overloading

Elaboration: Method overloading is a static/compile-time binding but not polymorphism. Is it correct to correlate static binding with polymorphism?

元气小坏坏 提交于 2019-12-02 11:58:16
问题 Before I ask my question, let me to explain my understanding and opinion. By only Overriding we can't achieve polymorphism unless there is upcasting. And as it can only seen at runtime people might have named it as Run time ploymorphism. ( I have no objection to call polymorphism as Run Time Polymorphism ) I have objection to call method overloading as compile time polymorphism or polymorphism . I agree that method overloading is static binding (compile time binding), but I can't see

Why is not overloaded function for derived class object invoked when given a pointer to base class in C++?

不羁岁月 提交于 2019-12-02 11:42:37
In the following code #include <iostream> using namespace std; class A { public: A() {} virtual ~A() {}; }; class B : public A { public: B() {} virtual ~B() {}; }; void process(const A&) { cout << "processing A" << endl; } void process(const B&) { cout << "processing B" << endl; } int main(void) { A* a = new B; process(*a); return 0; } the output of running it becomes processing A but I would have assumed that it should have been processing B since a points to the derived class B and not A . So why does it call the first implementation of process function and not the second? The static type of

concept of overloading in C++

烂漫一生 提交于 2019-12-02 11:22:05
case 1: you can overload two functions namely: void foo(int *); void foo(const int *); while in , case 2: you can not overload two functions: void foo(int); void foo(const int); I have coded and checked this concept and yet unable to find out the reason to this variation in overloading. From Standard §13.1 Parameter declarations that differ only in the presence or absence of const and/or volatile are equivalent . That is, the const and volatile type-specifiers for each parameter type are ignored when determining which function is being declared, defined, or called. [ Example: typedef const int

template function name in terms of template argument

生来就可爱ヽ(ⅴ<●) 提交于 2019-12-02 09:31:25
问题 I've been looking for examples that relate to what my question is about and I still cannot find a solution. The closest thing I've found is Template function as a template argument I will try to post a working example in case it is needed but so far part of my code involves the following: template<class InterfaceType, class T> inline void write_info(InterfaceType& interface, T& t) { InterfaceType::write_info(interface, t); } template<class InterfaceType, class T> inline void write_data

Overloading assignment operator for pointers to two different classes

荒凉一梦 提交于 2019-12-02 09:19:40
My Question: I'm trying to overload the assignment operator for pointers to two different classes. Here is an example: dc.h: #ifndef DC_H_ #define DC_H_ #include "ic.h" class dc { double d; char c; public: dc(): d(0), c(0) { } dc(double d_, char c_): d(d_), c(c_) { } dc* operator=(const ic* rhs); ~dc() { } }; #endif /* DC_H_ */ class ic.h: #ifndef IC_H_ #define IC_H_ class ic { int i; char c; public: ic(): i(0), c(0) { } ic(int i_, char c_): i(i_), c(c_) { } ~ic() { } }; #endif /* IC_H_ */ dc.cpp: #include "dc.h" dc* dc::operator=(const ic* rhs) { d = rhs->i; c = rhs->c; return this; } ic.cpp:

Overloading + operator for arrays in groovy

孤街醉人 提交于 2019-12-02 08:37:44
I am a groovy newbie. Maybe this is a piece of cake, but I want to overload the + operator for arrays/lists to code like this def a= [1,1,1] def b= [2,2,2] assert [3,3,3] == a + b I wouldn't recommend globally overriding well-established behaviors. But, if you insist, this will do as you ask: ArrayList.metaClass.plus << {Collection b -> [delegate, b].transpose().collect{x, y -> x+y} } A more localized alternative would be to use a category: class PlusCategory{ public static Collection plus(Collection a, Collection b){ [a, b].transpose().collect{x, y -> x+y} } } use (PlusCategory){ assert [3, 3

The type of the expression must be an array type but it resolved to float

烂漫一生 提交于 2019-12-02 08:33:22
I hit a bump when I'm doing my Java code. I feel like I somehow got the concept messed up, like I not sure for this: void setScore(float[] sco) { sco = score; } public void setScore(float sco, int id) { sco[id] = score; } The error message corresponds to "sco[ID] = score; " The type of the expression must be an array type but it resolved to float I'm confused what I should put in the bracket, the book asks me to put "float[] score" instead of "float[] sco", but it doesn't work, so I edited a bit after several trials. This part of coding generally describes the method of overloading that stores

Java cast to superclass and call overload method

荒凉一梦 提交于 2019-12-02 08:16:23
问题 abstract class A { int met(A a) { return 0; } int met(B b) { return 1; } int met(C c) { return 2; } } class B extends A { int met(A a) { return 3; } int met(B b) { return 4; } int met(C c) { return 5; } } class C extends B { int f() { return ((A)this).met((A)this); } } public class teste { public static void main(String args[]) { C x = new C(); System.out.println(x.f()); } } The program will return 3 and I was expecting 0. Why does the first cast in the method f do nothing and the second one

Java cast to superclass and call overload method

南笙酒味 提交于 2019-12-02 08:04:41
abstract class A { int met(A a) { return 0; } int met(B b) { return 1; } int met(C c) { return 2; } } class B extends A { int met(A a) { return 3; } int met(B b) { return 4; } int met(C c) { return 5; } } class C extends B { int f() { return ((A)this).met((A)this); } } public class teste { public static void main(String args[]) { C x = new C(); System.out.println(x.f()); } } The program will return 3 and I was expecting 0. Why does the first cast in the method f do nothing and the second one works? Is it because in the A and B classes the met methods are overloaded and therefore static binding

A problem with generic method overloading

て烟熏妆下的殇ゞ 提交于 2019-12-02 06:32:33
问题 I have the following methods: void s<t>(int a, t b) { ... .. . } void s<int>(int a, int b) { ... .. . } void s<long>(int a, long b) { ... .. . } when I want to use it as s<long>(10,10) I see these overrides in tooltip. s<long>(int a,int b); and s<long>(int a,long b); . But, I think i must see just s<long>(int a,long b); . What's wrong ? I have visual studio 2008 sp1 . Thanks Update : I have test it in Visual Studio 2010.The result is the same. Update : It seems it is about c# not visual