a += b; and a + b; What i was wondering was
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