overloading

I've been reading about overloading true and false in C#, and I think I understand the basic difference between this and defining a bool operator. The example I see around is something like: public static bool operator true(Foo foo) { return (foo.PropA > 0); } public static bool operator false(Foo foo) { return (foo.PropA <= 0); } To me, this is the same as saying: public static implicit operator bool(Foo foo) { return (foo.PropA > 0); } The difference, as far as I can tell, is that by defining true and false separately, you can have an object that is both true and false, or neither true nor

In C# you can do this: foo = string.Format("{0} {1} {2} {3} ...", "aa", "bb", "cc" ...); This method Format() accepts infinite parameters, being the first one how the string should be formatted and the rest are values to be put in the string. Today I've come to a situation where I had to get a set of strings and test them, then I remembered this language functionality, but I had no clue. After a few unsuccessful web searches, I've realised it would be more prudent to just get an array, which didn't make me quite satisfied. Q: How do I make a function that accepts infinite parameters? And how

I've got a small program: #include<iostream> using namespace std; void f(int) { cout << "int\n"; } void f(short) { cout << "short\n"; } int main(void){ char c = 0; f(c); return 0; } It prints int . I felt that, if this is because of "Integer promotion", why is not short preferred? I also know that integer promotion happens in an expression (like A=B). But I don't have expression in call to f(), right? If this is related to overload resolution rule, why passing char to f will result into compilers preferring int to short ? If I delete f(int) , then f(c) will call f(short) ! So in summary, my

In C++17, it is trivial to implement an overload(fs...) function that, given any number of arguments fs... satisfying FunctionObject , returns a new function object that behaves like an overload of fs... . Example: template <typename... Ts> struct overloader : Ts... { template <typename... TArgs> overloader(TArgs&&... xs) : Ts{forward<TArgs>(xs)}... { } using Ts::operator()...; }; template <typename... Ts> auto overload(Ts&&... xs) { return overloader<decay_t<Ts>...>{forward<Ts>(xs)...}; } int main() { auto o = overload([](char){ cout << "CHAR"; }, [](int) { cout << "INT"; }); o('a'); //

How to declare few methods with the same name ,but with different numbers of parameters or different types in one class? What I must to change in this class: class MyClass: """""" #---------------------------------------------------------------------- def __init__(self): """Constructor""" def my_method(self,parameter_A_that_Must_Be_String): print parameter_A_that_Must_Be_String def my_method(self,parameter_A_that_Must_Be_String,parameter_B_that_Must_Be_String): print parameter_A_that_Must_Be_String print parameter_B_that_Must_Be_String def my_method(self,parameter_A_that_Must_Be_String

I have a basic inheritance situation with an overloaded method in the super class. public class Person { private String name; private int dob; private String gender; public Person(String theName, int birth, String sex){ name = theName; dob = birth; gender = sex; } public void work(){ getWorkDetail(this); } public void getWorkDetail(Employee e){ System.out.println("This person is an Employee"); } public void getWorkDetail(Person p){ System.out.println("This person is not an Employee"); } } The following Employee class extends the Person class above: public class Employee extends Person { String

I'm new with Java and I'm having trouble understanding the constructor issue, I have looked at many tutorials and still I'm having difficult to understand why we use constructors, anyway, my specific question is : Correct me if I'm wrong, if i want to add in my class more than one constructor, I'll write the first one and the second will be int type (inside the brackets). is it because the constructors have to be with the same name as the class and we need to distinguish between them ? what if I want to add a third constructor ? Can it also be int type ? a) is it because the constructors have

I can surely answer to this question by myself writing a dummy test but I want to know what people think about the question. Here it is: Which method will be call when we have both at the same time overloading and overriding? I am only considering Type overloading and not arity overloading and when Type the overload are related. Let me throw you an example: class AA {} class BB : AA {} class A { public virtual void methodA(AA anAA) { Console.Write("A:methodA(AA) called"); } public virtual void methodA(BB aBB) { Console.Write("A:methodA(BB) called"); } } class B : A { public override void